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a) \(A=\dfrac{1}{3}+\dfrac{1}{5}+\dfrac{1}{35}+\dfrac{1}{63}+\dfrac{1}{99}+\dfrac{1}{143}\)
\(A=\dfrac{1}{1.3}+\dfrac{1}{3.5}+\dfrac{1}{5.7}+\dfrac{1}{7.9}+\dfrac{1}{9.10}+\dfrac{1}{143}\)
\(A=\dfrac{1}{2}.\left(1-\dfrac{1}{3}+\dfrac{1}{3}-\dfrac{1}{5}+\dfrac{1}{5}-\dfrac{1}{7}+\dfrac{1}{7}-\dfrac{1}{9}+\dfrac{1}{9}-\dfrac{1}{10}\right)+\dfrac{1}{143}\)
\(A=\dfrac{1}{2}.\left(1-\dfrac{1}{100}\right)+\dfrac{1}{143}=\dfrac{1}{2}.\dfrac{99}{100}+\dfrac{1}{143}=\dfrac{99}{200}+\dfrac{1}{143}=\dfrac{99.143+200.1}{200.143}=\dfrac{14157+200}{28600}=\dfrac{14357}{28600}\)
b) \(x+\left(x+1\right)+\left(x+2\right)+...+\left(x+99\right)=14950\)
\(\Rightarrow x+x+...+x+\left(1+2+...+99\right)=14950\)
\(\Rightarrow100x+\left(\left(99+1\right):2\right).99:2=14950\)
\(\Rightarrow100x+2475=14950\Rightarrow100x=12475\Rightarrow x=\dfrac{12475}{100}=\dfrac{499}{4}\)
a: \(\Leftrightarrow n+2\in\left\{1;-1;5;-5\right\}\)
hay \(n\in\left\{-1;-3;3;-7\right\}\)
b: \(\Leftrightarrow n-1-2⋮n-1\)
\(\Leftrightarrow n-1\in\left\{1;-1;2;-2\right\}\)
hay \(n\in\left\{2;0;3;-1\right\}\)
c: \(\Leftrightarrow3n-6+8⋮n-2\)
\(\Leftrightarrow n-2\in\left\{1;-1;2;-2;4;-4;8;-8\right\}\)
hay \(n\in\left\{3;1;4;0;6;-2;10;-6\right\}\)
a) (−27). 1011 − 27. (−12) + 27. (−1)
= (-27). (1011 - 12 + 1)
= (-27). 1000 = -27 000
b) (−9). (−9). (−9) + 103 + 9.3
= (-9). 3 + 103 + 9.3
= 9.3 - 9.3 + 103
= 0 + 103 = 103
c) (−157). (127 − 316) − 127. (316 − 157)
= (-157). 127 - 316. (-157) - 127.316 - 127. (-157)
= (-157). 127 + 316. 157 - 127. 316 + 127.157
= (127.157 - 157.127) + (316. 157 - 127.316)
= 0 + (157 - 127). 316
= 0 + 30. 316
= 9480
1,
a,\(2020-\left(249+2020\right)+\left(249-573\right)\)
\(=2020-249-2020+249-573\)
\(=-573\)
b,\(\left|-257\right|+\left(-3\right)^0-\left(18+257\right)\)
\(=257+1-18-257\)
\(=1-18=-17\)
\(c,25.\left(85-47\right)-85.\left(47+25\right)\)
\(=25.85-25.47-47.85+85.25\)
\(=85.\left(25-47+25\right)-25.47\)
\(=85.3-25.47\)
\(=-920\)
2,
\(a,15-5.\left(x+2\right)=-30\)
\(=>5.\left(x+2\right)=15+30=45\)
\(=>x+2=\frac{45}{5}=9\)
\(=>x=7\)
\(b,\left(x+2\right)^2+5=105\)
\(=>\left(x+2\right)^2=100\)
\(=>\left(x+2\right)^2=10^2\)
\(=>x+2=10\)
\(=>x=8\)
\(c,\left|2x-5\right|-\left(-6\right)=11\)
\(=>\left|2x-5\right|=11-6=5\)
\(=>\orbr{\begin{cases}2x-5=5\\2x-5=-5\end{cases}}\)
\(=>\orbr{\begin{cases}2x=5-5=0\\2x=-5+5=0\end{cases}=>x=0}\)
Bài 1
a.\(\frac{-3}{4}\)-y:\(\frac{1}{5}\)=\(\frac{9}{28}\)
y:\(\frac{1}{5}\)=\(\frac{-15}{14}\)
y= \(\frac{-3}{14}\)
b.5x + 5x+2=650
5x . 1 + 5x + 52=650
5x(1+25)=650
5x.26=650
5x=25
x=2
249 - 95 x 8 + 32 x 4
=249-760+9x4
=249-760+36
=249+36-760
=285-760 không thuộc N
Vậy kết quả phép tính trên ko thuộc N.
Tick cho mik nhé!
Ta có:
\(3.9^{x+1}+6.9^{x-1}=249\\\Leftrightarrow3.9.9^x+6.9^x:9=249 \\ \Leftrightarrow27.9^x+\dfrac{2}{3}.9^x=249\\ \Leftrightarrow\left(27+\dfrac{2}{3}\right)9^x=249\\ \Leftrightarrow\dfrac{83}{3}.9^x=249\\ \Leftrightarrow9^x=249:\dfrac{83}{3}=9\\ \Rightarrow x=1\)
Đs...