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gợi ý :Thực hiện phép tính ở từng vế
Tụ làm nốt
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\(\text{a/-(59-3x)+39 = 3x -20}\)
\(-59+3x+39=3x-20\)
\(3x-59+39=3x-20\)
\(3x-20=3x-20\)
\(\Leftrightarrowđpcm\)
\(\text{b/ -(a+b+c) +(b-c) - (a-c-1)= 1+c- 2a }\)
\(-a-b-c+b-c-a+c+1=1+c-2a\)
\(1+\left(-b+b\right)+\left(-c-c+c\right)+\left(-a-a\right)=1+c-2a\)
\(1+0-c-2a=1+c-2a\)
\(1-c-2a=1+c-2a\)
\(\Rightarrow\)không thỏa mãn đề bàii
\(\text{c/ -(19-2x)=39= 2x+20}\)
\(-19+2x+39=2x+20\)
\(2x+\left(-19+39\right)=2x+20\)
\(2x+20=2x+20\)
\(\Leftrightarrowđpcm\)
\(\text{d/ b/ -(a+b+c) +(b-c) - (a-c+1)= c-2a-1 }\)
\(-a-b-c+b-c-a+c-1=c-2a-1\)
\(\left(-b+b\right)+\left(-c-c+c\right)+\left(-a-a\right)-1=c-2a-1\)
\(0-c-2a-1=c-2a-1\)
\(-c-2a-1=c-2a-1\)
\(\Leftrightarrow ko\)thỏa mãn đề bài
chúc bạn học tốt
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-(59- 3x)+39=3x-20
<=>-59+3x+39=3x-20
<=>3x-3x=59-20-39
<=>0x=0
vậy x có vô số nghiệm
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1 Tìm số nguyên x bik:
a.-( 2x+2)+25=-19
-2x - 2 + 25 = - 19
-2x = -19+2-25
-2x = -42
x = 21
b.1-(12+3x)=7
1 - 12 - 3x = 7
- 11 - 3x = 7
-3x = 7 + 11
- 3x = 18
x = -6
c.-(2x+2)+25=-19
giống câu a nhé
2.Rút gọn biểu thức
a.2x+(-61)-(21-61)
= 2x - 61 - 21 + 61
= 2x - 21
b. (-3-x+5)+3
= 2 - x + 3
= -1 -x
c.11-(13-x)+(13-11)
= 11 - 13 + x + 13 - 11
= x
d.25-(15-x+303)+303
= 25 - 15 + x - 303 + 303
= 10 + x
e.x+(-81)-(11-8)
= x - 81 - 11 + 8
= x - 84
f. (-1-x+2)+1
= -1 - x + 2 + 1
= - x + 2
g.15-(11-x)+(11-15)
= 15 - 11 + x + 11 - 15
= x
i) 15-(15-x+202)+202
= 15 - 15 + x - 202 + 202
= x
3.Chứng minh đẳng thức
a.-(59-3x)+39=3x-20
- 59 + 3x + 39 = 3x - 20
- 59 + 39 + 20 = 3x - 3x
0 = 0
b.-(a+b+c)+(b-c)-(a-c-1)=1+c-29
b - a - b - c + b - c - a + c + 1 = 1 + c - 29
b - a - b - c + b - c - a + c - c = 1 - 29 - 1
- 2a + b - 2c = - 29
chịu luôn -__-
c.-(19-2x)+39=2x+20
- 19 + 2x + 39 = 2x + 20
2x - 2x = 20 + 19 - 29
0 = 0
d.-(a+b+c)+b-c-( a-c+1)=c-2a-1
- a - b - c + b - c - a + c - 1 = c - 2a - 1
- a - b - c + b - c - a + c + 2a - c = -1 + 1
- 2c = 0
c = 0
Vậy c = 0
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\text{- ( 2789 _ 435 ) + ( 1789 _ 1435 )}\)
\(=-2789+435+1789-1435\)
\(=\left(-2789+1789\right)+\left(435-1435\right)\)
\(=-1000+-1000\)
\(=-2000\)
\(=-\left(-2010\right)+36.41-36.\left(-59\right)\)
\(=2010+36.\left(41+59\right)\)
\(=2010+36.100\)
\(=2010+3600\)
\(=5610\)
\(-75.\left(18-65\right)-65.\left(75-18\right)\)
\(=-75.18+75.65-65.75+65.18\)
\(=18.\left(-75+65\right)+75.\left(65-65\right)\)
\(=18.\left(-10\right)+75.0\)
\(=-180\)
\(-15:x=3\)
\(x=-15:3\)
\(x=-5\)
\(-3x+8=7\)
\(-3x=-1\)
\(x=\frac{1}{3}\)
\(\left(x-6\right).\left(7-x\right)=0\)
\(\Rightarrow\orbr{\begin{cases}x-6=0\\7-x=0\end{cases}\Leftrightarrow\orbr{\begin{cases}x=6\\x=7\end{cases}}}\)
\(\Rightarrow x\in\left\{6;7\right\}\)
\(2.\left(x-3\right)-3.\left(x-5\right)=4.\left(3-x\right)-18\)
\(2x-6-3x+15=12-4x-18\)
\(2x-3x+4x=12-18-15+6\)
\(3x=-15\)
\(\Rightarrow x=-5\)
\(-a.\left(c-d\right)-d.\left(a+c\right)=-c.\left(a+d\right)\)
\(-a.c+a.d-d.a+-d.c=-c.\left(a+d\right)\)
\(-c.\left(a+d\right)+a.\left(d-d\right)=-c.\left(a+d\right)\)
\(-c.\left(a+d\right)+a.0=-c.\left(a+d\right)\)
\(\Rightarrow-c.\left(a+d\right)=-c.\left(a+d\right)\)
(3a+2).(2a–1)+(3–a).(6a+2)–17.(a–1)
=6a²−3a+4a−2+18a+6−6a²−2a−17a+17
=(6a²−6a²)+(−3a+4a+18a−2a−17a)+(17−2+6)
=0+0+21
=21
học tốt
nice