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17 tháng 3 2017

Chọn C.

Dựa vào định nghĩa khối đa diện. Mỗi cạnh là cạnh chung của đúng hai mặt.

19 tháng 1 2022

TL :

Gọi số cạnh của khối đa diện là \(C\), số đỉnh là \(Đ\). Vì mỗi đỉnh là đỉnh chung của ba cạnh và mỗi cạnh có \(2\)đỉnh nên \(3Đ=2C\)do đó \(Đ\) là sỗ chẵn.

HT

19 tháng 1 2022

Gọi số cạnh của khối đa diện là C, số đỉnh là Đ. Vì mỗi đỉnh là đỉnh chung của ba cạnh và mỗi cạnh có 2 đỉnh nên 3Đ=2C do đó Đ là sỗ chẵn.

20 tháng 5 2017

Khối đa diện

25 tháng 4 2019

Lấy một đỉnh B tùy ý của hình đa diện (H). Gọi M 1  là một mặt của hình đa diện (H) chứa B. Gọi A, B, C là ba đỉnh liên tiếp của  M 1 . Khi đó AB, BC là hai cạnh của (H). Gọi  M 2  là mặt khác với  M 1  và có chung cạnh AB với  M 1 . Khi đó  M 2  còn có ít nhất một đỉnh D sao cho A, B, D là ba đỉnh khác nhau liên tiếp của  M 2 . Nếu D ≡ C thì  M 1  và  M 2  có hai cạnh chung AB và BC, điều này vô lí. Vậy D phải khác C. Do đó qua đỉnh B có ít nhất ba cạnh BA, BC và BD.

AH
Akai Haruma
Giáo viên
11 tháng 7 2017

Lời giải:

Thiết diện là một tam giác đều cạnh \(a\sqrt{3}\) nên \(2R=\sqrt{3}a\Rightarrow R=\frac{\sqrt{3}a}{2}\)

Do đó diện tích xq của hình nón là:

\(S_{xq}=\pi Rl=\frac{3a^2}{2}\pi\)

Đáp án C

4 tháng 2 2020

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4 tháng 2 2020

Thui khỏi bt lm òi * nhắn lun ko bt cho nhanh lại cn lm màu *

10 tháng 11 2021

Giả sử đa diện (H)(H) có các đỉnh là A1,…AdA1,…Ad, gọi m1,…mdm1,…md lần lượt là số các mặt của (H)(H) nhận chúng là đỉnh chung, ở đó m1,…mdm1,…md là những số lẻ.

Như vậy mỗi đỉnh AkAk có mkmk cạnh đi qua.

Ta có: đỉnh A1A1 có m1m1 cạnh đi qua.

đỉnh A2A2 có m2m2 cạnh đi qua.

...

đỉnh AdAd có mdmd cạnh đi qua.

Do đó số các cạnh (có thể trùng nhau) của đa diện là m1+m2+...+mdm1+m2+...+md.

Tuy nhiên, do mỗi cạnh là cạnh chung của đúng hai mặt nên số cạnh ở trên được đếm hai lần.

Vậy số cạnh thực tế của (H)(H) bằng

c=12(m1+m2+...+md)c=12(m1+m2+...+md)      

Vì cc là số nguyên, m1,…mdm1,…md là những số lẻ nên dd phải là số chẵn.

Ví dụ : Hình chóp ngũ giác.

Đỉnh S là đỉnh chung của 5 mặt, tất cả các đỉnh còn lại là đỉnh chung của 3 mặt, hình chóp ngũ giác có 6 đỉnh

giup mình cày Sp vơi

Câu 1: Cho a, b, c là ba số dương thỏa mãn điều kiện a, b và ab cùng khác 1. Trong các khẳng định sau, khẳng định nào đúng?\(A.log_{ab}c=\frac{log_ac+log_bc}{log_ac.log_bc}.\)                              \(B.log_{ab}c=\frac{log_ac.log_bc}{log_ac+log_bc}.\)\(C.log_{ab}c=\frac{\left|log_ac-log_bc\right|}{log_ac.log_bc}.\)                              \(D.log_{ab}c=\frac{log_ac.log_bc}{\left|log_ac-log_bc\right|}.\)Câu 2: Xét hàm...
Đọc tiếp

Câu 1: Cho a, b, c là ba số dương thỏa mãn điều kiện a, b và ab cùng khác 1. Trong các khẳng định sau, khẳng định nào đúng?

\(A.log_{ab}c=\frac{log_ac+log_bc}{log_ac.log_bc}.\)                              \(B.log_{ab}c=\frac{log_ac.log_bc}{log_ac+log_bc}.\)

\(C.log_{ab}c=\frac{\left|log_ac-log_bc\right|}{log_ac.log_bc}.\)                              \(D.log_{ab}c=\frac{log_ac.log_bc}{\left|log_ac-log_bc\right|}.\)

Câu 2: Xét hàm số \(f\left(x\right)=-x^4+4x^2-3.\)Khẳng định nào sau đây đúng?

A. Hàm số đồng biến trong khoảng \(\left(-\infty;\sqrt{2}\right).\)

B. Hàm số đồng biến trong khoảng \(\left(-\sqrt{2};+\infty\right).\)

C. Hàm số đồng biến trong từng khoảng \(\left(-\infty;-\sqrt{2}\right)\)và \(\left(0;\sqrt{2}\right).\)

D. Hàm số đồng biến trong từng khoảng \(\left(-\sqrt{2};0\right)\)và \(\left(\sqrt{2};+\infty\right)\)

1
22 tháng 6 2019

Lần sau em đăng trong h.vn

1. \(log_{ab}c=\frac{1}{log_cab}=\frac{1}{log_ca+log_cb}=\frac{1}{\frac{1}{log_ac}+\frac{1}{log_bc}}=\frac{1}{\frac{log_ac+log_bc}{log_ac.log_bc}}=\frac{log_ac.log_bc}{log_ac+log_bc}\)

Đáp án B: 

2. \(f'\left(x\right)=-4x^3+8x\)

\(f'\left(x\right)=0\Leftrightarrow-4x^3+8x=0\Leftrightarrow x=0,x=\sqrt{2},x=-\sqrt{2}\)

Có BBT: 

x -căn2 0 căn2 f' f 0 0 0 - + - +

Nhìn vào bảng biên thiên ta có hàm số ... là đáp án C