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E = 1 x 1 + 2 x2 + 3 x 3 + . . . + 15 x 15
E = 1( 2 -1 ) + 2 ( 3 -1 ) + 3 ( 4-1 ) + . . . + 15 ( 16 -1 )
E = 1.2 -1 + 2.3 - 2 + 3.4 - 3 + . . . + 15 . 16 - 15
E = ( 1.2 + 2.3 + 3.4+ . . . + 15 .16 ) - ( 1 + 2 + 3 + . . . + 15 )
E = 1360- 120
E = 1240
Tk mk nha
S5=5x5-(4x4-(3x3-(2x2-1x1)))
S2011=2001x2001-(2000x2000-(1999x1999-(....)))
A=1x2+2x3+3x4+...+49x50
3A= 3(1.2+2.3+3.4+...+49.50)
3A= 1.2.3+2.3.3+3.4.3+...+49.50.3
3A= 1.2.(3-0)+2.3(4-1)+3.4(5-2)+...+49.50.(51-48)
3A= 0.1.2-1.2.3+1.2.3-2.3.4+2.3.4-3.4.5+...+48.49.50-49.50.51
3A= 49.50.51
A= 49.50.51/3=41650
B=1x3+3x5+5x7+...+99x101
B=1/1.3 +1/3.5 +...+1/99.101
2B=2/1.3 + 2/3.5 +...+2/99.101
2B=1-1/3+1/3-1/5+...+1/99-1/101
2B=1-1/101
2B=100/101
B=100/101:2=100/202
\(E=1.1+2.2+3.3+4.4+...+99.99\)
\(\Rightarrow E=1^2+2^2+3^2+4^2+...+99^2\)
\(\Rightarrow E=\dfrac{99.\left(99+1\right)\left(2.99+1\right)}{6}\)
\(\Rightarrow E=\dfrac{99.100.199}{6}\)
\(\Rightarrow E=33.50.199=328350\)
E = 1 x 1 + 2 x 2 + 3 x 3 + 4 x 4 +...+ 99 x 99
E = 1x(2-1) + 2 x (3-1)+...+ 99 x (100 -1)
D = 1 x 2 - 1 + 2 x 3 - 2 +...+ 99 x 100 - 99
D = 1x2 + 2 x 3 +...+ 99 x 100 - ( 1 + 2 +...+ 99)
Đặt A = 1x2 + 2 x 3 +...+ 99 x 100
B = 1 + 2 + ...+ 99
1x2 x 3 = 1x2x3
2x3x3 = 2x 3 x (4-1) = 2x3x4 - 1x2x3
3 x 4 x 3 = 3 x 4 x ( 5 - 2) = 3 x 4 x 5 - 2 x 3 x 4
................................................
99 x 100 x 3 = 99 x 100 x (101 - 98) = 99x100x101 - 98 x 99 x 100
Cộng vế với vế ta có: 3A = 99 x 100 x 101
A = 99 x 100 x 101 : 3 = 333300
B = 1 + 2 + 3 + ...+ 99
B = (99 + 1).[(99 -1):1 +1]:2 = 4950
E = 33300 - 4950 = 328350
= 1.1! + (3 - 1).2! + (4 - 1).3! + ...+ (16 - 1).15!
= 1! + 3.2! - 2! + 4.3! - 3! + ...+16.15! - 15!
= 1! + 3! - 2! + 4! - 3! + ...+16! - 15!
= 1! + (3! + 4! + ...+ 16!) - (2! + 3! + ...+ 15!)
= 1 + 16! - 2! = ....
Ta có: 1x1!+2x2!+......+15x15!
= 1.1! + (3 - 1).2! + (4 - 1).3! + ...+ (16 - 1).15!
= 1! + 3.2! - 2! + 4.3! - 3! + ...+16.15! - 15!
= 1! + 3! - 2! + 4! - 3! + ...+16! - 15!
= 1! + (3! + 4! + ...+ 16!) - (2! + 3! + ...+ 15!)
= 1 + 16! - 2!
Vậy ...............
hok tốt
\(E=1\cdot1+2\cdot2+3\cdot3+...+15\cdot15\)
\(=1\cdot\left(2-1\right)+2\cdot\left(3-1\right)+3\cdot\left(4-1\right)+...+15\cdot\left(16-1\right)\)
\(=1\cdot2-1+2\cdot3-2+3\cdot4-3+...+15\cdot16-15\)
\(=\left(1\cdot2+2\cdot3+3\cdot4+...+15\cdot16\right)-\left(1+2+3+...+15\right)\)
\(=1360-120=1240\)