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Ta có : x+75%.x=\(\frac{-5}{8}\)
=> x+0,75.x=\(\frac{-5}{8}\)
=> x+\(\frac{3}{4}\).x=\(\frac{-5}{8}\)
=> x.(1+\(\frac{3}{4}\))=\(\frac{-5}{8}\)
=> x.\(\frac{7}{4}\)=\(\frac{-5}{8}\)
=> x=\(\frac{-5}{14}\)
Vậy x=\(\frac{-5}{14}\)
Các bạn hãy tk cho mk nha !!!
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a, Có bằng nhau
b, Không bằng nhau
c, Có bằng nhau
d, Không bằng nhau
e, Không bằng nhau
a) 3/4 và 6/8
Ta có 3 . 8 = 4 . 6
=> 3/4 = 6/8
b) -4/5 và 8/-9
Ta có : -4 . ( -9 ) \(\ne\)8 . 5
=> -4/5 \(\ne\)8/-9
c) 10/14 và -15/-21
Ta có : 10/14 = 5/7 ; -15/-21 = 5/7
=> 10/14 = -15/-21
d) -4/7 và 4/7
Ta có : -4 < 4
=> -4/7 \(\ne\)4/7
e) 6/15 và -8/20
Ta có : 6/15 = 2/5 ; -8/20 = -2/5
=> 6/15 = -8/20
* Cái này \(\ne\)bạn tạm hiểu là " không bằng nhé :v Thực ra nó là " khác " *
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\(\frac{\frac{3}{5}+\frac{3}{7}+\frac{3}{11}}{\frac{7}{5}+1+\frac{7}{17}}\div\frac{\frac{1}{3}-\frac{1}{4}+\frac{1}{5}}{\frac{7}{6}-\frac{7}{8}+\frac{7}{10}}\)
\(=\frac{\frac{3}{5}+\frac{3}{7}+\frac{3}{11}}{\frac{7}{5}+\frac{7}{7}+\frac{7}{17}}\div\frac{\frac{2}{6}-\frac{2}{8}+\frac{2}{10}}{\frac{7}{6}-\frac{7}{8}+\frac{7}{10}}\)
\(=\frac{3\left(\frac{1}{5}+\frac{1}{7}+\frac{1}{11}\right)}{7\left(\frac{1}{5}+\frac{1}{7}+\frac{1}{11}\right)}\div\frac{2\left(\frac{1}{6}-\frac{1}{8}+\frac{1}{10}\right)}{7\left(\frac{1}{6}-\frac{1}{8}+\frac{1}{10}\right)}\)
\(=\frac{3}{7}\div\frac{2}{7}\)
\(=\frac{3}{7}\times\frac{7}{2}=\frac{3}{2}\)
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a) \(\frac{2}{3}+\frac{1}{3}\cdot\left(-\frac{2}{5}\right)\\ =\frac{2}{3}+\frac{-2}{15}\\ =\frac{10}{15}+\frac{-2}{15}\\ =\frac{8}{15}\)
b) \(0,75\cdot1\frac{7}{9}-1\frac{2}{5}:\frac{-21}{20}\\ =\frac{3}{4}\cdot\frac{16}{9}-\frac{7}{5}\cdot\frac{-20}{21}\\ =\frac{4}{3}-\frac{-4}{3}\\ =\frac{4}{3}+\frac{4}{3}\\ =\frac{4}{3}\cdot2\\ =\frac{8}{3}\)
c) \(\frac{-2}{17}+\frac{15}{23}+\frac{15}{-17}-\frac{-4}{19}+\frac{8}{23}\\ =\frac{-2}{17}+\frac{15}{23}+\frac{-15}{17}+\frac{4}{19}+\frac{8}{23}\\ =\left(\frac{-2}{17}+\frac{-15}{17}\right)+\left(\frac{15}{23}+\frac{8}{23}\right)+\frac{4}{19}\\ =\left(-1\right)+1+\frac{4}{19}\\ =0+\frac{4}{19}\\ =\frac{4}{19}\)
d) \(2019^0\cdot\left(6-2\frac{4}{5}\right)\cdot3\frac{1}{8}-1\frac{3}{5}:25\%\\ =1\cdot\left(\frac{30}{5}-\frac{14}{5}\right)\cdot\frac{25}{8}-\frac{8}{5}:\frac{1}{4}\\ =1\cdot\frac{16}{5}\cdot\frac{25}{8}-\frac{8}{5}\cdot4\\ =\frac{16}{5}\cdot\frac{25}{8}-\frac{32}{5}\\ =\frac{50}{5}-\frac{32}{5}\\ =\frac{18}{5}\)
e) \(\left(\frac{7}{8}-\frac{1}{2}\right)\cdot2\frac{2}{3}-\frac{3}{7}\cdot\left(2,5^2\right)\\ =\left(\frac{7}{8}-\frac{4}{8}\right)\cdot\frac{8}{3}-\frac{3}{7}\cdot6,25\\ =\frac{3}{8}\cdot\frac{8}{3}-\frac{3}{7}\cdot\frac{25}{4}\\ =1-\frac{75}{28}\\ =\frac{28}{28}-\frac{75}{28}\\ =\frac{-47}{28}\)
a, \(\frac{2}{3}+\frac{1}{3}.\left(\frac{-2}{5}\right)\)
= \(\frac{2}{3}+\frac{-2}{15}=\frac{8}{15}\)
b, \(0,75.1\frac{7}{9}-1\frac{2}{5}:\frac{-21}{20}\)
= \(\frac{3}{4}.\frac{16}{9}-\frac{7}{5}.\frac{-20}{21}\)
= \(\frac{4}{3}-\left(\frac{-4}{3}\right)=\frac{8}{3}\)
c, \(\frac{-2}{17}+\frac{15}{23}+\frac{15}{-17}+\frac{4}{19}+\frac{8}{23}\)
= \(\left(\frac{-2}{17}+\frac{-15}{17}\right)+\left(\frac{15}{23}+\frac{8}{23}\right)+\frac{4}{19}\)
= \(\left(-1\right)+1+\frac{4}{19}=0+\frac{4}{19}=\frac{4}{19}\)
d, \(\left(6-2\frac{4}{5}\right).3\frac{1}{8}-1\frac{3}{5}:25\%\)
=> \(\left(6-\frac{14}{5}\right).\frac{25}{8}-\frac{8}{5}:25\%\)
= \(\frac{16}{5}.\frac{25}{8}-\frac{8}{5}.25:100\)
= 10 - 0,4 = 9,6
e, \(\left(\frac{7}{8}-\frac{1}{2}\right).2\frac{2}{3}-\frac{3}{7}.\left(2,5^2\right)\)
=> \(\frac{3}{8}.\frac{8}{3}-\frac{3}{7}.6,25\)
= \(1-\frac{75}{28}=\frac{-47}{28}\)
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Ai giúp mình đi, ai nhanh tay mà đúng thì mình tick, ai chậm mà đúng thì tick lun nha~ Thanks các bạn nhiêu nhen :)
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còn phần d hình như sai đề
nếu sửa 16->169 thì tính được đó
a)= 23.(19-14)+1
=8.6+1
=49
b)=102-[60:(56-4-3.5)]
=100-[60:(25-15)]
=100-[60:10]
=100-6=94
c)=160:{17+[32.5-(14+211-8)]}
=160:{17+[45-14-8]}
=160:{17+23}
=160:40
=4
`(-2) + (-5)/8`
`=(-16)/8 + (-5)/8`
`= -(16+5)/8`
`= -21/8`
(-2) + 5 / 8
= (-16) /8 + (-5)/8
= -21/8