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\(\left(2+\frac{5}{6}\right)\div1\frac{1}{5}+\frac{-7}{12}\)
\(=\left(\frac{12}{6}+\frac{5}{6}\right)\div\frac{6}{5}-\frac{7}{12}\)
\(=\frac{17}{6}\div\frac{6}{5}-\frac{7}{12}\)
\(=\frac{17}{6}\times\frac{5}{6}-\frac{7}{12}\)
\(=\frac{85}{12}-\frac{7}{12}\)
\(=\frac{78}{12}=\frac{13}{2}\)
\(\left(15-6\frac{13}{18}\right)\div11\frac{1}{7}-2\frac{1}{8}\div1\frac{11}{40}\)
\(=9\frac{13}{18}\div\frac{78}{7}-\frac{17}{8}\div\frac{51}{40}\)
\(=\frac{175}{18}\div\frac{78}{7}-\frac{17}{8}\times\frac{40}{51}\)
\(=\frac{175}{18}\times\frac{7}{78}-\frac{5}{3}\)
\(=\frac{1225}{1404}-\frac{5}{3}\)
\(=\frac{1225}{1404}-\frac{2340}{1404}\)
\(=\frac{-1115}{1404}\)
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\(a)15\frac{3}{13}-\left(3\frac{4}{7}+8\frac{3}{13}\right)\)
\(=15\frac{3}{13}-3\frac{4}{7}-8\frac{3}{13}\)
\(=15\frac{3}{13}-8\frac{3}{13}-3\frac{4}{7}\)
\(=7-3\frac{4}{7}\)
\(=6\frac{7}{7}-3\frac{4}{7}=3\frac{3}{7}\)
\(b)\left(7\frac{4}{9}+4\frac{7}{11}\right)-3\frac{4}{9}\)
\(=7\frac{4}{9}-4\frac{7}{11}-3\frac{4}{9}\)
\(=7\frac{4}{9}-3\frac{4}{9}-4\frac{7}{11}\)
\(=4-4\frac{7}{11}=\frac{7}{11}\)
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a)\(\dfrac{6^2.6^3}{3^5}=\dfrac{2^2.3^2.2^3.3^3}{3^5}=2^5=32\)
b)\(\dfrac{25^2.4^2}{5^5\left(-2\right)^5}=\dfrac{5^2.5^2.2^2.2^2}{5^5.\left(-2\right)^5}=\dfrac{1}{-10}=-\dfrac{1}{10}\)
c)\(\dfrac{2^7.9^3}{8^2.3^6}=\dfrac{2^7.\left(3^2\right)^3}{\left(2^3\right)^2.3^6}=\dfrac{2^7.3^6}{2^6.3^6}=2\)
d)\(\dfrac{6^3+3.6^2+3^3}{-13}=\dfrac{2^3.3^3+3.2^2.3^2+3^3}{-13}=\dfrac{3^3\left(2^3+2^2+1\right)}{-13}\)
\(=\dfrac{3^3.13}{-13}=-3^3=-27\)
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\(x-40\%x=3,6\)
\(\Rightarrow100\%x-40\%x=3,6\)
\(\Rightarrow60\%x=3,6\)
\(\Rightarrow\frac{60}{100}x=3,6\)
\(\Rightarrow x=6\)
\(3\frac{2}{7}x-\frac{1}{3}=-2\frac{3}{4}\)
\(\Rightarrow\frac{23}{7}x-\frac{1}{3}=-\frac{11}{4}\)
\(\Rightarrow\frac{23}{7}x=-\frac{33}{12}+\frac{4}{12}\)
\(\Rightarrow\frac{23}{7}x=\frac{29}{12}\)
\(\Rightarrow x=\frac{29}{12}:\frac{23}{7}=\frac{203}{276}\)
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mk chỉ làm thôi nhé
Ta tách biểu thức trên thành hai phần A và B
\(A=\frac{12-\frac{12}{7}-\frac{12}{289}-\frac{12}{85}}{4-\frac{4}{7}-\frac{4}{289}-\frac{12}{85}}\)
\(A=\frac{12.\left(1-\frac{1}{7}-\frac{1}{289}-\frac{1}{85}\right)}{4.\left(1-\frac{1}{7}-\frac{1}{289}-\frac{1}{85}\right)}\)
\(A=3\)
\(B=\frac{3+\frac{3}{13}+\frac{3}{169}+\frac{3}{91}}{7+\frac{7}{13}+\frac{7}{169}+\frac{7}{91}}\)
\(B=\frac{3.\left(1+\frac{1}{13}+\frac{1}{169}+\frac{1}{91}\right)}{7.\left(1+\frac{1}{13}+\frac{1}{169}+\frac{1}{91}\right)}\)
\(B=\frac{3}{7}\)
=> A:B=7
=>b=7
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2-2/19+2/43-2/1943
3-3/19+3/43-3/1943
=2(1-1/19+1/43-1/1943)
3(1-1/19+1/43-1/1943)
=2/3
Chúc bạn học tốt!!!!!
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a)\(\frac{-1}{3}.\frac{141}{17}-13.\frac{-1}{17}\)
\(=\frac{141}{3}.\frac{-1}{17}-13.\frac{-1}{17}\)
\(=47.\frac{-1}{17}-13.\frac{-1}{3}\)
\(=\frac{-1}{17}.\left(47-13\right)\)
\(=\frac{-1}{17}.33=....\)(tự tính)
\(a,\)\(\frac{-1}{3}.\frac{141}{17}-13.\frac{-1}{7}\)
\(=\frac{-1.141}{3.17}+13.\frac{1}{17}\)
\(=\frac{-141}{17}.\frac{1}{7}+13.\frac{1}{7}\)
\(=\frac{1}{7}\left(-47+13\right)\)
\(=\frac{-34}{7}\)
\(b,\)\(\frac{-9}{16}.\frac{13}{3}-\left(-\frac{3}{4}\right)^2.\frac{19}{3}\)
\(=\left(\frac{3}{4}\right)^2.\frac{-13}{3}-\left(-\frac{9}{16}\right).\frac{19}{3}\)
\(=\frac{9}{16}.\frac{-13}{3}+\frac{9}{16}.\frac{19}{3}\)
\(=\frac{9}{16}\left(\frac{-13}{3}+\frac{19}{3}\right)=\frac{9}{16}.2=\frac{9}{8}\)
\(\frac{6^3+3\times6^2+3^3}{-13}=\frac{2^3\times3^3+3\times2^2\times3^2+3^3}{-13}\)
\(=\frac{3^3\left(2^3+2^2+1\right)}{-13}\)
\(=\frac{3^3\times13}{-13}\)
\(=-27\)
Cảm Ơn !