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\(\left(\frac{1}{6}+\frac{1}{10}+\frac{1}{15}\right):\left(\frac{1}{6}+\frac{1}{10}-\frac{1}{15}\right)\)
=\(\frac{1}{3}+\frac{1}{5}\)
=\(\frac{5}{3}\)
<=> (a+15)(1/1.2 +...+1/99.100)=297/10
<=>(a+15)(1/1-1/2+...=1/99-1/100)=297/100
<=> (a+15)99/100=297/100
<=>a+15=3
<=>a=-12
\(\frac{1}{x}:\frac{1}{3}\times\frac{1}{4}=\frac{5}{6}\)
\(\frac{3}{x}\times\frac{1}{4}=\frac{5}{6}\)
\(\frac{3}{x}=\frac{5}{6}:\frac{1}{4}\)
\(\frac{3}{x}=\frac{10}{3}\)
\(\Leftrightarrow3.3=10.x\)
\(\Leftrightarrow9=10.x\)
\(\Leftrightarrow x=\frac{9}{10}\)
\(\frac{1}{x}:\frac{1}{3}\times\frac{1}{4}=\frac{5}{6}\)
\(\frac{1}{x}:\frac{1}{3}=\frac{10}{3}\)
\(\frac{3}{x}=\frac{10}{3}\)
\(x=3.\frac{3}{10}=\frac{9}{10}\)
\(\frac{a}{b}.4+\frac{1}{6}=\frac{17}{6}\)
\(\frac{a}{b}.4\) \(=\frac{17}{6}-\frac{1}{6}\)
\(\frac{a}{b}.4\) \(=\frac{8}{3}\)
\(\frac{a}{b}=\frac{8}{3}:4\)
\(\frac{a}{b}=\frac{2}{3}\)
\(\frac{a}{b}.4=\frac{17}{6}-\frac{1}{6}\)
\(\frac{a}{b}.4=\frac{16}{6}\)
\(\frac{a}{b}=\frac{16}{6}:4\)
\(\frac{a}{b}=\frac{16}{6}.\frac{1}{4}=\frac{16}{6.4}=\frac{2}{3}\)
Bỏ đi \(\frac{1}{36}\) ta được
\(\frac{1}{3}\) +\(\frac{1}{6}\)+\(\frac{1}{10}\)+\(\frac{1}{15}\)+\(\frac{1}{21}\)+\(\frac{1}{28}\)
=\(\frac{140+70+42+28+20+15}{420}\)
=\(\frac{315}{420}\)
=\(\frac{3}{4}\)
a,=25/6;7/6=25/6x6/7=25/7
b,=7/2x32/6=56/3
c,=17/5-11/10=34/10-11/10=23/10
d,=8/3+11/4=32/12+33/12=65/12
\(a.200+6+\frac{3}{100}=206,03.\) .
\(b.27+\frac{4}{10}+\frac{6}{100}=27,46\) .
Gọi số cần tìm là x
Theo đề bài ta có :
\(\frac{x}{6}=\frac{10}{15}\)
\(\Rightarrow\) \(x\times15=6\times10\)
\(x\times15=60\)
\(x=60\div15\)
\(x=4\)
Vậy số cần tìm là 4
\(\frac{x}{6}=\frac{10}{15}\)
\(\Rightarrow\frac{5x}{30}=\frac{20}{30}\)
\(\Rightarrow5x=20\)
\(\Rightarrow x=4\)