\(\frac{3}{5}\)- \(\frac{7}{45}\)+\(\fra...">
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\(\frac{3}{5}-\frac{7}{45}+\frac{11}{9.13}-\frac{15}{13.17}+\frac{19}{17.21}-\frac{23}{21.25}\)

\(=\frac{3}{5}-\frac{7}{45}+\frac{11}{117}-\frac{15}{221}+\frac{19}{357}-\frac{23}{42}\)

\(=\left(\frac{-7}{45}-\frac{15}{221}-\frac{23}{42}\right)+\left(\frac{3}{5}+\frac{11}{117}+\frac{19}{357}\right)\)

đến đây bạn tự tính nhé.

9 tháng 4 2019

1, Tính tổng:

\(C=\frac{5}{7}\cdot\frac{5}{11}+\frac{5}{7}\cdot\frac{2}{11}-\frac{5}{7}\cdot\frac{14}{11}\)

\(=\frac{5}{7}\cdot\left(\frac{5}{11}+\frac{2}{11}-\frac{14}{11}\right)=\frac{5}{7}\cdot\frac{-7}{11}=\frac{-5}{11}\)

2, Tìm x:

\(x+\frac{5}{5\cdot9}+\frac{4}{9\cdot13}+\frac{4}{13\cdot17}+...+\frac{4}{41\cdot45}=\frac{-37}{45}\)

\(\Rightarrow x+\frac{1}{5}-\frac{1}{9}+\frac{1}{9}-\frac{1}{13}+\frac{1}{13}-\frac{1}{17}+...+\frac{1}{41}-\frac{1}{45}=\frac{-37}{45}\)

\(\Rightarrow x+\frac{1}{5}-\frac{1}{45}=\frac{-37}{45}\Rightarrow x+\frac{9}{45}-\frac{1}{45}=\frac{-37}{45}\)

\(\Rightarrow x+\frac{8}{45}=\frac{-37}{45}\Rightarrow x=\frac{-37}{45}-\frac{8}{45}=\frac{-45}{45}=-1\)

- Các bài tìm x còn lại bạn cứ theo trình tự thực hiện phép tính mà làm nhé!

9 tháng 4 2019

\(C=\frac{5}{7}\cdot\frac{5}{11}+\frac{5}{7}\cdot\frac{2}{11}-\frac{5}{7}\cdot\frac{14}{11}\)

\(=\frac{5}{7}\cdot\left(\frac{5}{11}+\frac{2}{11}-\frac{14}{11}\right)\)

\(=\frac{5}{7}\cdot-\frac{7}{11}\)

\(=-\frac{5}{11}\)

14 tháng 3 2018

a) \(\frac{31}{23}-\left(\frac{7}{23}+\frac{8}{23}\right)\)

\(=\frac{31}{23}-\frac{15}{23}\)

\(=\frac{16}{23}\)

b) \(\left(\frac{1}{3}+\frac{12}{67}+\frac{13}{41}\right)-\left(\frac{79}{67}-\frac{28}{41}\right)\)

\(=\frac{1}{3}+\frac{12}{67}+\frac{13}{41}-\frac{79}{67}+\frac{28}{41}\)

\(=\frac{1}{3}+\left(\frac{12}{67}-\frac{79}{67}\right)+\left(\frac{13}{41}+\frac{28}{41}\right)\)

\(=\frac{1}{3}+\frac{-67}{67}+\frac{41}{41}\)

\(=\frac{1}{3}-1+1\)

\(=\frac{1}{3}\)

c) \(\frac{38}{45}-\left(\frac{8}{45}-\frac{17}{52}-\frac{3}{11}\right)\)

\(=\frac{38}{45}-\frac{8}{45}+\frac{17}{52}+\frac{3}{11}\)

\(=\frac{30}{45}+\frac{17}{52}+\frac{3}{11}\)

\(=\frac{2}{3}+\frac{17}{52}+\frac{3}{11}\)

\(=\frac{104+51}{156}+\frac{3}{11}\)

\(=\frac{155}{156}+\frac{3}{11}\)

\(=\frac{156}{156}-\frac{1}{156}+\frac{3}{11}\)

\(=1-\frac{1}{156}+\frac{3}{11}\)

\(=1-\left(\frac{11-468}{1716}\right)\)

\(=1-\frac{-457}{1716}\)

\(=1+\frac{457}{1716}\)

\(=\frac{2173}{1716}\)

14 tháng 3 2018

a)31/23-(7/32+8/23)=31/23-7/32-8/23=(31/23-8/23)-7/32=1-7/32=25/32

18 tháng 8 2020

a) \(\frac{-8}{18}-\frac{15}{27}=\frac{-4}{9}-\frac{5}{9}=\frac{-4-5}{9}=\frac{-9}{9}=-1\)

b) \(\frac{19}{24}-\left(-\frac{1}{2}+\frac{7}{24}\right)\)

\(=\frac{19}{24}+\frac{1}{2}-\frac{7}{24}=\left(\frac{19}{24}-\frac{7}{24}\right)+\frac{1}{2}=\frac{1}{2}+\frac{1}{2}=1\)

c) \(\frac{3^{11}\cdot11+3^{11}\cdot21}{3^9\cdot2^5}=\frac{3^{11}\left(11+21\right)}{3^9\cdot2^5}\)

\(=\frac{3^{11}\cdot32}{3^9\cdot32}=3^2=9\)

16 tháng 5 2018

a/=(74-(-1937)1)

   =74-(-1937)

   =2011

b/=4/7+5/6:5-3/8*(-4)

   =4/7+1/6-(-3/2)

   =31/42-(-3/2)

   =47/21

minh chi biet bay nhieu

18 tháng 8 2020

a) \(-\frac{8}{18}-\frac{15}{27}=-\frac{4}{9}-\frac{5}{9}=\frac{-9}{9}=-1\)

b) \(\frac{19}{24}-\left(-\frac{1}{2}+\frac{7}{24}\right)\)

\(=\frac{19}{24}+\frac{12}{24}-\frac{7}{24}=\frac{24}{24}=1\)

c) \(P=\frac{3^{11}.11+3^{11}.21}{3^9.2^5}\)

\(P=\frac{3^{11}.\left(11+21\right)}{2^9.2^5}=\frac{3^{11}.32}{2^9.32}=3^2=9\)

d) \(\frac{2}{1.2}+\frac{2}{2.3}+\frac{2}{3.4}+...+\frac{2}{99.100}\)

\(=2\left(1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{99}-\frac{1}{100}\right)\)

\(=2\left(1-\frac{1}{100}\right)\)

\(=2.\frac{99}{100}=\frac{99}{50}\)

\(3\frac{14}{19}+\frac{13}{17}+\frac{35}{43}+6\frac{5}{19}+\frac{8}{43}\)

\(=\left(3\frac{14}{19}+6\frac{5}{19}\right)+\left(\frac{35}{43}+\frac{8}{43}\right)+\frac{13}{17}\)

\(=10+1+\frac{13}{17}=11+\frac{13}{17}=11\frac{13}{17}\)

\(\frac{-5}{7}.\frac{2}{11}+\frac{-5}{7}.\frac{9}{11}+1\frac{5}{7}\)

\(=\frac{-5}{7}.\frac{2}{11}+\frac{-5}{7}.\frac{9}{11}+1+\frac{-5}{7}.\left(-1\right)\)

\(=\frac{-5}{7}\left(\frac{2}{11}+\frac{9}{11}-1\right)+1\)

\(=\frac{-5}{7}.0+1==0+1=1\)