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câu 1
125875/125871
câu 2
a) 13/17 < 15/19
b) 12/48 = 9/36
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2006x125+1000 / 126x2005-888
= (2005+1)x125+1000 / (125+1)x2005-888
= 2005x125+125+1000 / 125x2005+2005-888
= 2005x125+1125 / 125x2005+1117
= 1125/1117
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\(\frac{2006x125+1000}{126x2006-1006}=\frac{2006x125+1000}{125x2006-2006-1006}=\frac{2006x125+1000}{125x2006+1000}=1\)
=\(\frac{2006x125+1000}{125x2006+2006-1006}\)
=\(\frac{2006x125+1000}{125x2006+1000}\)
=1
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\(\frac{2006\cdot125+1000}{126\cdot2006-1006}=\frac{2006\cdot\left(126-1\right)+1000}{126\cdot2006-1006}\)
\(=\frac{2006\cdot126-2006+1000}{126\cdot2006-1006}\)
\(=\frac{2006\cdot126-1006}{126\cdot2006-1006}\)
\(=1\)
\(\frac{2006x125+1000}{126x2006-1006}\)
\(=\frac{2006x125+1000}{\left(125+1\right)x2006-1006}\)
\(=\frac{2006x125+1000}{125x2006+1x2006-1006}\)
\(=\frac{2006x125+1000}{125x2006+2006-1006}\)
\(=\frac{2006x125+1000}{125x2006+1000}\)
\(=1\)
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\(1\frac{1}{2}x1\frac{1}{3}:1\frac{1}{4}:1\frac{1}{5}\)
\(=\frac{3}{2}x\frac{4}{3}:\frac{5}{4}:\frac{6}{5}\)
\(=\frac{3}{2}x\frac{4}{3}x\frac{4}{5}x\frac{5}{6}\)
\(=\frac{4x4}{2x6}=\frac{2x2x4}{2x2x3}=\frac{4}{3}\)
\(1\frac{1}{2}\times1\frac{1}{3}\div1\frac{1}{4}\div1\frac{1}{5}=\frac{3}{2}\times\frac{4}{3}\div\frac{5}{4}\div\frac{6}{5}=\frac{3}{2}\times\frac{4}{3}\times\frac{4}{5}\times\frac{5}{6}\)
\(=\frac{3\times4\times4\times5}{2\times3\times5\times6}=\frac{4}{3}\)
\(\dfrac{2006 \times 125+1000}{126 \times 2005-880}\)
\(=\dfrac{(2005+1) \times 125+1000}{(125+1) \times 2005-880}\)
\(=\dfrac{2005 \times 125+125+1000}{125 \times 2005+2005-880}\)
\(=\dfrac{2005 \times 125+1125}{2005 \times 125+1125}=1\)
2=1