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18 tháng 4 2017
1\(\dfrac{5}{7}\) . 0,75 - \(\dfrac{6}{7}.1\dfrac{1}{3}+\dfrac{6}{7}\)
= \(\dfrac{12}{7}.0,75-\dfrac{6}{7}.\dfrac{4}{3}+\dfrac{6}{7}\)
= \(\dfrac{6}{7}.2.0,75-\dfrac{6}{7}.\dfrac{4}{3}+\dfrac{6}{7}\)
= \(\dfrac{6}{7}.\left(2.0,75-\dfrac{4}{3}+1\right)\)
= \(\dfrac{6}{7}.\dfrac{7}{6}\)
=1
2 tháng 7 2022
a: \(=\dfrac{77}{12}:\dfrac{11}{4}+\dfrac{45}{4}\cdot\dfrac{2}{15}\)
\(=\dfrac{77}{12}\cdot\dfrac{4}{11}+\dfrac{3}{2}\)
\(=\dfrac{7}{3}+\dfrac{3}{2}=\dfrac{23}{6}\)
b: \(=\left(\dfrac{3}{5}+\dfrac{415}{1000}-\dfrac{3}{200}\right)\cdot\dfrac{8}{3}\cdot\dfrac{1}{4}\)
\(=\dfrac{600+415-15}{1000}\cdot\dfrac{2}{3}=\dfrac{2}{3}\)
c: \(=\dfrac{28}{15}\cdot\dfrac{3}{4}-\left(\dfrac{11}{20}+\dfrac{4}{20}\right)\cdot\dfrac{3}{7}\)
\(=\dfrac{7}{5}-\dfrac{3}{4}\cdot\dfrac{3}{7}=\dfrac{7}{5}-\dfrac{9}{28}=\dfrac{151}{140}\)
17 tháng 4 2017
\(x:4\dfrac{1}{3}=2,5\\ x:\dfrac{13}{3}=\dfrac{5}{2}\\ x=\dfrac{5}{2}.\dfrac{13}{3}\\ x=\dfrac{65}{6}=10\dfrac{5}{6}\)
25 tháng 4 2017
\(-2\dfrac{1}{4}.\)\(\left(3\dfrac{5}{12}-1\dfrac{2}{9}\right)\)
=\(\dfrac{-9}{4}\).\(\left(\dfrac{41}{12}-\dfrac{11}{9}\right)\)
=\(\dfrac{-9}{4}.\dfrac{41}{12}-\dfrac{-9}{4}.\dfrac{11}{9}\)
=\(\dfrac{-123}{16}-\dfrac{-11}{4}\)
=\(\dfrac{-123}{16}-\dfrac{-44}{16}\)
=\(\dfrac{-79}{16}\)
25 tháng 4 2017
\(\left(-25\%+0,75+\dfrac{7}{12}\right)\div\left(-2\dfrac{1}{8}\right)\)
=\(\left(\dfrac{-1}{4}+\dfrac{3}{4}+\dfrac{7}{12}\right)\div\left(\dfrac{-17}{8}\right)\)
=\(\left(\dfrac{-3}{12}+\dfrac{9}{12}+\dfrac{7}{12}\right).\dfrac{-8}{17}\)
=\(\dfrac{13}{12}.\dfrac{-8}{17}=\dfrac{-26}{51}\)
NN
1
3 tháng 7 2017
\(-1\dfrac{1}{2}-x=\dfrac{-2}{3}+0,75\)
\(\dfrac{-3}{2}-x=\dfrac{1}{12}\Rightarrow x=\dfrac{-19}{12}\)
\(\left|\dfrac{4}{5}-x\right|-\dfrac{1}{10}=\dfrac{2}{5}\)
\(\Leftrightarrow\left|\dfrac{4}{5}-x\right|=\dfrac{1}{2}\)
\(\Leftrightarrow\dfrac{4}{5}-x=\dfrac{1}{2}\Rightarrow x=\dfrac{3}{10}\)
\(\Leftrightarrow\dfrac{4}{5}-x=-\dfrac{1}{2}\Rightarrow x=\dfrac{13}{10}\)
14 tháng 5 2022
\(A=\dfrac{9-18+14}{24}\cdot\dfrac{6}{5}+\dfrac{1}{2}=\dfrac{5}{24}\cdot\dfrac{6}{5}+\dfrac{1}{2}=\dfrac{1}{4}+\dfrac{1}{2}=\dfrac{3}{4}\)
\(B=\dfrac{28}{15}\cdot\dfrac{3}{4}-\left(\dfrac{11}{20}+\dfrac{1}{4}\right)\cdot\dfrac{5}{7}\)
\(=\dfrac{7}{5}-\dfrac{11+5}{20}\cdot\dfrac{5}{7}\)
\(=\dfrac{7}{5}-\dfrac{4}{7}=\dfrac{49-20}{35}=\dfrac{29}{35}\)
T
4 tháng 8 2018
\(\dfrac{\dfrac{1}{4}\left(4,75-\dfrac{3}{20}\right).3,2}{0,23:\dfrac{5}{8}.0,5}+\left|-0,75\right|.2\dfrac{1}{3}\)
\(=\left[\dfrac{1}{4}\left(4,75-\dfrac{3}{20}\right).3,2\right]:\left[0,23:\dfrac{5}{8}.0,5\right]+0,75.2\dfrac{1}{3}\)
\(=\left(\dfrac{1}{4}.\dfrac{23}{5}.\dfrac{16}{5}\right):\left(\dfrac{23}{100}:\dfrac{5}{8}.\dfrac{1}{2}\right)+\dfrac{3}{8}\)
\(=\dfrac{92}{25}:\dfrac{23}{125}+\dfrac{3}{8}=20+\dfrac{3}{8}=\dfrac{163}{8}\)
\(\dfrac{1}{2}-\left(40\%-0,75\right)=\dfrac{1}{2}-\left(\dfrac{40}{100}-\dfrac{3}{4}\right)=\dfrac{1}{2}-\dfrac{-7}{20}=\dfrac{1}{2}+\dfrac{7}{20}=\dfrac{17}{20}\)
hi