Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
a)-2-13-14-19=-48
b)221+4[-40-4]=221-176=45
c)(-2)^5+32=-32+32=0
d)=93
Bài 2:Tim x, biết
a)-3x=-7-8<=>x=5
b)(x-6).(7-x)=0
=>_x-6=0=>x=6
_7-x=0=>x=7
Bài 1 .Tính
a, (-2)-13+(-14)-19
= -15+(-14)-19
= -29-19
= -48
b,221+4[(-5).8-4]
=221+4[-40-4]
=221+4(-44)
=221+(-176)
=-45
c,(-2)3.(-2)2+32
=-8.4+32
=-32+32
=0
d,-15.12-8.(-12)
=-15.12-(-8).12
=12.[-15-(-8)]
=12.(-7)
=-84
Bài 2 .Tìm x , biết
a, -3x+8=-7
-3x=-7-8
-3x=-15
x=-15:(-3)
x=5
Vậy x=5
b, (x-6).(7-x)=0
\(\Rightarrow\orbr{\begin{cases}x-6=0\\7-x=0\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}x=0+6=6\\x=7-0=7\end{cases}}\)
Vậy..............................
Bài 1:
A,
(100+121+144)÷(169+196)
=365:365=1
B
,1.2.3...7.8.(9-1-8)
=1.2.3...7.8.0=0
C,
3^2.2^4.2^32/11.2^13.2^22-2^26
=3^2.2^36/11.2^35-2^36
=3^2.2^36/2^35-(11-2)
=9.2/9=2
D,
=1152-374-1152+(-65)+374
=(1152-1152)+(-374+374)+(-65)
=0+0+(-65)=-65
E,
=13-(12-11-10+9)+(8-7-6+5)-(4-3-2+1)
=13-0+0-0=13
Bài 2:
A,(19x+50)÷14=25-16
(19x+50)÷14=9
19x+50=126
19x=76
x=4
B,
31x+(1+2+3+...+30)=1240
31x+465=1240
31x=775
×=25
a) \(\left(\frac{4}{13}.\frac{6}{5}+\frac{4}{13}.\frac{2}{5}\right).\left(2x+1\right)^2=\frac{10}{13}\)
\(\left(\frac{4}{13}.\frac{8}{5}\right).\left(2x+1\right)^2=\frac{10}{13}\)
\(\frac{32}{65}.\left(2x+1\right)^2=\frac{10}{13}\)
\(\left(2x+1\right)^2=\frac{10}{13}\div\frac{32}{65}\)
\(\left(2x+1\right)^2=\frac{25}{16}\)
\(\Rightarrow2x+1\in\left\{\frac{5}{4};-\frac{5}{4}\right\}\)
\(\hept{\begin{cases}2x+1=\frac{5}{4}\\2x+1=-\frac{5}{4}\end{cases}\Rightarrow\hept{\begin{cases}2x=\frac{1}{4}\\2x=-\frac{9}{4}\end{cases}\Rightarrow}\hept{\begin{cases}x=\frac{1}{8}\\x=-\frac{9}{8}\end{cases}}}\)
Vậy \(x\in\left\{\frac{1}{8};-\frac{9}{8}\right\}\)
\(x^3-\frac{9}{16}.x=0\)
\(x\left(x^2-\frac{9}{16}\right)=0\)
\(\hept{\begin{cases}x=0\\x^2-\frac{9}{16}=0\end{cases}\Rightarrow\hept{\begin{cases}x=0\\x^2=\frac{9}{16}\end{cases}\Rightarrow}\hept{\begin{cases}x=0\\x=\pm\frac{3}{4}\end{cases}}}\)
Vậy \(x\in\left\{0;\frac{3}{4};-\frac{3}{4}\right\}\)
Bài 2:
a; 17 - 11 - (-39)
= 17 - 11 + 39
= 6 + 39
= 45
b; 125 - 4[ 3 -7 .(-2)]
= 125 - 4.[3 + 14]
= 125 - 4.17
= 125 - 68
= 57
bài1:a
-3 + 12
= 12 - 3
= 9
b)(-24) : 8 = -3
c)-9 - 13
= -9 + (-13)
=-(9 + 13)
= -22
Bài 1:
1; ( - 35) : (-7) = 5
2; (- 42) : 21 = - 2
3; 45 : (-9) = -5
4; 18 : 9 = 2
5; (- 30) : (- 15) = 2
6; 0 : 18 = 0
7; 0 : (-13) = 0
8; 44 : (-4) = - 11
9; - 55 : 11 = - 5
10; 46 : 23 = 2
a) (54 + 57) . (89 - 27) . (24 - 42)
= (54 + 57) . (89 - 27) . (16 - 16)
= (54 + 57) . (89 - 27) . 0
= 0
b) (72003 + 72002) : 72001
= 72003 : 72001 + 72002 : 72001
= 72 + 7
= 49 + 7
= 53
c) (169 - 42 ) × ( 169 - 52 ) ×......× ( 169 - 132)
= (169 - 42 ) × ( 169 - 52 ) ×......× ( 169 - 169)
= (169 - 42 ) × ( 169 - 52 ) ×......× 0
= 0
Tìm x biết
7 × ( x - 14 ) + 39 = 25 + 279 ÷ 9
=> 7 × ( x - 14 ) + 39 = 25 + 31
=> 7 × ( x - 14 ) + 39 = 56
=> 7 × (x - 14) = 56 - 39
=> 7 × (x - 14) = 17
=> x - 14 = 17 : 7
=> x - 14 = 17/7
=> x = 17/7 + 14
=> x = 115/7
\((5^4+4^7)\times(8^9-2^7)\times(2^4-4^2)\)
\(=(5^4+4^7)\times(8^9-2^7)\times0\)
\(=0\)
Bài 1: tính
a)(-2 )7:(-2)4+8
=(-2)3+8
=-8+8
=0
b) (-14).9-13.(-19)
=-126-(-247)
=121
Bài 2:tìm x
a) 7.x = -14
x=-14:7
x=-2
b) 6.x-(-5)=17
6x+5=17
6x=17-5
6x=12
x=12:6
x=2
c) (x+2).(x-9)=0
\(\Rightarrow\orbr{\begin{cases}x+2=0\\x-9=0\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}x=0-2=-2\\x=0+9=9\end{cases}}\)
Camon bn nhìu nha!!