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\(x^3-4x^2-8x+8\)
\(\Leftrightarrow\left(x^3-4x^2\right)-\left(8x-8\right)\)
\(\Leftrightarrow x^2\left(x-4\right)-4\left(x-4\right)\)
\(\Leftrightarrow\left(x-4\right)\left(x^2-4\right)\)
- x2.(x3-x2+x-1)
- x.( x3-3x2-1)+3
- x.(x2-xy-y2)
Tìm x:
x3-16x = 0
=> x.(x2-16) = 0
=> x = 0 hay x2-16 = 0
=> x = 0 hay x2 = 0+16
=> x = 0 hay x2 = 16
=> x = 0 hay x = 4 hay x = -4
x4+x=x(x3+1)=x(x+1)(x2-x+1)
x4+64=x4+16x2+64-16x2=(x2+8)2-(4x)2=(x2+8+4x)(x2+8-4x)
4x4+81=4x4+36x2+81-36x2=(2x2+9)2-(6x)2=(2x2+9+6x)(2x2+9-6x)
64x4+y4=64x4+16(xy)2+y4-16(xy)2=(8x2+y2)-(4xy)2=(8x2+y2-4xy)(8x2+y2=4xy)
x4+4y4=x4+4(xy)2+4y4-4(xy)2=(x2+2y2-2xy)(x2+2y2+2xy)
x4+x2+1=(x4+2x2+1)-x2=(x2+1-x)(x2+1+x)
Mình làm có vài đoạn hơi tắt nha.
\(\left(2+1\right)\left(2^2+1\right)...\left(2^8+1\right)-2^{16}=\left(2-1\right)\left(2+1\right)\left(2^2+1\right)...\left(2^8+1\right)-2^{16}\)\(2^{16}\)
\(=-1\)
a)\(\left(x+2\right)\left(x^2-2x+4\right)-x\left(x^2+2\right)=0\)
\(\Leftrightarrow\left(x^3+2^3\right)-x^3-2x=0\)
\(\Leftrightarrow8-2x=0\)
\(\Leftrightarrow2x=8\)
\(\Leftrightarrow x=4\)
b)\(\left(x-1\right)^3-\left(x+3\right)\left(x^2-3x+9\right)+3\left(x^2-4\right)=2\)
\(x^3-3x^2+3x-1-x^3-27+3x^2-12=2\)
\(x^3-3x^2+3x-1-x^3-27+3x^2-12-2=0\)
\(3x-42=0\)
\(3x=42\)
\(x=14\)
Ta có :
(xn)2=x18
=> x2n=x2.9
=> x2.xn=x2.x9
=> xn=x9
=> n=9
:) thế thôi
( xn)2 = x18
hay xnx2 = x18
Suy ra nx2 = 18
Vậy n = 9.