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Ta có 2=2
3=3
38=2.19
12=3.\(2^2\)
\(\Rightarrow BCNN\left(2;3;38;12\right)=2^2.3.19\)=228
\(\frac{1}{2}=\frac{1\cdot114}{2\cdot114}=\frac{114}{228}\)
\(\frac{1}{3}=\frac{1\cdot76}{3\cdot76}=\frac{76}{228}\)
\(\frac{1}{38}=\frac{1\cdot6}{38\cdot6}=\frac{6}{228}\)
\(-\frac{1}{12}=-\frac{1\cdot19}{12\cdot19}=-\frac{19}{228}\)
ta có mẫu số chung : 228
QĐMS các phân số : \(\frac{1}{2}\); \(\frac{1}{3}\);\(\frac{1}{38}\);\(\frac{-1}{12}\)
= \(\frac{114}{228}\);\(\frac{76}{228}\);\(\frac{6}{228}\);\(\frac{-19}{228}\)
k cho mình nha! thanks! ^_^
Ta rút gọn:
\(\frac{12}{15}=\frac{4}{5}=\frac{48}{60}\)
\(\frac{14}{-21}=\frac{-2}{3}=\frac{-40}{60}\)
\(\frac{-21}{-18}=\frac{21}{18}=\frac{7}{6}=\frac{70}{60}\)
\(\frac{2}{n}+\frac{2}{n+1}=\frac{2\left(n+1\right)}{n\left(n+1\right)}+\frac{2n}{n\left(n+1\right)}\)\(=\frac{2\left(n+1\right)+2n}{n\left(n+1\right)}=\frac{2n+2+2n}{n\left(n+1\right)}=\frac{4n+2}{n\left(n+1\right)}\)
\(\frac{1}{n\left(n+1\right)}+\frac{-2}{n+1}=\frac{1}{n\left(n+1\right)}+\frac{-2n}{n\left(n+1\right)}\)\(=\frac{1+\left(-2n\right)}{n\left(n+1\right)}=\frac{1-2n}{n\left(n+1\right)}\)
Ta có \(\frac{25}{53}\)=\(\frac{25.101}{53.101}\)=\(\frac{2525}{5353}\)
\(\frac{25}{53}\)=\(\frac{25.10101}{53.10101}\)=\(\frac{252525}{535353}\)
=>\(\frac{19}{28}va\frac{5}{9}\)
\(\frac{171}{252}va\frac{140}{252}\)