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\(\frac{8}{5}-\frac{18}{27}\)
\(=\frac{8}{5}-\frac{2}{3}\)
\(=\frac{24}{15}-\frac{10}{15}\)
\(=\frac{14}{15}\)
\(\frac{12}{20}-\frac{6}{18}\)
\(=\frac{3}{5}-\frac{1}{3}\)
\(=\frac{9}{15}-\frac{5}{15}\)
\(=\frac{4}{15}\)
\(\frac{8}{24}-\frac{5}{25}\)
\(=\frac{1}{3}-\frac{1}{5}\)
\(=\frac{5}{15}-\frac{3}{15}\)
\(=\frac{2}{15}\)
\(\frac{18}{21}-\frac{12}{27}\)
\(=\frac{6}{7}-\frac{4}{9}\)
\(=\frac{54}{63}-\frac{28}{63}\)
\(=\frac{26}{63}\)
1)8/5-2/3=14/15
2)3/5-1/3=4/15
3)1/3-1/5=2/15
4)6/7-4/9=26/63
\(1-\left(\frac{12}{5}+y=\frac{8}{9}\right):\frac{16}{9}=0\)
\(1-\left(\frac{12}{5}+y-\frac{8}{9}\right)=0\times\frac{16}{9}\)
\(1-\left(\frac{12}{5}+y-\frac{8}{9}\right)=0\)
\(\frac{12}{5}+y-\frac{8}{9}=1-0\)
\(\frac{12}{5}-y+\frac{8}{9}=1\)
\(\frac{12}{5}-y=1-\frac{8}{9}\)
\(\frac{12}{5}-y=\frac{1}{9}\)
\(y=\frac{12}{5}-\frac{1}{9}\)
\(y=\frac{108}{45}-\frac{5}{45}\)
\(y=\frac{103}{45}\)
a) $\frac{{14}}{{18}}:\frac{8}{9} = \frac{7}{9}:\frac{8}{9} = \frac{7}{9} \times \frac{9}{8} = \frac{{63}}{{72}} = \frac{7}{8}$
b) $\frac{9}{6}:\frac{3}{{10}} = \frac{3}{2}:\frac{3}{{10}} = \frac{3}{2} \times \frac{{10}}{3} = \frac{{30}}{6} = 5$
c) $\frac{4}{5}:\frac{{10}}{{15}} = \frac{4}{5}:\frac{2}{3} = \frac{4}{5} \times \frac{3}{2} = \frac{{12}}{{10}} = \frac{6}{5}$
d) $\frac{1}{6}:\frac{{21}}{9} = \frac{1}{6}:\frac{7}{3} = \frac{1}{6} \times \frac{3}{7} = \frac{3}{{42}} = \frac{1}{{14}}$
a) \(A=\frac{27\text{x}45+27\text{x}25}{2+4+6+8+...+18}=\frac{27\left(45+25\right)}{\left(18+2\right)\text{x}\left(\frac{18-2}{2}+1\right)}\)
\(A=\frac{27\text{x}70}{20\text{x}9}=\frac{3\text{x}9\text{x}10\text{x}7}{10\text{x}2\text{x}9}\)
\(A=\frac{21}{2}\)
b) \(B=\frac{28\text{x}108-52\text{x}12}{32-28+24-20+16-12+8-4}\)
\(B=\frac{28\text{x}12\text{x}9\text{}\text{}-52\text{x}12}{\left(32-28\right)+\left(24-20\right)+\left(16-12\right)+\left(8-4\right)}\)
\(B=\frac{12\left(28\text{x}9-52\right)}{4+4+4+4}=\frac{12\text{x}200}{4\text{x}4}\)
\(B=\frac{4\text{x}3\text{x}4\text{x}50}{4\text{x}4}=150\)
a) \(\frac{8}{5}-\frac{18}{27}=\frac{8}{5}-\frac{2}{3}\)
\(\Rightarrow\frac{8}{5}-\frac{2}{3}=\frac{24}{15}-\frac{10}{15}\)
\(\Rightarrow\frac{14}{15}\)
b) \(\frac{18}{21}-\frac{12}{27}=\frac{6}{7}-\frac{4}{9}\)
\(\Rightarrow\frac{6}{7}-\frac{4}{9}=\frac{54}{63}-\frac{28}{63}\)
\(\Rightarrow\frac{26}{63}\)
c) \(\frac{8}{24}-\frac{5}{25}=\frac{1}{3}-\frac{1}{5}\)
\(\Rightarrow\frac{1}{3}-\frac{1}{5}=\frac{5}{15}-\frac{3}{15}\)
\(\Rightarrow\frac{2}{15}\)
d) \(\frac{12}{20}-\frac{6}{18}=\frac{3}{5}-\frac{1}{3}\)
\(\Rightarrow\frac{3}{5}-\frac{1}{3}=\frac{9}{15}-\frac{5}{15}\)
\(\Rightarrow\frac{4}{15}\)
ta có: \(\frac{12}{27}=\frac{4}{9}\)
mà\(\frac{25}{45}=\frac{5}{9};\frac{20}{45}=\frac{4}{9};\frac{40}{42}=\frac{20}{21};\frac{32}{72}=\frac{4}{9};\frac{15}{27}=\frac{5}{9}\)
\(\Rightarrow\frac{12}{27}=\frac{20}{45}=\frac{32}{72}\left(=\frac{4}{9}\right)\)
CHÚC BN HỌC TỐT!
\(\frac{1995.1993-18}{1975.1993.1994}\)\(=\frac{1995-18}{1975.1994}\)
\(=\frac{1977}{1975.1994}\)
\(=\frac{1975+2}{1975.1994}\)
\(=\frac{2}{1994}=\frac{1}{997}\)
\(\frac{1996.1995-996}{1000+1996.1994}\)\(=\frac{1995-996}{1994+1000}\)
\(=\frac{999}{1994+1000}\)
\(=\frac{999}{1994+999+1}\)
\(=\frac{1}{1994+1}=\frac{1}{1995}\)
35/27 x 18/49 = 35x18/27x49 = 630/1323 = 10/21
18/25 x 36/125 = 18x36/25x125 = 648/3125
mình ko bt đúng ko nữa nếu sai thì thông cảm nha
các bạn có cách nào mà làm mẫu số chung nhỏ nhất mà ko cần rút gọn được ko
\(=\dfrac{4}{9}+\dfrac{4}{9}=\dfrac{8}{9}\)
4/9 + 4/9 = 8/9