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a) \(\frac{x-3}{3}-1=\frac{x}{-4}\)
\(\Leftrightarrow\frac{x-3}{3}-\frac{3}{3}=\frac{x}{-4}\)
\(\Leftrightarrow\frac{x-6}{3}=\frac{x}{-4}\)
\(\Leftrightarrow-4\left(x-6\right)=3x\)
\(\Leftrightarrow-4x+24=3x\)
\(\Leftrightarrow24=3x+4x\)
\(\Leftrightarrow7x=24\)
\(\Leftrightarrow x=\frac{24}{7}\)
b) \(\frac{5}{8}-\left(x-\frac{1}{2}\right)=\frac{-3}{4}\)
\(\Leftrightarrow\frac{5}{8}-x+\frac{1}{2}=\frac{-3}{4}\)
\(\Leftrightarrow\frac{5}{8}+\frac{4}{8}-x=\frac{-3}{4}\)
\(\Leftrightarrow\frac{9}{8}-x=\frac{-3}{4}\)
\(\Leftrightarrow x=\frac{9}{8}+\frac{3}{4}\)
\(\Leftrightarrow x=\frac{15}{8}\)
a) \(\frac{9}{20}\) c) \(\frac{-55}{4}\)
b) \(\frac{116}{75}\) d) \(\frac{-76}{45}\)
đúng hết đấy nhé mình tính kĩ lắm ko sai đâu
chúc may mắn
X : \(3\frac{1}{15}\)=\(1\frac{1}{2}\)
X : \(\frac{46}{15}\)=\(\frac{3}{2}\)
X = \(\frac{3}{2}\)X \(\frac{46}{15}\)
X = \(\frac{23}{5}\)
#)Giải :
\(x\div3\frac{1}{5}=1\frac{1}{2}\)
\(\Leftrightarrow x\div\frac{16}{5}=\frac{3}{2}\)
\(\Leftrightarrow x=\frac{24}{5}\)hay \(4\frac{4}{5}\)
\(\frac{2}{3}x-\frac{1}{2}x=\frac{5}{12}\)
\(\Leftrightarrow\left(\frac{2}{3}-\frac{1}{2}\right)x=\frac{5}{12}\)
\(\Leftrightarrow\frac{1}{6}x=\frac{5}{12}\)
\(\Leftrightarrow x=\frac{5}{2}\)
a) \(1\frac{5}{8}:x-1\frac{1}{4}=2\)
=> \(\frac{13}{8}:x-\frac{5}{4}=2\)
=> \(\frac{13}{8}:x=\frac{13}{4}\)
=> \(x=\frac{13}{8}:\frac{13}{4}=\frac{13}{8}\cdot\frac{4}{13}=\frac{1}{2}\)
b) \(\left(x-\frac{1}{3}\right)^2-\frac{1}{2}=0\)
=> \(\left(x-\frac{1}{3}\right)^2=\frac{1}{2}\)
=> x không thỏa mãn
c) 2(x - 1) = 3x + 1
=> 2x - 2 = 3x + 1
=> 2x - 2 - 3x - 1 = 0
=> 2x - 3x - 2 - 1 = 0
=> -x = 3
=> x = -3
d) \(\frac{-2}{x}=\frac{x}{-8}\)=> x2 = 16 => x = \(\pm\)4
e) |7 - x| + 2x = 11
=> |7 - x| = 11 - 2x
=> 7 - x = 11 - 2x
=> 7 - x - 11 + 2x = 0
=> 7 - 11 - x + 2x = 0
=> -4 + x = 0
=> -4 = -x
=> x = 4
a)=> 13/8 : x-5/4 =2
<=> 13/8 : x= 13/4
<=> x=1/2
b)=>x2 - (1/3)2 = 1/2
=>x2-1/9=1/2
=>x2=11/18
=>x=0.78 (bằng xấp xỉ thôi nhé bạn :33)
c)=>2x-2=3x-1
=>2x-3x=2-1
=>-x=1
=>x=-1
còn 2 câu bạn làm nốt nhé :33
k đúng cho mk nhé!!!!
\(a.-1,52+\frac{2}{47}-x=3.\)
\(\Leftrightarrow\frac{2}{47}-x=4,52\)
\(\Leftrightarrow x=\frac{2}{47}-4,52\)
\(\Leftrightarrow x=-\frac{5261}{1175}\)
\(b.x+3,5-\frac{4}{7}=\frac{3}{2}-1\frac{3}{5}\)
\(\Leftrightarrow x=\frac{3}{2}-\frac{8}{5}-\frac{7}{2}+\frac{4}{7}\)
\(\Leftrightarrow x=-\frac{106}{35}\)
\(c.\left(x:2\frac{1}{8}\right).\frac{1}{6}=-\frac{3}{8}.\left(\frac{1}{2}-1\frac{3}{5}\right)\)
\(\Leftrightarrow\left(x:\frac{17}{8}\right).\frac{1}{6}=-\frac{3}{16}+\frac{3}{5}\)
\(\Leftrightarrow\left(x:\frac{17}{8}\right).\frac{1}{6}=\frac{33}{80}\)
\(\Leftrightarrow x:\frac{17}{8}=\frac{99}{40}\)
\(\Leftrightarrow x=\frac{99}{40}.\frac{17}{8}\)
\(\Leftrightarrow x=\frac{1683}{320}\)
ta có \(x+1.x+1=8.2=16\)
\(x+1.x+1=4^2\)
\(x+1=4\)
\(x=3\)
Theo đầu bài ta có:
\(\frac{x+1}{2}=\frac{8}{x+1}\)
\(\Rightarrow\left(x+1\right)\left(x+1\right)=2\cdot8\)
\(\Rightarrow\left(x+1\right)^2=16\)
\(\Rightarrow x+1=\sqrt{16}\)
\(\Rightarrow x=4-1\)
\(\Rightarrow x=3\)