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\(8^2.32^4=2^{3.2}.2^{5.4}=2^6.2^{20}=2^{20+6}=20^{26}\)
\(27^3.9^4.243=3^{3.3}.9^{2.4}.3^5=3^9.3^8.3^5=3^{9+8+5}=3^{22}\)
\(8^2\cdot32^4=\left(2^3\right)^2\cdot\left(2^5\right)^4=2^6\cdot2^{20}=2^{26}\)
\(27^3\cdot9^4\cdot243=\left(3^3\right)^3\cdot\left(3^2\right)^4\cdot3^5=3^9\cdot3^8\cdot3^5=3^{22}\)
\(A=8^4.16^5.32=\left(2^3\right)^4.\left(2^4\right)^5.2^5\)\(=2^{12}.2^{20}.2^5=2^{12+20+5}=2^{37}\)
Vậy \(A=2^{37}\)
\(B=27^4.81^{10}=\left(3^3\right)^4.\left(3^4\right)^{10}=3^{12}.3^{40}=3^{12+40}=3^{52}\)
Vậy \(B=3^{52}\)
\(A=8^2\times32^4=\left(2^3\right)^2\times\left(2^5\right)^4=2^6\times2^{20}=2^{26}\)
1 phút trước (17:06)
Viết các tích sau dưới dạng lũy thừa:
a. \(8^4.16^5.32=2^{12}.2^{20}.2^5=2^{37}\)
b.\(27^4.81^{10}=3^{12}.3^{40}=3^{52}\)
a) 84 . 165 . 32
= (23)4 . (24)5 . 25
= 212 . 220 . 25
= 237
b) 274 . 8110
= (33)4 . (34)10
= 312 . 340
= 352
\(4.16^5.32=2^2.2^{20}.2^5=2^{27}\)
\(72^4.81^{10}=2^{12}.3^8.3^{40}=2^{12}.3^{48}=2^{12}.\left(3^4\right)^{12}=2^{12}.81^{12}=243^{12}\)
\(8^5=\left(2^3\right)^5\\ =2^{3\cdot5}=2^{15}\\ 32^{2021}=\left(2^5\right)^{2021}\\ =2^{5\cdot2021}=2^{10105}\)