\(\frac{1}{1^2}.\frac{6}{2^2}.\frac{12}{3^2}.\frac{20}{4^2}....\frac{110}{^{10^2}}=-20:x\)
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16 tháng 8 2015

(1.6.12.20.....110)/(1.1.2.2.3.3.....10.10)=-20/x

(1.2.3.3.4.4.5.....10.11)/(1.1.2.2.3.3...10.10)=-20/x

11/2=-20/x

hay -20/x=11/2

x=-40/11

...
Đọc tiếp

\(\left(\frac{-5}{12}+\frac{7}{4}-\frac{3}{8}\right)-\left[4\frac{1}{2}-7\frac{1}{3}\right]-\left(\frac{1}{4}-\frac{5}{2}\right)\)

\(\left[2\frac{1}{4}-5\frac{3}{2}\right]-\left(\frac{3}{10}-1\right)-5\frac{1}{2}+\left(\frac{1}{3}-\frac{5}{6}\right)\)

\(\frac{4}{7}-\left(3\frac{2}{5}-1\frac{1}{2}\right)-\frac{5}{21}+\left[3\frac{1}{2}-4\frac{2}{3}\right]\)

\(\frac{1}{8}-1\frac{3}{4}+\left(\frac{7}{8}-3\frac{7}{2}+\frac{3}{4}\right)-\left[\frac{7}{4}-\frac{5}{8}\right]\)

\(\left(\frac{3}{5}-2\frac{1}{10}+\frac{11}{20}\right)-\left[\frac{-3}{4}+1\frac{7}{2}\right]\)

\(\left[-2\frac{1}{5}-2\frac{2}{3}\right]-\left(\frac{1}{15}-5\frac{1}{2}\right)+\left[\frac{-1}{6}+\frac{1}{3}\right]\)

\(1\frac{1}{8}-\left(\frac{1}{15}-\frac{1}{2}+\frac{-1}{6}\right)+\left[\frac{5}{4}+\frac{3}{2}\right]\)

\(\frac{5}{6}-\left(1\frac{1}{3}-1\frac{1}{2}\right)+\left[\frac{5}{12}-\frac{3}{4}-\frac{1}{6}\right]\)

\(1\frac{1}{4}-\left(\frac{7}{12}-\frac{2}{3}-1\frac{3}{8}\right)+\left[\frac{5}{24}-2\frac{1}{2}\right]-\frac{1}{6}-\left[\frac{-3}{4}\right]\)

\(-2\frac{1}{5}+2\frac{3}{10}-\left(\frac{6}{20}-\left[\frac{2}{8}-1\frac{1}{2}\right]\right)+\left[\frac{7}{20}-1\frac{1}{4}\right]\)

\(-\left[1\frac{2}{3}-3\frac{1}{2}+\frac{1}{4}\right]+\left(\frac{2}{6}-\frac{5}{12}\right)-\left(\frac{1}{3}-\left[\frac{1}{4}-\frac{1}{3}\right]\right)\)

\(-\frac{4}{5}-\left(1\frac{1}{10}-\frac{7}{10}\right)+\left[\frac{3}{4}-1\frac{1}{5}\right]+1\frac{1}{2}\)

\(\frac{3}{21}-\frac{5}{14}+\left[1\frac{1}{3}-5\frac{1}{2}+\frac{5}{14}\right]-\left(\frac{1}{6}-\frac{3}{7}+\frac{1}{3}\right)\)

\(-1\frac{2}{5}+\left[1\frac{3}{10}-\frac{7}{20}-1\frac{1}{4}\right]-\left(\frac{1}{5}-\left[\frac{3}{4}-1\frac{1}{2}\right]\right)\)

\(2\frac{1}{3}-\left(\frac{1}{2}-2\frac{1}{6}+\frac{3}{4}\right)+\left[\frac{5}{12}-1\frac{1}{3}\right]-\frac{7}{8}+3\frac{1}{2}\)

\(2\frac{1}{4}-1\frac{3}{5}-\left(\frac{9}{20}-\frac{7}{10}\right)+\left[1\frac{3}{5}-2\frac{1}{2}\right]+\frac{3}{4}\)

\(\left[\frac{8}{3}-5\frac{1}{4}+\frac{1}{6}\right]-\frac{7}{4}+\frac{-5}{12}-\left(1-1\frac{1}{2}+\frac{1}{3}\right)\)

\(\left(\frac{1}{4}-\left[1\frac{1}{4}-\frac{7}{10}\right]+\frac{1}{2}\right)-2\frac{1}{5}-1\frac{3}{10}+\left[1-\frac{1}{2}\right]\)

TRÌNH BÀY GIÚP MÌNH NHA 

0

\(\frac{7}{8}.(\frac{2}{12}+\frac{4}{10})\)

\(\Rightarrow\frac{7}{8}.(\frac{10+24}{60})\)

\(\Rightarrow\frac{7}{8}.\frac{34}{60}=\frac{238}{480}\)

bt2

\(2.x-\frac{5}{4}=\frac{20}{15}\)

\(\Leftrightarrow2x=\frac{20}{15}+\frac{5}{4}\)

\(\Leftrightarrow2x=\frac{80+75}{60}\)

\(\Leftrightarrow2x=2,5\)

\(\Leftrightarrow x=1,25\)

29 tháng 10 2018

.7/8.(1/6+2/5)=7/8.17/30=119/240

3/2-5/6:1/4+\(\sqrt{4}\)=3/2-10/3+2=1/6

2x=20/15+5/4

2x=31/12

x=31/12:2

x=31/24

ko bt nha thông cảm

22 tháng 6 2019

#)Well ! Bài này cg dạng tầm cỡ vừa :v 

Làm cho ai v ? mau vô nhận bài đê !

22 tháng 6 2019

ờ tụi làm cho bạn trên lớp í mà

Mà tui ngu quá nhóm lun từ số 1 nhanh hơn ko 

18 tháng 7 2018

a,x-2/5=5/7

x=5/7+2/5

x=39/35

b,-2/5.x=4/15

x=4/15:-2/5

x=-2/3

18 tháng 7 2018

a) \(x-\frac{2}{5}=\frac{5}{7}\)

\(x=\frac{2}{5}+\frac{5}{7}\)

\(x=\frac{14}{35}+\frac{25}{35}=\frac{39}{35}\)

b)

\(\frac{-2}{5}x=\frac{4}{15}\)

\(x=\frac{4}{15}:-\frac{2}{5}\)

\(x=\frac{4}{15}\cdot-\frac{5}{2}=-\frac{2}{3}\)

c) \(2x\left(x-\frac{1}{7}\right)=2x^2-\frac{2x}{7}\)

d) \(\frac{1}{2}+\frac{3}{4}x=\frac{1}{4}\)

\(\frac{3}{4}x=\frac{1}{4}-\frac{1}{2}\)

\(\frac{3}{4}x=-\frac{1}{4}\)

\(x=-\frac{1}{4}\cdot\frac{4}{3}=-\frac{1}{3}\)

f) \(\frac{11}{12}-\left(\frac{2}{5}+x\right)=\frac{2}{5}\)

\(\frac{2}{5}+x=\frac{11}{12}-\frac{2}{5}=\frac{31}{60}\)

\(x=\frac{31}{60}-\frac{2}{5}=\frac{7}{60}\)

30 tháng 7 2018

\(a,\frac{16^3.3^{10}+120.6^9}{4^6.3^{12}+6^{11}}\)

\(=\frac{\left(2^4\right)^3.3^{10}+2^3.3.5.\left(2.3\right)^9}{\left(2^2\right)^6.3^{12}+\left(2.3\right)^{11}}\)

\(=\frac{2^{12}.3^{10}+2^3.3.5.2^9.3^9}{2^{12}.3^{12}+2^{11}.3^{11}}\)

\(=\frac{2^{12}.3^{10}+2^{12}.3^{10}.5}{2^{11}.3^{11}\left(2.3+1\right)}\)

\(=\frac{2^{12}.3^{10}\left(1+5\right)}{2^{11}.3^{11}.7}=\frac{2.6}{3.7}=\frac{4}{7}\)