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NT
1
2 tháng 7 2018
\(-1,75-\left(\dfrac{-1}{9}-2\dfrac{1}{18}\right)\)
\(=-1,75-\left(\dfrac{-2}{18}-\dfrac{37}{18}\right)\)
\(=\dfrac{-10,5}{6}-\dfrac{13}{6}\)
\(=\dfrac{-23,5}{6}\)
\(=-\dfrac{47}{12}\)
TX
0
14 tháng 9 2021
\(=-\dfrac{7}{4}+\dfrac{1}{9}+\dfrac{37}{18}\\ =\dfrac{-63+4+37}{36}=\dfrac{-23}{36}\)
14 tháng 9 2021
\(-1,75-\left(-\dfrac{1}{9}-2\dfrac{1}{18}\right)=-\dfrac{7}{4}+\dfrac{1}{9}+\dfrac{37}{18}=\dfrac{\left(-7\right).9+4+37.2}{36}=\dfrac{5}{12}\)
YN
21 tháng 6 2022
Dấu "^" của cậu nghĩa là phân số?
\(a,-1,75-\left(-\dfrac{1}{9}-2\dfrac{1}{18}\right)=-\dfrac{7}{4}-\left(-\dfrac{2}{18}-\dfrac{37}{18}\right)=-\dfrac{7}{4}+\dfrac{13}{6}=\dfrac{5}{12}\)
\(b,-\dfrac{1}{12}-\left(2\dfrac{5}{8}-\dfrac{1}{3}\right)=-\dfrac{1}{12}-\dfrac{55}{24}=-\dfrac{19}{8}\)
\(c,-\dfrac{5}{6}-\left(-\dfrac{3}{8}+\dfrac{1}{30}\right)=-\dfrac{5}{6}+\dfrac{41}{120}=-\dfrac{59}{120}\)
T
7 tháng 7 2021
a) 3x – 6 + x(x – 2) = 0
=> 3x - 6 + x2 - 2x = 0
=> ( 3x - 2x ) - 6 + x2 = 0
=> x - 6 + x2 = 0
=> x2 + x = 6
=> x( x + 1 ) = 2 . 3
=> x = 2
T
7 tháng 7 2021
b) 2x(x – 3) – x(x – 6) – 3x = 0
=> 2x2 - 6x - x2 + 6x - 3x = 0
=> ( 2x2 - x2 ) + ( 6x - 6x ) - 3x = 0
=> x2 - 3x = 0
=> x( x - 3 ) = 0
\(\Rightarrow\orbr{\begin{cases}\text{x = 0}\\\text{x - 3 = 0}\end{cases}\Rightarrow\orbr{\begin{cases}\text{x = 0}\\\text{x = 3}\end{cases}}}\)
26 tháng 9 2020
Bài 1:
a) Ta có: \(\frac{3}{8}+\frac{-5}{6}\)
\(=\frac{3}{8}-\frac{5}{6}\)
\(=\frac{9}{24}-\frac{20}{24}\)
\(=-\frac{11}{24}\)
b) Ta có: \(\frac{15}{12}-\frac{-1}{4}\)
\(=\frac{15}{12}+\frac{1}{4}\)
\(=\frac{15}{12}+\frac{3}{12}\)
\(=\frac{18}{12}=\frac{3}{2}\)
Bài 2:
a) Ta có: \(-\frac{1}{12}-\left(2\frac{5}{8}-\frac{1}{3}\right)\)
\(=-\frac{1}{12}-\frac{21}{8}+\frac{1}{3}\)
\(=\frac{-2}{24}-\frac{63}{24}+\frac{8}{24}\)
\(=\frac{-57}{24}\)
\(=-\frac{19}{8}\)
b) Ta có: \(\frac{-5}{6}-\left(\frac{-3}{8}+\frac{1}{10}\right)\)
\(=\frac{-5}{6}+\frac{3}{8}-\frac{1}{10}\)
\(=\frac{-100}{120}+\frac{45}{120}-\frac{12}{120}\)
\(=\frac{-67}{120}\)
c) Ta có: \(-1.75-\left(\frac{-1}{9}-2\frac{1}{18}\right)\)
\(=-\frac{7}{4}+\frac{1}{9}+\frac{37}{18}\)
\(=\frac{-63}{36}+\frac{4}{36}+\frac{74}{36}\)
\(=\frac{15}{36}=\frac{5}{12}\)
25 tháng 3 2017
2) -12:\(\left(-\dfrac{5}{6}\right)^2\)=\(-12:\dfrac{25}{36}=-12\cdot\dfrac{36}{25}=-\dfrac{432}{25}\)
s) \(-\dfrac{1}{12}-\left(2\dfrac{5}{8}-\dfrac{1}{3}\right)=-\dfrac{1}{12}-\left(\dfrac{21}{8}-\dfrac{1}{3}\right)\)
= \(-\dfrac{1}{12}-\dfrac{55}{24}=-\dfrac{2}{24}-\dfrac{55}{24}=-\dfrac{57}{24}=-\dfrac{19}{8}\)
t) \(-1,75-\left(-\dfrac{1}{9}-2\dfrac{1}{18}\right)=-1,75-\left(-\dfrac{2}{18}-\dfrac{37}{18}\right)\)
= -1,75-(\(-\dfrac{13}{6}\)) = \(-\dfrac{7}{4}+\dfrac{13}{6}=\dfrac{5}{12}\)
c) \(\left(\sqrt{\dfrac{1}{9}}-0,5\right)^3+\dfrac{-1}{3}=\left(\dfrac{1}{3}-\dfrac{1}{2}\right)^3-\dfrac{1}{3}\)
= \(\left(-\dfrac{1}{6}\right)^3-\dfrac{1}{3}=\dfrac{-1}{216}-\dfrac{1}{3}=-\dfrac{73}{216}\)
d) \(\left(\dfrac{1}{2}-\sqrt{\dfrac{4}{25}}\right)^2-2\dfrac{1}{2}=\left(\dfrac{1}{2}-\dfrac{2}{5}\right)^2-\dfrac{5}{2}\)
= \(\left(\dfrac{1}{10}\right)^2-\dfrac{5}{2}=\dfrac{1}{100}-\dfrac{250}{100}=-\dfrac{249}{100}=-2,49\)
\(-1,75-\left(-\dfrac{1}{9}-2\dfrac{1}{18}\right)\)
\(=-1,75-\left(-\dfrac{1}{9}-\dfrac{37}{18}\right)\)
\(=-1,75-\left(-\dfrac{39}{18}\right)\)
\(=\dfrac{5}{12}\)