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19 tháng 9 2018
\(\frac{2^{11}\cdot9^2}{3^5\cdot16^2}\)
\(=\frac{2^{11}\cdot3^4}{3^5\cdot2^8}\)
\(=\frac{2^3}{3}\)
\(=\frac{8}{3}\)
17 tháng 8 2018
a) \(k=\frac{2^{11}.9^2}{3^5.16^2}=\frac{2^{11}.\left(3^2\right)^2}{3^5.\left(2^4\right)^2}=\frac{2^{11}.3^4}{3^5.2^8}=\frac{8.1}{3.1}=\frac{8}{3}\)
17 tháng 8 2018
b) \(N=\frac{9^3.27^2}{6^2.3^{10}}=\frac{\left(3^2\right)^3.\left(3^3\right)^2}{\left(2.3\right)^2.3^{10}}=\frac{3^6.3^6}{2^2.3^2.3^{10}}=\frac{3^{12}}{4.3^{12}}=\frac{1}{4}\)
30 tháng 7 2015
a) \(K=\frac{2^{11}\cdot9^2}{3^5\cdot16^2}=\frac{2^{11}\cdot3^4}{3^5\cdot2^8}=\frac{2^3}{3}=\frac{8}{3}\)
b) \(N=\frac{9^3\cdot27^2}{6^2\cdot3^{10}}=\frac{3^6\cdot3^6}{2^2\cdot3^2\cdot3^{10}}=\frac{1}{4}\)
c) \(P=\frac{27^{15}\cdot5^3\cdot8^4}{25^2\cdot81^{11}\cdot2^{11}}=\frac{3^{45}\cdot5^3\cdot2^{12}}{5^4\cdot3^{44}\cdot2^{11}}=\frac{3\cdot2}{5}=\frac{6}{5}\)
22 tháng 10 2017
\(\dfrac{\dfrac{2}{3}-\dfrac{2}{5}+\dfrac{2}{9}+\dfrac{2}{13}}{\dfrac{11}{3}-\dfrac{11}{5}+\dfrac{11}{9}+\dfrac{11}{13}}\)
\(=\dfrac{2\cdot\left(\dfrac{1}{3}-\dfrac{1}{5}+\dfrac{1}{9}+\dfrac{1}{13}\right)}{11\cdot\left(\dfrac{1}{3}-\dfrac{1}{5}+\dfrac{1}{9}+\dfrac{1}{13}\right)}\)
\(=\dfrac{2}{11}\)
19 tháng 6 2018
8)\(\frac{4}{9}:\left(-\frac{1}{7}\right)+6\frac{5}{9}:\left(-\frac{1}{7}\right)\)
=\(\frac{4}{9}:\left(-\frac{1}{7}\right)+\frac{59}{9}:\left(-\frac{1}{7}\right)\)
=\(\left(\frac{4}{9}+\frac{59}{9}\right).\left(-7\right)\)
=7.(-7)
=-49
9 tháng 11 2018
a.\(\dfrac{17}{15}\div\dfrac{4}{3}=\dfrac{17}{20}\)
b.\(\dfrac{-12}{21}\div\dfrac{34}{43}=\dfrac{-86}{119}\)
c.\(\dfrac{-5}{9}\times\dfrac{3}{11}+\dfrac{13}{18}\times\dfrac{3}{11}\)
=\(\dfrac{3}{11}\times(\dfrac{-5}{9}+\dfrac{13}{18})=\dfrac{3}{11}\times\dfrac{1}{6}=\dfrac{1}{22}\)
d.\(\dfrac{-2}{9}\times\dfrac{5}{11}+\dfrac{-16}{9}\times\dfrac{5}{11}=\dfrac{5}{11}\times(\dfrac{-2}{9}+\dfrac{-16}{9})\)
=\(\dfrac{5}{11}\times(-2)=\dfrac{-10}{11}\)
DH
6 tháng 7 2017
a, \(\dfrac{2}{3}-4\left(\dfrac{1}{2}+\dfrac{3}{4}\right)=\dfrac{2}{3}-4.\dfrac{5}{4}=\dfrac{2}{3}-5=-\dfrac{13}{3}\)
b, \(-\dfrac{2}{3}.\dfrac{3}{11}+\dfrac{-16}{9}.\dfrac{3}{11}=\dfrac{3}{11}.\left(-\dfrac{2}{3}+\dfrac{-16}{9}\right)\)
\(=\dfrac{3}{11}.\dfrac{-22}{9}=-\dfrac{2}{3}\)
Câu c lấy máy tính tính nha!
c,
QD
6 tháng 7 2017
c) \(\dfrac{11}{125}-\dfrac{17}{18}-\dfrac{5}{7}+\dfrac{4}{9}+\dfrac{17}{14}\)
\(=\dfrac{11}{125}-\dfrac{17}{18}-\dfrac{10}{14}+\dfrac{8}{18}+\dfrac{17}{14}\)
\(=\dfrac{11}{125}+\left(-\dfrac{17}{18}+\dfrac{8}{18}\right)+\left(-\dfrac{10}{14}+\dfrac{17}{14}\right)\)
\(=\dfrac{11}{125}+\left(-\dfrac{9}{18}\right)+\dfrac{7}{14}\)
\(=\dfrac{11}{125}+\left(-\dfrac{1}{2}\right)+\dfrac{1}{2}\)
\(=\dfrac{11}{125}+0=\dfrac{11}{125}\)
TH
30 tháng 8 2018
\(5\dfrac{1}{2}+\left(-3\right)4\dfrac{9}{11}+\left(-2\dfrac{1}{11}\right)2\dfrac{1}{2}+\left(-6\right)\left(-\dfrac{4}{5}\right)+\dfrac{1}{2}\)
\(=\dfrac{11}{2}+\left(-3\right).\dfrac{53}{11}+\left(-\dfrac{23}{11}\right).\dfrac{5}{2}+\dfrac{24}{5}+\dfrac{1}{2}\)
\(=\dfrac{11}{2}+\left(-\dfrac{159}{11}\right)+\left(-\dfrac{115}{22}\right)+\dfrac{24}{5}+\dfrac{1}{2}\)
\(=\left(\dfrac{11}{2}+\dfrac{1}{2}\right)+\left(-\dfrac{318}{22}\right)+\left(-\dfrac{115}{22}\right)+\dfrac{24}{5}\)
\(=\dfrac{12}{2}+\left(-\dfrac{433}{22}\right)+\dfrac{24}{5}\)
\(=-\dfrac{977}{110}\)
C
30 tháng 8 2018
\(5\dfrac{1}{2}+\left(-3\right).4\dfrac{9}{11}+\left(-2\dfrac{1}{11}\right).2\dfrac{1}{2}+\left(-6\right).\left(-\dfrac{4}{5}\right)+\dfrac{1}{2}\)
\(=\dfrac{11}{2}+\left(-3\right).\dfrac{53}{11}+\left(-\dfrac{23}{11}\right).\dfrac{5}{2}+\left(-6\right).\left(-\dfrac{4}{5}\right)+\dfrac{1}{2}\)
\(=\dfrac{11}{2}+\left(-14\dfrac{5}{11}\right)+\left(-5\dfrac{5}{22}\right)+4\dfrac{4}{5}+\dfrac{1}{2}\)
\(=\dfrac{11}{2}+\left(-\dfrac{159}{11}\right)+\left(-\dfrac{115}{22}\right)+\dfrac{24}{5}+\dfrac{1}{2}\)
\(=\dfrac{11}{2}+\left(-\dfrac{318}{22}\right)+\left(-\dfrac{115}{22}\right)+\dfrac{24}{5}+\dfrac{1}{2}\)
\(=\left(\dfrac{11}{2}+\dfrac{1}{2}\right)+\left[\left(-\dfrac{318}{22}\right)+\left(-\dfrac{115}{22}\right)\right]+\dfrac{24}{5}\)
\(=\dfrac{11+1}{2}+\dfrac{\left(-318\right)+\left(-115\right)}{22}+\dfrac{24}{5}\)
\(=\dfrac{12}{2}+\left(-\dfrac{433}{22}\right)+\dfrac{24}{5}\)
\(=-8\dfrac{97}{110}=-\dfrac{977}{110}\)
TH
20 tháng 6 2018
a/Ta có: \(\dfrac{4}{3}-\left[\left(\dfrac{-11}{6}\right)-\left(\dfrac{2}{9}+\dfrac{5}{3}\right)\right]\)
\(=\) \(\dfrac{4}{3}-\left[\dfrac{-11}{6}-\dfrac{2}{9}-\dfrac{5}{3}\right]\)
\(=\) \(\dfrac{4}{3}+\dfrac{11}{6}+\dfrac{2}{9}+\dfrac{5}{3}\)
\(=\) \(\dfrac{24}{18}+\dfrac{33}{18}+\dfrac{4}{18}+\dfrac{30}{18}\)
\(=\) \(\dfrac{91}{18}\)
b/Ta có: \(\left(8-\dfrac{9}{4}+\dfrac{2}{7}\right)-\left(-6-\dfrac{3}{7}+\dfrac{5}{4}\right)-\left(3+\dfrac{2}{4}-\dfrac{9}{7}\right)\)
\(=\) \(8-\dfrac{9}{4}+\dfrac{2}{7}+6+\dfrac{3}{7}-\dfrac{5}{4}-3-\dfrac{2}{4}+\dfrac{9}{7}\)
\(=\) \(8+6-3-\dfrac{9}{4}-\dfrac{5}{4}-\dfrac{2}{4}+\dfrac{2}{7}+\dfrac{3}{7}+\dfrac{9}{7}\)
\(=\) \(11-\dfrac{2}{4}+\dfrac{14}{7}\)
\(=\) \(11-\dfrac{1}{2}+2\)
\(=\) \(9-\dfrac{1}{2}\)
\(=\) \(\dfrac{17}{2}\)
Chúc bn học tốt!!!
\(\dfrac{2^{11}.9^2}{3^5.16^2}\)
= \(\dfrac{2^{11}.3^4}{3^5.2^8}\)
= \(\dfrac{2^3}{3}\)= \(\dfrac{8}{3}\)= 2, (6)