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12 tháng 7 2017
a)\(\frac{2}{3}+\frac{3}{4}+\frac{5}{6}\)
\(=\frac{8+9+10}{12}\)
\(=\frac{27}{12}=\frac{9}{4}\)
b)\(\frac{15}{8}-\frac{7}{12}+\frac{5}{6}\)
\(=\frac{45-14+20}{24}\)
\(=\frac{51}{24}=\frac{17}{8}\)
2)
a)\(\frac{2}{5}+\frac{7}{13}+\frac{3}{5}+\frac{1}{7}\)
\(=\frac{2}{5}+\frac{3}{5}+\frac{7}{13}+\frac{1}{7}\)
\(=1+\frac{7}{13}+\frac{1}{7}\)
\(=\frac{20}{13}+\frac{1}{7}\)
\(=\frac{153}{91}\)
Tí tớ trả lời tiếp
T
14 tháng 4 2019
\(A=\left(\frac{3}{8}+\frac{-3}{4}+\frac{7}{12}\right):\frac{5}{6}+\frac{1}{2}\)
\(A=\left(\frac{3}{8}+\frac{-6}{8}+\frac{7}{12}\right):\frac{5}{6}+\frac{1}{2}\)
\(A=\left(\frac{-3}{8}+\frac{7}{12}\right):\frac{5}{6}+\frac{1}{2}\)
\(A=\left(\frac{-36}{24}+\frac{56}{24}\right):\frac{5}{6}+\frac{1}{2}\)
\(A=\frac{5}{6}:\frac{5}{6}+\frac{1}{2}\)
\(A=\frac{5}{6}\times\frac{6}{5}+\frac{1}{2}\)
\(A=1+\frac{1}{2}\)
\(A=\frac{1}{1}+\frac{1}{2}=\frac{2}{2}+\frac{1}{2}\)
\(A=\frac{3}{2}\)
25 tháng 7 2019
a) \(\frac{-5}{8}\cdot\left(\frac{4}{9}+\frac{-7}{12}\right)\)
\(=\frac{-5}{8}\cdot\frac{-5}{36}\)
\(=\frac{25}{288}\)
b) \(\left(-3,2\right)\cdot\frac{-15}{64}+\left(0,8-2\frac{4}{5}\right):3\frac{1}{2}\)
\(=\frac{3}{4}+\left(-2\right):\frac{7}{2}\)
\(=\frac{3}{4}+\frac{-4}{7}\)
\(=\frac{5}{28}\)
=))
MH
3
25 tháng 7 2019
\(\left(-3,2\right).\frac{-15}{64}+\left(0,8-2\frac{4}{15}\right):3\frac{1}{2}=-\frac{16}{5}.-\frac{15}{64}+\left(\frac{4}{5}-\frac{34}{15}\right):\frac{7}{2}\)
\(=-\frac{3}{4}+\left(-\frac{22}{15}\right).\frac{2}{7}\)
\(=-\frac{3}{4}-\frac{44}{105}\)
\(=\frac{-315-176}{420}\)
\(=-\frac{491}{420}\)
25 tháng 7 2019
\(\left(-3,2\right)\cdot\frac{-15}{64}+\left(0,8-2\frac{4}{15}\right):3\frac{1}{2}\)
\(=\frac{3}{4}+\frac{-22}{15}:\frac{7}{2}\)
\(=\frac{3}{4}+\frac{-44}{105}\)
\(=\frac{-315}{176}\)
=))
HT
6 tháng 9 2020
\(A=-\frac{2}{3}+1\frac{1}{4}-\frac{1}{6}=-\frac{2}{3}+\frac{5}{4}-\frac{1}{6}=\frac{5}{12}\)
\(B=\frac{13}{15}\cdot0,25\cdot3+\left(\frac{8}{15}-1\frac{19}{60}\right)\div1\frac{23}{24}\)
\(B=\frac{13}{15}\cdot\frac{1}{4}\cdot3+\left(\frac{8}{15}-\frac{79}{60}\right)\div\frac{47}{24}\)
\(B=\frac{13}{20}-\frac{47}{60}\cdot\frac{24}{47}\)
\(B=\frac{13}{20}-\frac{2}{5}=\frac{1}{4}\)
11 tháng 4 2019
\(1\frac{13}{15}\cdot3\cdot(0,5)^2\cdot3+\left[\frac{8}{15}-1\frac{19}{60}:1\frac{23}{24}\right]\)
\(=\frac{28}{15}\cdot3\cdot0,5\cdot0,5\cdot3+\left[\frac{8}{15}-\frac{79}{60}:\frac{47}{24}\right]\)
\(=\frac{28}{5}\cdot0,25\cdot3+\left[\frac{32}{60}-\frac{79}{60}\cdot\frac{24}{47}\right]\)
\(=\frac{28}{5}\cdot\frac{25}{100}\cdot3+\left[\frac{32}{60}-\frac{158}{235}\right]\)
\(=\frac{28}{5}\cdot\frac{1}{4}\cdot3+\frac{-98}{705}=\frac{7}{5}\cdot1\cdot3+\frac{-98}{705}\)
Đến đây là tính dễ rồi :v
\((-3,2)\cdot\frac{-15}{64}+\left[0,8-2\frac{4}{15}\right]:1\frac{23}{24}\)
\(=\frac{-32}{10}\cdot\frac{-15}{64}+\left[\frac{8}{10}-\frac{34}{15}\right]:\frac{47}{24}\)
\(=\frac{-32\cdot(-15)}{10\cdot64}+\left[\frac{4}{5}-\frac{34}{15}\right]:\frac{47}{24}\)
\(=\frac{-1\cdot(-3)}{2\cdot2}+\frac{4\cdot3-34}{15}:\frac{47}{24}\)
\(=\frac{3}{4}+\frac{-22}{15}:\frac{47}{24}\)
\(=\frac{3}{4}+\frac{-517}{180}=\frac{-191}{90}\)
Bài 2 : \(\frac{2\cdot(-13)\cdot9\cdot10}{(-3)\cdot4\cdot(-5)\cdot26}=\frac{1\cdot(-1)\cdot3\cdot2}{(-1)\cdot2\cdot(-1)\cdot2}=\frac{1\cdot3}{-1\cdot2}=\frac{3}{-2}=\frac{-3}{2}\)
\(\frac{15\cdot8+15\cdot4}{12\cdot3}=\frac{15\cdot(8+4)}{12\cdot3}=\frac{15\cdot12}{12\cdot3}=\frac{15}{3}=5\)
DT
thực hiện phép tính \(\left(-3,2\right).\frac{-15}{64}+\left(0,8-2\frac{4}{15}\right):3\frac{2}{3}\)
4
19 tháng 5 2015
(-3,2) . \(\frac{-15}{64}\)+(0,8-2\(\frac{4}{15}\)):3\(\frac{2}{3}\)
=\(\frac{3}{4}\)+(-\(\frac{22}{15}\)):\(\frac{11}{3}\)
=\(\frac{3}{4}\)+\(\left(-\frac{22}{15}\right).\frac{3}{11}\)
=\(\frac{3}{4}\)-\(\frac{2}{5}=\frac{7}{20}\)
chọn đúng giúp mình nha!
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HT
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