![](https://rs.olm.vn/images/avt/0.png?1311)
Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
a) \(A=x^2+2xy+y^2-4x-4y+1\)
\(=\left(x+y\right)^2-4\left(x+y\right)+1\)
\(=3^2-4.3+1=-2\)
b) \(B=x\left(x+2\right)+y\left(y-2\right)-2xy+37\)
\(=x^2+2x+y^2-2y-2xy+37\)
\(=\left(x-y\right)^2+2\left(x-y\right)+37\)
\(=7^2+2.7+37=100\)
c) \(C=x^2+4y^2-2x+10+4xy-4y\)
\(=\left(x+2y\right)^2-2\left(x+2y\right)+10\)
\(=5^2-2.5+10=25\)
a) \(A=x^2+2xy+y^2-4x-4v+1\)
\(=\left(x+y\right)^2-4\left(x+y\right)+1\)
\(=3^2-4.3+1=-2\)
![](https://rs.olm.vn/images/avt/0.png?1311)
a) A= 2x2-8x+10 = 2(x-2)2+2\(\ge\)2\(\Leftrightarrow\)x=2
Vậy MinA=2 \(\Leftrightarrow\)x=2
b) B= -(x-1)2-(2y+1)2+7 \(\le\)7
Dấu = xảy ra khi x=1 và y=\(\frac{-1}{2}\)
Vậy MaxB=7 ....
![](https://rs.olm.vn/images/avt/0.png?1311)
(x3 - 4y)(x2 - 2xy + 4y)(x2 + 2xy + 4y) tại x = -2; y = 1/2
Thay x = -2; y = 1/2 vào biểu thức, ta có:
[(-2)3 - 4.(1/2)].[(-2)2 - 2.(-2).(1/2) + 4.(1/2)].[(-2)2 + 2.(-2).(1/2) + 4.(1/2)]
= -10.8.4
= -320
Vậy:..
![](https://rs.olm.vn/images/avt/0.png?1311)
a, Với x-y=7 thì
\(A=x\left(x+2\right)+y\left(y-2\right)-2xy+37\)
\(=x^2+2x+y^2-2y-2xy+37=\left(x^2-2xy+y^2\right)+\left(2x-2y\right)+37\)
\(=\left(x-y\right)^2+2\left(x-y\right)+37=7^2+2.7+37\)
\(=49+14+37=100\)
Vậy A=100
b, Với x+2y=5 thì
\(B=x^2+4y^2-2x+10+4xy-4y\)
\(=x^2+4y^2-2x+2x+4y+4xy-4y=x^2+4y^2+4xy\)
\(=x^2+2.x.2y+\left(2y\right)^2=\left(x+2y\right)^2=5^2=25\)
Vậy B=25
![](https://rs.olm.vn/images/avt/0.png?1311)
A=x2+2xy+y2-4x-4y+1
=(x+y)2-4.(x+y)+1
thay x+1= 3 ta được:
A=32-4.3+1
=9-12+1
=-2
![](https://rs.olm.vn/images/avt/0.png?1311)
\(A=x^2+2xy+y^2-4x-4y+1\)
\(=\left(x+y\right)^2-4\left(x+y\right)+1=3^2-4.3+1=-2\)
Vậy A=-2
Ta có: A = x2 - 4y2 + 4y = x2 - 4y(y - 1) = x2 - 4y[y - (x + 2y)] = x2 - 4y(y - x - 2y) = x2 - 4y(-y - x) = x2 + 4y2 + 4xy = (x + 2y)2 = 12 = 1
Ta có :
\(A=x^2-4y^2+4y\)
\(=\left(x^2-4y^2\right)+4y\)
\(=\left(x-2y\right)\left(x+2y\right)+4y\)
\(=x-2y+4y\) \(\left(x+2y=1\right)\)
\(=x+2y\)
\(=1\)
Vậy...........
Học tốt!!!