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NC
16 tháng 7 2018
\(\frac{6^3+3.6^2+3}{-13}\)
\(=\frac{216+108+27}{-13}\)
\(=\frac{351}{-13}\)
\(=-27\)
6 tháng 12 2022
Bài 2:
1: =>5x+1=6/7 hoặc 5x+1=-6/7
=>5x=-1/7 hoặc 5x=-13/7
=>x=-1/35 hoặc x=-13/35
2: =>x-1=4
=>x=5
3: =>3x-1=3
=>3x=4
=>x=4/3
4: \(\Leftrightarrow\dfrac{5}{x+3}=\dfrac{-5}{6}+\dfrac{1}{2}=\dfrac{-5+3}{6}=\dfrac{-2}{6}=\dfrac{-1}{3}\)
=>x+3=-15
=>x=-18
7: \(\Leftrightarrow2^{2x+1}+2^{2x+6}=264\)
=>2^2x+1*(1+2^5)=264
=>2^2x+1=8
=>2x+1=3
=>x=1
9: =>x^4=8x
=>x^4-8x=0
=>x=2
DD
5
BA
24 tháng 9 2019
\(\frac{6^3+3\cdot6^2+3^3}{-13}\)
\(=\frac{6^2\cdot\left(6+3\right)+3^3}{-13}\)
\(=\frac{6^2\cdot3^2+3^3}{-13}\)
\(=\frac{3^3\cdot\left(6^2+3\right)}{-13}\)
\(=\frac{3^3\cdot39}{-13}\)
\(=-3^3=-27\)
31 tháng 7 2017
a) \(\frac{4^2.4^3}{2^{10}}\)\
\(=\frac{4^5}{\left(2^2\right)^{10}}=\frac{4^5}{4^{10}}=\frac{1}{4^5}\)
b) \(\frac{0,6^5}{0,2^6}=\frac{\left(0,2.3\right)^5}{0,2^6}=\frac{0,2^5.3^5}{0,2^6}=\frac{3^5}{0,2}=5.3^5\)
HN
1
14 tháng 8 2016
\(\frac{6^3+3.6^2+3^2}{-13}\)
\(=\frac{\left(2.3\right)^3+3.\left(2.3\right)^2+3^2}{-13}\)
\(=\frac{2^3.3^3+\left(3.3^2\right).2+3^2}{-13}\)
\(=\frac{3^2.\left(2^3.3+3.2+1\right)}{-13}\)
\(=\frac{3^2.31}{-13}\)
\(=\frac{9.31}{-13}\)
\(=\frac{273}{-13}\)
\(=-21\)
10 tháng 11 2018
a) \(\dfrac{-3}{5}.51\dfrac{11}{13}+\dfrac{3}{5}.21\dfrac{11}{13}\)
\(=\dfrac{-3}{5}.\left(51\dfrac{11}{13}-21\dfrac{11}{13}\right)\)
\(=\dfrac{-3}{5}.30\)
\(=-18.\)
b) \(\left|\dfrac{-3}{4}\right|.\left|-\dfrac{2}{3}\right|=\dfrac{3}{4}.\dfrac{2}{3}=\dfrac{1}{2}\).
c) \(\dfrac{-3}{5}+5\dfrac{1}{13}-\dfrac{2}{3}+1\dfrac{3}{5}-\dfrac{11}{33}\)
\(=\left(1\dfrac{3}{5}-\dfrac{3}{5}\right)+5\dfrac{1}{13}-\left(\dfrac{2}{3}+\dfrac{11}{33}\right)\)
\(=1+\dfrac{66}{13}-1\)
\(=\dfrac{66}{13}.\)
d) \(\dfrac{3}{4}.\sqrt{16}-10.\sqrt{0,81}\)
\(=\dfrac{3}{4}.4-10.\dfrac{9}{10}\)
\(=3.9\)
\(=27.\)
e) \(\left(\dfrac{3}{4}\right)^3:\left(\dfrac{-3}{8}\right)^3=\dfrac{3^3}{4^3}.\dfrac{\left(-8\right)^3}{3^3}=\left(\dfrac{-8}{4}\right)^3=\left(-2\right)^3=-8\)
f) \(\dfrac{6^4.15^3}{8.9^3.10^3}=\dfrac{2^4.3^4.3^3.5^3}{2^3.3^6.2^3.5^3}=\dfrac{2.3^7}{2^3.3^6}=\dfrac{3}{2^2}=\dfrac{3}{4}.\)
8 tháng 12 2022
Bài 2:
a: =>x^2=60
=>\(x=\pm2\sqrt{15}\)
b: =>2^2x+3=2^3x
=>3x=2x+3
=>x=3
c: \(\Leftrightarrow\sqrt{\dfrac{1}{2}x-2}\cdot\dfrac{1}{2}=1\)
\(\Leftrightarrow\sqrt{\dfrac{1}{2}x-2}=2\)
=>1/2x-2=4
=>1/2x=6
=>x=12
\(\dfrac{6^3+3.6^2+3^3}{-13}\)=\(\dfrac{3^3.2^3+3.2^2.3^2+3^3}{-13}\)=\(\dfrac{3^3\left(2^3+2^2+1\right)}{-13}\)
=\(\dfrac{3^3.13}{-13}\)=\(-3^3\)=\(-27\)