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a)\(=-\sqrt{\left(\frac{a}{b}\right)^2\cdot\frac{b}{a}}\)
\(=-\sqrt{\frac{a^2}{b^2}\cdot\frac{b}{a}}\)
\(=-\sqrt{\frac{a}{b}}\)
a, \(\sqrt{\frac{\left(x-y\right)^2}{x^2}\cdot\frac{x}{x-y}}=\) \(\frac{x-y}{x}\)
b. \(\sqrt{\frac{\left(x+y\right)^2}{\left(x-y\right)^2}\cdot\frac{x-y}{x+y}}=\sqrt{\frac{x+y}{x-y}}\)
c.\(\sqrt{\frac{x^4}{\left(x-5\right)^2}\cdot\frac{x-5}{3x}}=\sqrt{\frac{x^3}{3\left(x-5\right)}}\)
\(-2\sqrt{-a}=\sqrt{\left(-2\right)^2\cdot-a}=\sqrt{-4a}\)
a) \(\sqrt{27x^2}=\sqrt{3.\left(3x\right)^2}=\left|3x\right|.\sqrt{3}=3x\sqrt{3}\left(x>0\right)\)
b) \(\sqrt{8xy^2}=\left|y\right|.2\sqrt{2x}=-2y\sqrt{2x}\left(x\ge0,y\le0\right)\)
1) \(x\sqrt{13}=\sqrt{13x^2}\left(x\ge0\right)\)
2) \(x\sqrt{-15x}=-\left|x\right|\sqrt{15x}=-\sqrt{15x^3}\left(x< 0\right)\)
3) \(x\sqrt{2}=-\left|x\right|\sqrt{2}=-\sqrt{2x^2}\left(x\le0\right)\)
a) \(\sqrt{25\cdot96}=\sqrt{5^2\cdot2^5\cdot3}=\sqrt{5^2\cdot\left(2^2\right)^2\cdot2\cdot3}\)
\(=20\sqrt{6}\)
b) \(\sqrt{21\cdot75\cdot14}=\sqrt{2\cdot3^2\cdot5^2\cdot7^2}=105\sqrt{2}\)
c) \(y^2\sqrt{x^6\cdot y^8}=\sqrt{x^6\cdot y^4\cdot y^8}=\sqrt{\left(x^3\right)^2\cdot\left(y^6\right)^2}=x^3\cdot y^6\)
hì,giúp bn đc phần a thôi nha!!!
\(a,\sqrt{25.96}=\sqrt{25.16.6}=\sqrt{25}.\sqrt{16}.\sqrt{6}=5.4.\sqrt{6}=20\sqrt{6}\)
=.= hok tốt!!!
Sai rồi nha bae , ĐKXĐ là \(\hept{\begin{cases}y\ne0\\y\ne\pm5\end{cases}}\)nha nên dẫn đến đáp án sai luôn
\(\left(x-5\right)\sqrt{\frac{3}{25-x^2}}=\sqrt{\left(x-5\right)^2}\sqrt{\frac{3}{\left(5-x\right)\left(x+5\right)}}=\sqrt{\left(5-x\right)^2.\frac{3}{\left(5-x\right)\left(x+5\right)}}=\sqrt{\frac{3\left(5-x\right)}{x+5}}\)
a) \(\sqrt{49.360}=\sqrt{7^2.6^2.10}=7.6\sqrt{10}=42\sqrt{10}\)
b) \(-\sqrt{500.162}=-\sqrt{\left(2^2.5^2.5\right).\left(2.3^2.3^2\right)}\)
\(=-2.5.3.3\sqrt{5.2}=-90\sqrt{10}\)
c) \(\sqrt{125a^2}=\sqrt{5^2.a^2.5}=5\left|a\right|\sqrt{5}=-5a\sqrt{5}\) (do a <0)
d) \(\frac{1}{3}\sqrt{225a^2}=\frac{1}{3}\sqrt{15^2.a^2}=\frac{15}{3}\left|a\right|=5\left|a\right|\)
a < 0 thì suy ra \(\frac{1}{3}\sqrt{225a^2}=\frac{1}{3}\sqrt{15^2.a^2}=\frac{15}{3}\left|a\right|=5\left|a\right|=-5a\)
a>=0 thì suy ra \(\frac{1}{3}\sqrt{225a^2}=\frac{1}{3}\sqrt{15^2.a^2}=\frac{15}{3}\left|a\right|=5\left|a\right|=5a\)
d) \(\dfrac{1}{3}\sqrt{225a^2}=\dfrac{1}{3}\sqrt{\left(15a\right)^2}=\dfrac{1}{3}\left|15a\right|=\left|5a\right|\)
\(\Rightarrow\left[{}\begin{matrix}a>0\Rightarrow d=5a\\a< 0\Rightarrow d=-5a\end{matrix}\right.\)
Giải:
a) \(\sqrt{49.360}\)
\(=\sqrt{7^2.3^2.2^2.10}\)
\(=7.3.2\sqrt{10}\)
\(=42\sqrt{10}\)
Vậy ...
b) \(-\sqrt{500.162}\)
\(=-\sqrt{10^2.5.9^2.2}\)
\(=-10.9\sqrt{10}\)
\(=-90\sqrt{10}\)
Vậy ...
c) \(\sqrt{125a^2}\)
\(=\sqrt{5^2.5.a^2}\)
\(=\sqrt{5^2.5.\left(-a\right)^2}\)
\(=-5a\sqrt{5}\)
Vậy ...
d) \(\dfrac{1}{3}\sqrt{225.a^2}\)
\(=\dfrac{1}{3}\sqrt{15^2.a^2}\)
\(=\dfrac{1}{3}.15.a^2\)
\(=5a^2\)
Vậy ...
5 y y = ( 5 y ) 2 . y = 25. y 2 . y = 25. y 3
Chọn đáp án D