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Bài 1:
a) \(\dfrac{4}{14}-x=\dfrac{10}{-21}\)
\(\Leftrightarrow x=\dfrac{4}{14}-\dfrac{10}{-21}\)
\(\Leftrightarrow x=\dfrac{16}{21}\)
Vậy ...
b) \(\dfrac{4}{14}:x=\dfrac{-21}{-20}\)
\(\Leftrightarrow\dfrac{4}{14.x}=\dfrac{21}{20}\)
\(\Leftrightarrow21.14.x=20.4\)
\(\Leftrightarrow294x=80\)
\(\Leftrightarrow x=\dfrac{40}{147}\)
Vậy ...
c) \(75\%.x+3=18\)
\(\Leftrightarrow\dfrac{3}{4}x=15\)
\(\Leftrightarrow x=20\)
Vậy ...
d) \(2x+1=32\)
\(\Leftrightarrow2x=31\)
\(\Leftrightarrow x=\dfrac{31}{2}\)
Vậy ...
Bài 1
A) \(\dfrac{4}{14}-x=\dfrac{10}{-21}\)
\(\Leftrightarrow x=\dfrac{4}{14}-\dfrac{10}{-21}\)
\(\Leftrightarrow x=\dfrac{4}{14}+\dfrac{10}{21}=\dfrac{12}{42}+\dfrac{20}{42}=\dfrac{32}{42}=\dfrac{16}{21}\)
B) \(\dfrac{4}{14}:x=\dfrac{-21}{-20}\)
\(\Leftrightarrow\dfrac{4}{14}.\dfrac{1}{x}=\dfrac{21}{20}\)
\(\Leftrightarrow\dfrac{4}{14x}=\dfrac{21}{20}\)
\(\Leftrightarrow20.4=21.14x\) (tích chéo)
\(\Leftrightarrow80=294x\)
\(\Leftrightarrow x=\dfrac{40}{147}\)
C) 75%.x + 3 = 18
\(\Leftrightarrow\dfrac{3}{4}x=15\)
\(\Leftrightarrow x=15:\dfrac{3}{4}=15.\dfrac{4}{3}=20\)
E) 2x + 1 = 32
<=> 2x = 31
<=> x = \(\dfrac{31}{2}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
A, -20+ (x-16) = -32
-20 +x -16 = -32
-36 + x = -32
x = -32 - (-36)
x = 4
Vậy x= 4
B, -42 - 7x= -14
-7x=-42-(-14)
-7x = -28
x = -28 : (-7)
x = 4
Vậy x= 4
c, 26+|𝑥−15|=30
| x -15| = 4
TH1: x - 15= 4
x = 19
TH2: x - 15 = -4
x= 11
vậy.........
![](https://rs.olm.vn/images/avt/0.png?1311)
số số hạng là :
( 1000000 - 1 ) : 1 + 1 = 1000000
tổng là :
( 1000000 + 1 ) x 1000000 : 2 = 500000500000
đáp số : 500000500000
![](https://rs.olm.vn/images/avt/0.png?1311)
(-14)-(57)-18=25
(-32)-14-12=-58
30+12+(-20)+(-12)=10
(-2)-(3-9)=4
6-(-5-11)=22
(-4)-(-2)-9=-11
![](https://rs.olm.vn/images/avt/0.png?1311)
11: Ta có: \(\left(x+3\right)^3=125\)
\(\Leftrightarrow x+3=5\)
hay x=2
12: Ta có: \(\left(2x\right)^4=16\)
\(\Leftrightarrow x^4=1\)
hay \(x\in\left\{1;-1\right\}\)
-14-(20-x)=32
-(20-x)=32+14
-20+x=46
x=46+20
x=66
Vậy x=66
x=66 nha bạn