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e,\(3\frac{2}{7}x-\frac{1}{8}=2\frac{3}{4}\)
\(=>\frac{23}{7}x-\frac{1}{8}=\frac{11}{4}\)
\(=>\frac{23}{7}x=\frac{11}{4}+\frac{1}{8}=\frac{23}{8}\)
\(=>x=\frac{23}{8}:\frac{23}{7}\)
\(=>x=\frac{7}{8}\)
b) \(5\frac{1}{4}.\frac{3}{8}+10\frac{3}{4}.\frac{3}{8}\)
\(=\left(5\frac{1}{4}+10\frac{3}{4}\right).\frac{3}{8}\)
\(=16.\frac{3}{8}=6\)
c) \(6\frac{1}{5}.\frac{-2}{7}+14\frac{4}{5}.\frac{-2}{7}\)
\(=\left(6\frac{1}{5}+14\frac{4}{5}\right).\frac{-2}{7}\)
\(=21.\frac{-2}{7}=-6\)
1125 : 1123- 35:9 - 60
1125: 1123- 243 : 9 - 60 121 - 243 : 9 - 60 = 34
125.100 - 25(9.4 +64)= 12500 - 25 (36+64) = 12500- 25.100=12500-2500=10000
\(\Rightarrow\dfrac{5}{4}-\dfrac{1}{4}x=\dfrac{3}{10}x-\dfrac{2}{5}\)
\(\Rightarrow\dfrac{5}{4}+\dfrac{2}{5}=\dfrac{3}{10}x-\dfrac{1}{4}x\)
\(\Rightarrow\dfrac{33}{20}=\dfrac{11}{20}x\)
\(\Rightarrow x=\dfrac{33}{20}\div\dfrac{11}{20}\)
\(\Rightarrow x=3\)
\(1\dfrac{1}{4}-x\dfrac{1}{4}=x\cdot30\%\cdot\dfrac{2}{5}\)
\(\Leftrightarrow\dfrac{5}{4}-x\dfrac{1}{4}=x\cdot\dfrac{3}{10}-\dfrac{2}{5}\)
\(\Leftrightarrow\dfrac{5}{4}-\dfrac{1}{4}x=\dfrac{3}{10}x-\dfrac{2}{5}\)
\(\Leftrightarrow25-5x=6x-8\)
\(\Leftrightarrow-5x-6x=-8-25\)
\(\Leftrightarrow-11x=-33\)
\(\Leftrightarrow x=3\)
Vậy x = 3
a: =>88/132<88/x<88/128
=>132>x>128
hay \(x\in\left\{131;130;129\right\}\)
c: =>9/56<7x/56<8y/56<26/56
=>\(\left\{{}\begin{matrix}7x\in\left\{14;21\right\}\\8y\in\left\{16;24\right\}\end{matrix}\right.\Leftrightarrow\left(x,y\right)\in\left\{\left(2;2\right);\left(3;3\right)\right\}\)