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\(\frac{12}{20}\)= \(\frac{6}{10}\)= \(\frac{3}{5}\)
\(\frac{3}{4}\)= \(\frac{9}{12}\)= \(\frac{12}{16}\)= \(\frac{15}{20}\)
\(\frac{75}{45}\)= \(\frac{15}{9}\)= \(\frac{5}{3}\)
\(\frac{3}{4}\)= \(\frac{18}{24}\)= \(\frac{12}{16}\)
12/20 = 6/10 = 3/5
3/4 = 9/12 = 12/16 = 15/20
75/45 = 15/9 = 5/3
3/4 = 18/24 = 12/16
Tk mk nha

Đáp án lần lượt là: \(\frac{23}{36};\frac{31}{7};\frac{1}{6};\frac{3}{5}\)
#Hk_tốt
#Ken'z

2/5 = 4/10 = 8/20
4/12 = 2/6 = 1/3
dấu / chính là "phần " nha.
VD 1/4 : Một phần bốn

1
\(\frac{2}{12;}=\frac{1}{6}\)
\(\frac{42}{63}=\frac{1}{2}\)
\(\frac{5}{60}=\frac{1}{12}\)
2.
\(\frac{3}{4}=\frac{15}{12}\) số còn lại giữ nguyên
\(\frac{20}{5}=\frac{120}{30};\frac{7}{6}=\frac{35}{30}\)
\(\frac{1}{6}\) \(\frac{7}{9}\) \(\frac{1}{12}\)
\(\frac{5}{12}và\frac{9}{12}\) \(\frac{120}{30}và\frac{35}{30}\)

1) \(\frac{4}{5}.\frac{8}{3}.\frac{x}{7}=\frac{96}{105}\)
\(\frac{32.x}{105}=\frac{96}{105}\)
\(32x=96\)
\(x=3\)
Bài 1: Tìm \(x\)
\(\frac45\times\frac83\times\) \(\frac{x}{7}\) = \(\frac{96}{105}\)
\(\frac{32}{15}\) x \(\frac{x}{7}\) = \(\frac{32}{35}\)
\(\frac{x}{7}\) = \(\frac{32}{35}\) : \(\frac{32}{15}\)
\(\frac{x}{7}\) = \(\frac{32}{35}\) x \(\frac{15}{32}\)
\(\frac{x}{7}\) = \(\frac37\)
\(x=\frac37\times7\)
\(x=3\)
b; \(\frac74\times\frac{3}{x}\times\) \(\frac{11}{5}\) = \(\frac{231}{200}\)
\(\frac74\) x \(\frac{3}{x}\) = \(\frac{231}{200}\) : \(\frac{11}{5}\)
\(\frac74\times\frac{3}{x}\) = \(\frac{231}{200}\) x \(\frac{5}{11}\)
\(\frac74\) x \(\frac{3}{x}\) = \(\frac{21}{40}\)
\(\frac{3}{x}\) = \(\frac{21}{40}\) : \(\frac74\)
\(\frac{3}{x}\) = \(\frac{21}{40}\) x \(\frac47\)
\(\frac{3}{x}\) = \(\frac{3}{10}\)
\(x=3:\frac{3}{10}\)
\(x=3\times\frac{3}{10}\)
\(x=10\)

a.\(\frac{3\cdot4\cdot7}{12\cdot8\cdot9}\)= \(\frac{3\cdot4\cdot7}{3\cdot4\cdot8\cdot9}\)= \(\frac{7}{72}\)
b. \(\frac{4\cdot5\cdot6}{12\cdot10\cdot8}\)= \(\frac{4\cdot5\cdot2\cdot3}{3\cdot4\cdot5\cdot2\cdot8}\)= \(\frac{1}{8}\)
c.\(\frac{5\cdot6\cdot7}{12\cdot14\cdot15}\)= \(\frac{5\cdot6\cdot7}{2\cdot6\cdot2\cdot7\cdot3\cdot5}\)= \(\frac{1}{12}\)