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\(6xy+\left(\frac{1}{2x3}+\frac{1}{3x4}+\frac{1}{4x5}+...+\frac{1}{7x8}\right)=\frac{29}{8}\)
Đăt \(A=\frac{1}{2x3}+\frac{1}{3x4}+\frac{1}{4x5}+...+\frac{1}{7x8}\)
\(\Rightarrow A=\frac{3-2}{2x3}+\frac{4-3}{3x4}+\frac{5-4}{4x5}+...+\frac{8-7}{7x8}\)
\(A=\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+...+\frac{1}{7}-\frac{1}{8}=\frac{1}{2}-\frac{1}{8}=\frac{3}{8}\)
\(\Rightarrow6xy+A=6xy+\frac{3}{8}=\frac{29}{8}\Rightarrow6xy=\frac{26}{8}\Rightarrow y=\frac{26}{8x6}\)
NHẦM LÀM LẠI :
\(B=\left(5+7+1\right)+\left(\frac{19}{29}+\frac{10}{29}\right)+\left(\frac{43}{52}+\frac{9}{52}\right)+\frac{1}{7}=13+1+1+\frac{1}{7}=15\frac{1}{7}\)
B=\(\left(5+\frac{1}{7}+\frac{19}{29}\right)+\left(7+\frac{43}{52}+1+\frac{10}{29}\right)+\frac{9}{52}=\left(5+7+1\right)+\left(\frac{19}{29}+\frac{10}{29}\right)+\left(\frac{43}{52}+\frac{10}{52}+\frac{9}{52}\right)+\frac{1}{7}=13+1+1+\frac{1}{7}=15\frac{1}{7}\)
\(=1-\frac{1}{1\cdot2}+1-\frac{1}{2\cdot3}+1-\frac{1}{3\cdot4}+...+1-\frac{1}{9\cdot10}\)
\(=\left[1+1+1+...+1\right]-\left[\frac{1}{1\cdot2}+\frac{1}{2\cdot3}+...+\frac{1}{9\cdot10}\right]\)
\(=9-\left[\frac{1}{1}-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+...+\frac{1}{9}-\frac{1}{10}\right]=9-\left[1-\frac{1}{10}\right]\)
\(=9-\frac{9}{10}=\frac{81}{10}\)
\(\frac{1}{2}+\frac{5}{6}+\frac{11}{12}+\frac{19}{20}+...+\frac{89}{90}\)
\(=1-\frac{1}{2}+1-\frac{1}{6}+1-\frac{1}{12}+1-\frac{1}{20}+...+1-\frac{1}{90}\)
\(=9-\left(\frac{1}{2}+\frac{1}{6}+\frac{1}{12}+\frac{1}{20}+...+\frac{1}{90}\right)\)
\(=9-\left(\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+\frac{1}{4.5}+...+\frac{1}{9.10}\right)\)
\(=9-\left(1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+....+\frac{1}{9}-\frac{1}{10}\right)\)
\(=9-\left(1-\frac{1}{10}\right)\)
\(=9-\frac{9}{10}=\frac{81}{10}\)
25/49 x 21/29 - 25/49 x 7/29 + 24/29
= 25/49 x ( 21/ 29 - 7/29 ) + 24/49
= 25/49 x 14/29 + 24/29
= 350/1421 + 24/29
= 350/1421 + 1176/1421
= 1526/1421
\(\frac{25}{49}\times\frac{21}{29}-\frac{25}{49}\times\frac{7}{29}+\frac{24}{49}\)
\(=\frac{25\times\left(21-7\right)}{49\times29}+\frac{24}{49}\)
\(\frac{50}{7\times29}+\frac{24}{49}=\frac{2450+4872}{7\times29\times49}=\frac{7322}{7\times29\times49}=\frac{1046}{1421}\)
A)\(-\frac{3}{29}+\frac{16}{58}=-\frac{3}{29}+\frac{8}{29}=\frac{5}{29}\)
B)\(-\frac{1}{5}+\frac{5}{18}+-\frac{7}{9}=-\frac{1}{5}+\frac{5}{18}+-\frac{14}{18}=-\frac{1}{5}+-\frac{1}{2}\)\(=-\frac{2}{10}+-\frac{5}{10}=-\frac{7}{10}\)
C)\(-\frac{8}{18}+-\frac{15}{27}=-\frac{4}{9}+-\frac{5}{9}=-1\)
\(\frac{1}{2}.3,6:8,2+29=\frac{1198}{41}\)nha ^_^
\(\frac{1198}{41}nha\)