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\(\frac{10^3+2.5^3+5^3}{65}=\frac{1000+5^3.3}{65}=\frac{1000+375}{65}\)
= \(\frac{1375}{65}=\frac{275}{13}\)
\(\frac{10^3+2.5^5+5^3}{65}\)
= \(\frac{\left(2.5\right)^3+2.5^5+5^3}{5.13}\)
= \(\frac{2^3.5^3+2.5^5+5^3}{5.13}\)
= \(\frac{5^3\left(2^3+2+1\right)}{5.13}\)
= \(\frac{5^2.11}{13}\)
= \(\frac{275}{13}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
a ) \(\frac{15}{2}-\left(-\frac{7}{3}\right)-\frac{7}{3}-10\)
= \(\frac{15}{2}+\frac{7}{3}-\frac{7}{3}-10\)
=\(\frac{15}{2}-10\)
= \(\frac{-5}{2}\)
b ) \(\frac{65}{2}+\left(-\frac{65}{3}\right)-\frac{130}{3}\)
= \(\frac{65}{6}-\frac{130}{3}\)
=\(\frac{-65}{2}\)
c ) \(\left(\frac{-16}{3}\right)+\left(\frac{-2}{3}\right)\)
= -6
d ) \(\frac{1}{7}+\frac{9}{-8}+\left(-\frac{3}{14}\right)\)
= \(\frac{-55}{56}+\left(-\frac{3}{14}\right)\)
= \(\frac{-67}{56}\)
e ) - 1,8 +\(\frac{5}{-6}\)
= \(\frac{-79}{30}\)
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\(x=\frac{2^3\cdot25^2}{10^2\cdot5^3}=\frac{2^3\cdot\left(5^2\right)^2}{\left(2\cdot5\right)^2\cdot5^3}\)
\(=\frac{2^3\cdot5^4}{2^2\cdot5^2\cdot5^3}=\frac{2^3\cdot5^4}{2^2\cdot5^5}=\frac{2}{5}\)
Vậy x = 2/5
\(\frac{10^3+2.5^3+5^3}{65}=\frac{10^3+5^3.\left(2+1\right)}{65}=\frac{10^3+5^3.3}{65}\)
= \(\frac{10^3+375}{65}=\frac{1375}{65}\)
\(\frac{10^3+2.5^3+5^3}{65}=\frac{1000+2.125+125}{65}=\frac{8.125+2.125+125.1}{65}=\frac{125\left(8+2+1\right)}{65}=\frac{125.11}{65}=\frac{1375}{65}=\frac{275}{13}\)