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=\(\frac{36-4+3}{6}-\frac{30+10-9}{6}-\frac{18-14+15}{6}\)
=\(\frac{35}{6}-\frac{31}{6}-\frac{19}{6}=\frac{35-31-19}{6}-\frac{15}{6}=-\frac{5}{2}\)
bài này thì dễ:
\(\left(6-\frac{2}{3}+\frac{1}{2}\right)-\left(5+\frac{5}{3}-\frac{3}{2}\right)-\left(3-\frac{7}{3}+\frac{5}{2}\right)\)
Cách 1:
\(\frac{35}{6}-\frac{31}{6}-\frac{19}{6}=\frac{35-31-19}{6}=-\frac{15}{6}=-\frac{5}{2}\)
Cách 2:
\(6-\frac{2}{3}+\frac{1}{2}-5-\frac{5}{3}+\frac{3}{2}-3+\frac{7}{3}-\frac{5}{2}=-2\frac{1}{2}=-\frac{5}{2}\)
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ta có: \(\frac{323232}{333333}=\frac{32}{33}\)
\(\frac{33333333}{34343434}=\frac{33}{34}\)
ta so sánh : \(\frac{32}{33}< \frac{33}{34}\)
=> \(\frac{323232}{333333}< \frac{33333333}{34343434}\)
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mk làm bài 1 thui,bài 2 chỉ qui đồng ms
3a/6 = 3b/4 => 3(a-b)/ (6-4) = 3.4,5/2= 13,5/2 =k
a = 2k=13,5
b = 4k/3 =9
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\(3-\frac{2}{3}+\frac{3}{5}\cdot\left(-\frac{10}{9}-\frac{25}{3}\right)-\frac{5}{6}\)
\(=3-\frac{2}{3}+\frac{3}{5}\cdot\left(-\frac{10}{9}-\frac{75}{9}\right)-\frac{5}{6}\)
\(=3-\frac{2}{3}+\frac{3}{5}\cdot-\frac{85}{9}-\frac{5}{6}\)
\(=3-\frac{2}{3}+\left(-\frac{17}{3}\right)-\frac{5}{6}\)
\(=\frac{-25}{6}\)
\(3-\frac{2}{3}+\frac{3}{5}.\left(\frac{-10}{9}-\frac{25}{3}\right)-\frac{5}{6}\)
\(=3-\frac{2}{3}+\frac{3}{5}.\left(\frac{-10}{9}-\frac{75}{9}\right)-\frac{5}{6}\)
\(=3-\frac{2}{3}+\frac{3}{5}.\frac{-85}{9}-\frac{5}{6}\)
\(=3-\frac{2}{3}+\frac{3.\left(-85\right)}{5.9}-\frac{5}{6}\)
\(=3-\frac{2}{3}+\frac{1.\left(-17\right)}{1.3}-\frac{5}{6}\)
\(=3-\frac{2}{3}+\frac{-17}{3}-\frac{5}{6}\)
\(=\frac{3}{1}-\frac{2}{3}+\frac{-17}{3}-\frac{5}{6}\)
\(=\frac{18}{6}-\frac{4}{6}+\frac{-34}{6}-\frac{5}{6}\)
\(=\frac{18-4+\left(-34\right)-5}{6}\)
\(=\frac{-25}{6}\)
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