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\(\frac{3}{7}\times\frac{1}{3}+\frac{3}{7}\times\frac{4}{3}-\frac{3}{7}\times\frac{1}{9}\)
\(\frac{3}{7}\times\left(\frac{1}{3}+\frac{4}{3}-\frac{1}{9}\right)\)
\(\frac{3}{7}\times\left(\frac{5}{3}-\frac{1}{9}\right)\)
\(\frac{3}{7}\times\left(\frac{45}{27}-\frac{3}{27}\right)\)
\(\frac{3}{7}\times\frac{14}{9}\)
\(\frac{2}{3}\)
\(\frac{7}{15}\times\frac{6}{5}+\frac{3}{5}\times\frac{6}{5}-\frac{17}{30}:\frac{5}{6}\)
\(\frac{7}{15}\times\frac{6}{5}+\frac{3}{5}\times\frac{6}{5}-\frac{17}{30}\times\frac{6}{5}\)
\(\left(\frac{7}{15}+\frac{3}{5}-\frac{17}{30}\right)\times\frac{6}{5}\)
\(\left(\frac{14}{30}+\frac{18}{30}-\frac{17}{30}\right)\times\frac{6}{5}\)
\(\frac{1}{2}\times\frac{6}{5}\)
\(\frac{3}{5}\)
Chúc bạn học tốt !!!
37×13+37×43−37×1937×13+37×43−37×19
37×(13+43−19)37×(13+43−19)
37×(53−19)37×(53−19)
37×(4527−327)37×(4527−327)
37×14937×149
23
\(\frac{9}{2}\) \(-\) ( \(x\) \(-\) \(\frac{3}{4}\) ) = \(\frac{25}{4}\)
\(x\) \(-\) \(\frac{3}{4}\) = \(\frac{9}{2}\) \(-\) \(\frac{25}{4}\)
\(x\) \(-\) \(\frac{3}{4}\) = \(-\frac{7}{4}\)
\(x\) = \(-\frac{7}{4}\) \(+\) \(\frac{3}{4}\)
\(x\) = \(-1\)
\(4\) \(+\) \(x\) \(+\) \(\frac{3}{4}\) = \(\frac{17}{2}\)
( \(4\) \(+\) \(\frac{3}{4}\)) \(+\)\(x\) = \(\frac{17}{2}\)
\(\frac{19}{4}\) \(+\) \(x\) = \(\frac{17}{2}\)
\(x\) = \(\frac{17}{2}\) \(-\) \(\frac{19}{4}\)
\(x\) = \(\frac{15}{4}\)
a) \(\left(\frac{1}{3}+\frac{1}{5}\right)+\left(\frac{1}{6}-\frac{1}{5}\right)=\left(\frac{1}{3}+\frac{1}{6}\right)+\left(\frac{1}{5}-\frac{1}{5}\right)=\frac{1}{2}\)
b) \(\frac{3}{16}\times\frac{7}{5}+\frac{3}{5}\times\frac{9}{16}=\frac{21}{80}+\frac{27}{80}=\frac{48}{80}=\frac{3}{5}\)
c) \(\frac{1}{1\times2}+\frac{1}{2\times3}+...+\frac{1}{2020\times2021}=1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+...+\frac{1}{2020}-\frac{1}{2021}\)
\(=1-\frac{1}{2021}=\frac{2020}{2021}\)
d) \(\frac{1}{1\times3}+\frac{1}{3\times5}+...+\frac{1}{2021\times2023}=\frac{1}{2}\times\left(\frac{2}{1\times3}+\frac{2}{3\times5}+...+\frac{2}{2021\times2023}\right)\)
\(=\frac{1}{2}\times\left(1-\frac{1}{3}+\frac{1}{3}-\frac{1}{5}+...+\frac{1}{2021}-\frac{1}{2023}\right)\)
\(=\frac{1}{2}\times\left(1-\frac{1}{2023}\right)=\frac{1}{2}\times\frac{2022}{2023}=\frac{1011}{2023}\)
e) \(\frac{3}{2}\times\frac{1}{7}\times\frac{5}{4}+\frac{15}{2}\times\frac{6}{7}\times\frac{1}{4}==\frac{15}{56}+\frac{80}{56}=\frac{95}{56}\)
Bài giải
\(\frac{2}{3}+\frac{3}{4}+\frac{4}{5}=\frac{40}{60}+\frac{45}{60}+\frac{48}{60}=\frac{133}{60}\)
\(\frac{8}{5}+\frac{7}{6}+\frac{10}{9}+\frac{1}{2}=\frac{144}{90}+\frac{105}{90}+\frac{100}{90}+\frac{45}{90}=\frac{394}{90}\)
\(\frac{15}{17}-\frac{11}{13}+\frac{3}{26}=\frac{390}{442}+\frac{374}{442}+\frac{51}{442}=\frac{815}{442}\)
\(\frac{9}{12}\text{ x }\frac{4}{3}\text{ : }\frac{8}{5}=\frac{9}{12}\text{ x }\frac{4}{3}\text{ x }\frac{5}{8}=\frac{9\text{ x }4\text{ x }5}{12\text{ x }3\text{ x }8}=\frac{5}{8}\)
\(\frac{4}{5}\text{ x }\frac{15}{8}\text{ : }\frac{5}{7}=\frac{4}{5}\text{ x }\frac{15}{8}\text{ x }\frac{7}{5}=\frac{4\text{ x }15\text{ x }7}{5\text{ x }8\text{ x }5}=\frac{21}{10}\)
\(\frac{2}{3}+\frac{3}{4}+\frac{4}{5}=\frac{40}{60}+\frac{45}{60}+\frac{48}{60}=\frac{133}{60}\)
\(\frac{8}{5}+\frac{7}{6}+\frac{10}{9}+\frac{1}{2}=\frac{144}{90}+\frac{105}{90}+\frac{100}{90}+\frac{45}{90}=\frac{197}{45}\)
\(\frac{15}{17}-\frac{11}{13}+\frac{1}{26}=\frac{390}{442}+\frac{374}{442}+\frac{51}{442}=\frac{815}{442}\)
\(\frac{9}{12}\times\frac{4}{3}:\frac{8}{5}=1:\frac{8}{5}=\frac{5}{8}\)
\(\frac{4}{5}\times\frac{15}{8}:\frac{5}{7}=\frac{3}{2}:\frac{5}{7}=\frac{21}{10}\)
a) x= \(\frac{-5}{12}\)
b) x = \(\frac{2}{5}\)
c) x =\(\frac{-87}{140}\)
d) x = \(\frac{109}{140}\)
e) x = \(\frac{13}{63}\)
Câu 2:
\(\dfrac{7}{9}\cdot\dfrac{3}{35}=\dfrac{1}{5}\cdot\dfrac{1}{3}=\dfrac{1}{15}\)
\(\dfrac{9}{22}\cdot55=\dfrac{9\cdot55}{22}=\dfrac{9\cdot5}{2}=\dfrac{45}{2}\)
5/3 : (1/5 + x) = 7/9
1/5 + x = 5/3 : 7/9
1/5 + x = 15/7
x = 15/7 - 1/5
x = 68/35
1/5 + x = 5/3 : 7/9
1/5 + x = 15/7
x = 15/7 - 1/5
x = 68/35