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#)Trả lời :
\(A=\frac{\left(140+70+42+28+20+15\right)}{420}\)
\(A=\frac{315}{420}=\frac{\left(315:105\right)}{\left(420:105\right)}=\frac{3}{4}\)
Vậy : \(A=\frac{3}{4}\)
#~Will~be~Pens~#
đặt \(A=\frac{1}{21}+\frac{1}{28}+\frac{1}{36}+........+\frac{2}{x.\left(x+1\right)}=\frac{2}{9}\)
\(\frac{1}{2}A=\frac{1}{42}+\frac{1}{56}+\frac{1}{72}+........+\frac{1}{x.\left(x+1\right)}=\frac{2}{9}.\frac{1}{2}\)
\(\frac{1}{2}A=\frac{1}{6.7}+\frac{1}{7.8}+\frac{1}{8.9}+........+\frac{1}{x.\left(x+1\right)}=\frac{1}{9}\)
\(\frac{1}{2}A=\frac{1}{6}-\frac{1}{7}+\frac{1}{7}-\frac{1}{8}+\frac{1}{8}-\frac{1}{9}+.....+\frac{1}{x}-\frac{1}{x+1}=\frac{1}{9}\)
\(\frac{1}{2}A=\frac{1}{6}-\frac{1}{x+1}=\frac{1}{9}\)
\(\Rightarrow\frac{1}{6}-\frac{1}{x+1}=\frac{1}{9}\)
\(\Rightarrow\frac{1}{x+1}=\frac{1}{6}-\frac{1}{9}\)
\(\Rightarrow\frac{1}{x+1}=\frac{1}{18}\)
\(\Rightarrow x+1=18\)
\(\Rightarrow x=18-1\)
\(\Rightarrow x=17\)
vậy \(x=17\)
Sửa đề
\(R=\left(1-\frac{1}{21}\right)\left(1-\frac{1}{28}\right)\left(1-\frac{1}{36}\right)....\left(1-\frac{1}{1326}\right)\)
\(R=\frac{20}{21}.\frac{27}{28}.\frac{35}{36}....\frac{1325}{1326}\)
\(R=\frac{40}{42}.\frac{54}{56}.\frac{70}{72}.......\frac{2650}{2652}\)
\(R=\frac{5.8}{6.7}.\frac{6.9}{7.8}.\frac{7.10}{8.9}.......\frac{50.53}{51.52}\)
\(R=\frac{5.6.7.8.9...50}{6.7.8.9.10...51}.\frac{8.9.10...53}{7.8.9...52}=\frac{5}{51}.\frac{53}{7}=\frac{265}{357}\)
\(R=\frac{20}{21}.\frac{27}{28}.\frac{34}{35}....\frac{1325}{1326}\)
Bạn chờ chút để mình nghĩ nốt nhé
\(-\frac{1}{21}+-\frac{1}{28}=\frac{-28-21}{588}=-\frac{49}{588}=\frac{-1}{12}\)
Chúc bạn học tốt
\(\frac{-1}{21}+\frac{-1}{28}=\frac{-28}{588}+\frac{-21}{588}=\frac{-49}{588}=\frac{-7}{84}\)
Bạn sai đề à