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\(\dfrac{-12}{13}\)X-5=6\(\dfrac{1}{13}\)
\(\dfrac{-12}{13}\)X-5=\(\dfrac{79}{13}\)
X-5=\(\dfrac{79}{13}\): \(\dfrac{-12}{13}\)
X-5=\(\dfrac{79}{13}\)x\(\dfrac{-13}{12}\)
X-5=\(\dfrac{-1027}{156}\)
X-5=\(\dfrac{-79}{12}\)
X =\(\dfrac{-79}{12}\)+5
X =\(\dfrac{-79}{12}\)+\(\dfrac{60}{12}\)
X = \(\dfrac{-19}{12}\)
X = -1\(\dfrac{7}{12}\)
Mình giải rõ ràng vì sợ bạn không hiểu nên hơi dài bạn thông cảm nha.
= -12/13x-5 = 79/13
=-12/13x=79/13+5
=-12/13x=144/13
x= 144/13 : -12/13
x= 144/13 . ( -13/12 )
x= -12
Vậy x=-12
b, \(-x-2=\dfrac{5}{4}\Rightarrow-x=\dfrac{13}{4}\Rightarrow x=-\dfrac{13}{4}\)
c, \(\dfrac{4}{3}-\left(x-\dfrac{1}{5}\right)=\left|-\dfrac{3}{10}+\dfrac{1}{2}\right|-\dfrac{1}{6}\)
\(\Rightarrow\dfrac{4}{3}-x+\dfrac{1}{5}=\left|\dfrac{1}{5}\right|-\dfrac{1}{6}\)
\(\Rightarrow-x=\dfrac{1}{5}-\dfrac{1}{6}-\dfrac{4}{3}-\dfrac{1}{5}\)
\(\Rightarrow-x=-\dfrac{3}{2}\Rightarrow x=\dfrac{3}{2}\)
d, \(\dfrac{1}{3}-\left(\dfrac{2}{3}-x+\dfrac{5}{4}\right)=\dfrac{7}{12}-\left(\dfrac{5}{2}-\dfrac{13}{6}\right)\)
\(\Rightarrow\dfrac{1}{3}-\dfrac{2}{3}+x-\dfrac{5}{4}=\dfrac{7}{12}-\dfrac{5}{2}+\dfrac{13}{6}\)
\(\Rightarrow x=\dfrac{7}{12}-\dfrac{5}{2}+\dfrac{13}{6}-\dfrac{1}{3}+\dfrac{2}{3}+\dfrac{5}{4}\)
\(\Rightarrow x=\dfrac{11}{6}\)
Chúc bạn học tốt!!!
1: \(\Leftrightarrow3x+4=2\)
=>3x=-2
=>x=-2/3
2: \(\Leftrightarrow7x-7=6x-30\)
=>x=-23
3: =>\(5x-5=3x+9\)
=>2x=14
=>x=7
4: =>9x+15=14x+7
=>-5x=-8
=>x=8/5
a, \(\dfrac{3}{4}+x=\dfrac{8}{13}\)
\(x=\dfrac{8}{13}-\dfrac{3}{4}\)
\(x=-\dfrac{7}{52}\)
b,\(\dfrac{11}{12}-\left(\dfrac{2}{5}+x\right)=\dfrac{2}{3}\)
\(\dfrac{2}{5}+x=\dfrac{11}{12}-\dfrac{2}{3}\)
\(\dfrac{2}{5}+x=\dfrac{1}{4}\)
\(x=\dfrac{1}{4}-\dfrac{2}{5}\)
\(x=-\dfrac{3}{20}\)
c, \(2x\left(x-\dfrac{1}{7}\right)=0\)
\(2x-\dfrac{1}{7}=0\)
\(x-\dfrac{1}{7}=0:2\)
\(x-\dfrac{1}{7}=0\)
\(x=0-\dfrac{1}{7}\)
\(x=\dfrac{1}{7}\)
d, \(\dfrac{3}{4}+\dfrac{1}{4}\div x=\dfrac{2}{5}\)
\(\left(\dfrac{3}{4}+\dfrac{1}{4}\right):x=\dfrac{2}{5}\)
\(1:x=\dfrac{2}{5}\)
\(x=1:\dfrac{2}{5}\)
\(x=\dfrac{5}{2}\)
a) \(\dfrac{3}{4}+x=\dfrac{8}{13}\)\(\Leftrightarrow\) \(x=\dfrac{8}{13}-\dfrac{3}{4}=\dfrac{-7}{52}\) vậy \(x=\dfrac{-7}{52}\)
b) \(\dfrac{11}{12}-\left(\dfrac{2}{5}+x\right)=\dfrac{2}{3}\) \(\Leftrightarrow\) \(\dfrac{11}{12}-\dfrac{2}{5}-x=\dfrac{2}{3}\) \(\Leftrightarrow\) \(x=\dfrac{11}{12}-\dfrac{2}{5}-\dfrac{2}{3}=\dfrac{-3}{20}\) vậy \(x=\dfrac{-3}{20}\)
c) \(2x\left(x-\dfrac{1}{7}\right)=0\) \(\Leftrightarrow\) \(2x^2-\dfrac{2}{7}x=0\)
\(\Delta\) = \(\left(\dfrac{-2}{7}\right)^2-4.2.0=\dfrac{4}{49}>0\)
\(\Rightarrow\) phương trình có 2 nghiệm phân biệt
\(x_1=\dfrac{\dfrac{2}{7}+\sqrt{\dfrac{4}{49}}}{4}=\dfrac{1}{7}\)
\(x_2=\dfrac{\dfrac{2}{7}-\sqrt{\dfrac{4}{49}}}{4}=0\)
vậy \(x=0;x=\dfrac{1}{7}\)
1)
a.\(\dfrac{1}{5}+x=\dfrac{13}{50}\)
\(\Leftrightarrow x=\dfrac{13}{50}-\dfrac{1}{5}=\dfrac{13-10}{50}=\dfrac{3}{50}\)
b.\(\dfrac{1}{6}-x=\dfrac{5}{12}\)
\(\Leftrightarrow x=\dfrac{1}{6}-\dfrac{5}{12}=\dfrac{2-5}{12}=-\dfrac{3}{12}=-\dfrac{1}{4}\)
c.\(x\left(-\dfrac{1}{2}\right)^2=\dfrac{1}{16}\)
\(\Leftrightarrow x\left(-\dfrac{1}{2}\right)^2=\dfrac{1}{4}.\left(-\dfrac{1}{2}\right)^2\)
\(\Leftrightarrow x=\dfrac{1}{4}\)
d.\(x:\dfrac{7}{11}=\dfrac{9}{33}\)
\(\Leftrightarrow x=\dfrac{9}{33}.\dfrac{7}{11}=\dfrac{3}{11}.\dfrac{7}{11}=\dfrac{21}{121}\)
e.\(\dfrac{3}{5}.x=-\dfrac{21}{10}\)
\(\Leftrightarrow x=-\dfrac{21}{10}:\dfrac{3}{5}=-\dfrac{21}{10}.\dfrac{5}{3}=-\dfrac{7}{2}\)
a. \(\left(\dfrac{1}{2}+1,5\right)x=\dfrac{1}{5}\Rightarrow2x=\dfrac{1}{5}\Rightarrow x=\dfrac{1}{5}:2=0,1\)
Vậy \(x=0,1\)
b. \(\left(-1\dfrac{3}{5}+x\right):\dfrac{12}{13}=2\dfrac{1}{6}\Rightarrow-1\dfrac{3}{5}+x=\dfrac{13}{6}\cdot\dfrac{12}{13}=2\Rightarrow x=2+1\dfrac{3}{5}=3,6\)
Vậy \(x=3,6\)
c. \(-\dfrac{4}{7}x+\dfrac{7}{5}=\dfrac{1}{8}:\left(-1\dfrac{2}{3}\right)\Rightarrow-\dfrac{4}{7}x+\dfrac{7}{5}=-\dfrac{3}{40}\Rightarrow-\dfrac{4}{7}x=-\dfrac{3}{40}-\dfrac{7}{5}=-\dfrac{59}{40}\Rightarrow x=\left(-\dfrac{59}{40}\right):\left(-\dfrac{4}{7}\right)=2,58125\)
Vậy \(x=2,58125\)
\(A.\dfrac{-5}{13}.\dfrac{-4}{13}.\dfrac{-3}{13}.....\dfrac{4}{13}.\dfrac{5}{13}\)
\(A=\dfrac{-5.-4.-3.-2.-1.0.1.2.3.4}{13^{10}}\)
\(A=\dfrac{0}{13^{10}}=0\)
\(A=\dfrac{-5}{13}\cdot\dfrac{-4}{13}\cdot\dfrac{-3}{13}\cdot...\cdot\dfrac{4}{13}\cdot\dfrac{5}{13}\)
\(A=\dfrac{\left(-5\cdot5\right)\cdot\left(-4\cdot4\right)\cdot...\cdot\left(-1\cdot1\right)\cdot0}{13\cdot13\cdot13\cdot...\cdot13}\)
\(A=\dfrac{0}{13\cdot13\cdot13\cdot...\cdot13}\)
\(A=0\)
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Đừng có ỷ lại vào người khác ,động não lên.
\(-\dfrac{12}{13}x=6\dfrac{1}{13}+5\)
\(-\dfrac{12}{13}x=\dfrac{144}{13}\)
\(x=\dfrac{144}{13}:-\dfrac{12}{13}\)
\(x=-12\)