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2013/2014=1-1/2014
2003/2004=1-1/2004
vì 1/2014<1/2004
=) 1-1/2014>1-1/2004
hay 2013/2014>2003/2004
![](https://rs.olm.vn/images/avt/0.png?1311)
bài 1
Ta có : 2016/2017<1
2017/2018<1
Nên 2016/2017=2017/2018
Bài 1 :
a) Ta có : \(\frac{2016}{2017}=1-\frac{1}{2017}\)
\(\frac{2017}{2018}=1-\frac{1}{2018}\)
Vì \(-\frac{1}{2017}< -\frac{1}{2018}\)nên \(\frac{2016}{2017}< \frac{2017}{2018}\)
b) Ta có : \(\frac{2018}{2017}=1+\frac{1}{2017}\)
\(\frac{2017}{2016}=1+\frac{1}{2016}\)
Vì \(\frac{1}{2017}< \frac{1}{2016}\) nên \(\frac{2018}{2017}< \frac{2017}{2016}\)
Câu 2 :
\(\frac{1}{1.3}+\frac{1}{3.5}+\frac{1}{5.7}+...+\frac{1}{101.103}\)
\(=\frac{1}{2}.\left(\frac{2}{1.3}+\frac{2}{3.5}+\frac{2}{5.7}+...+\frac{2}{101.103}\right)\)
\(=\frac{1}{2}.\left(1-\frac{1}{3}+\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{7}+...+\frac{1}{101}-\frac{1}{103}\right)\)
\(=\frac{1}{2}.\left(1-\frac{1}{103}\right)\)
\(=\frac{1}{2}.\frac{102}{103}=\frac{51}{103}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
a. 123/123 < 50/49
b. 19/40 < 81/160
c. 111/115< 555/559
d. 25/26 < 50/51
e. 29/33< 37/39
222/37<37/39
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Quy đồng tử số, ta có: \(\frac{1}{3}=\frac{1x5}{3x5}=\frac{5}{15}\)
Phân số nào có mẫu số nhỏ hơn thì lớn hơn
Mà: \(\frac{5}{15}>\frac{5}{123}\)
Vậy \(\frac{1}{3}>\frac{5}{123}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
Ta có:
\(\frac{20032003}{20022002}=\frac{20032003:10001}{20022002:10001}=\frac{2003}{2002}\)
\(\frac{2014}{2013}=\frac{2014.182}{366366}=\frac{366548}{366366}\)
\(\frac{2003}{2002}=\frac{2003.182}{366366}=\frac{364546}{366366}\)
\(\Rightarrow\frac{2014}{2013}>\frac{2003}{2002}\)
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không quy đồng thì rút gọn
121212/131313=12/13
vậy 12/13>12/18
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#)Giải :
Ta có : \(1-\frac{2010}{2011}=\frac{1}{2011}\)
\(1-\frac{2011}{2012}=\frac{1}{2012}\)
Vì \(\frac{1}{2011}>\frac{1}{2012}\Rightarrow\frac{2010}{2011}>\frac{2011}{2012}\)
\(\frac{2010}{2011}=1-\frac{1}{2011}\)
\(\frac{2011}{2012}=1-\frac{1}{2012}\)
\(2011\)<\(2012\)\(\Rightarrow\frac{1}{2011}\)>\(\frac{1}{2012}\)
\(\Rightarrow\frac{2010}{2011}\)<\(\frac{2011}{2012}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\frac{9}{11}\)< \(\frac{13}{15}\)
\(\frac{19}{15}\)< \(\frac{15}{11}\)
Ta có: 124124/125125=124124:1001/125125:1001=124/125
Ta có: 1-123/124=1/124, 1-124/125= 1/125
Ta thấy: 1/124>1/125 nên 123/124<124/125
Bạn nhắn riêng cho mik cách vt PS như bạn nhé!
Ta có :
\(\frac{123}{124}=1-\frac{1}{124}\)
\(\frac{124124}{125125}=\frac{124.101}{125.101}=\frac{124}{125}=1-\frac{1}{125}\)
Vì \(\frac{1}{124}>\frac{1}{125}\Rightarrow1-\frac{1}{124}< 1-\frac{1}{125}\)
\(\Rightarrow\frac{123}{124}< \frac{124124}{125125}\)