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huj sáng cũng làm 1 bài cho bạn bấy giờ nghĩ lại làm chi cho tốn thời gian
a/ x^3-3x^2-4x+12
=x2(x-3)-4(x-3)
=(x-3)(x2-4)
=(x-3)(x-2)(x+2)
b/ x^4-5x^2+4
=x4-4x2+4-x2
=(x2-2)2-x2
=(x2-x-2)(x2+x-2)
=(x2-x-2)(x2-x+2x-2)
=(x2-x-2)[x(x-1)+2(x-1)]
=(x2-x-2)(x-1)(x+2)
a) ( x - 1 )( 2x + 1 ) + 3( x - 1 )( x + 2 )( 2x + 1 )
= ( x - 1 )( 2x + 1 )[ 1 + 3( x + 2 ) ]
= ( x - 1 )( 2x + 1 )( 1 + 3x + 6 )
= ( x - 1 )( 2x + 1 )( 3x + 7 )
b) ( 6x + 3 ) - ( 2x - 5 )( 2x + 1 )
= 3( 2x + 1 ) - ( 2x - 5 )( 2x + 1 )
= ( 2x + 1 )[ 3 - ( 2x - 5 ) ]
= ( 2x + 1 )( 3 - 2x + 5 )
= ( 2x + 1 )( 8 - 2x )
= 2( 2x + 1 )( 4 - x )
c) ( x - 5 )2 + ( x + 5 )( x - 5 ) - ( 5 - x )( 2x + 1 )
= ( x - 5 )2 + ( x + 5 )( x - 5 ) + ( x - 5 )( 2x + 1 )
= ( x - 5 )[ ( x - 5 ) + ( x + 5 ) + ( 2x + 1 ) ]
= ( x - 5 )( x - 5 + x + 5 + 2x + 1 )
= ( x - 5 )( 4x + 1 )
d) ( 3x - 2 )( 4x - 3 ) - ( 2 - 3x )( x - 1 ) - 2( 3x - 2 )( x + 1 )
= ( 3x - 2 )( 4x - 3 ) + ( 3x - 2 )( x - 1 ) - 2( 3x - 2 )( x + 1 )
= ( 3x - 2 )[ ( 4x - 3 ) + ( x - 1 ) - 2( x + 1 ) ]
= ( 3x - 2 )( 4x - 3 + x - 1 - 2x - 2 )
= ( 3x - 2 )( 3x - 6 )
= 3( 3x - 2 )( x - 2 )
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a) \(x^2-xy+4x-2y+4\)
\(=\left(x^2+4x+4\right)-\left(xy+2y\right)\\ =\left(x+2\right)^2-y.\left(x+2\right)\)
\(=\left(x+2\right).\left(x+2-y\right)\)
b) \(2x^2-5x-3\)
\(=2x^2+x-6x-3\)
\(=\left(2x^2+x\right)-\left(6x+3\right)=x\left(2x+1\right)-3\left(2x+1\right)\)
\(=\left(2x+1\right).\left(x-3\right)\)
c)\(\)
c);d);e) tạm thời tớ chưa nghĩ ra-.-"
tham khả tạm 2 câu ạ, chúc học tốt'.'
a) \(x^2+4x+3\)
\(=x^2+3x+x+3\)
\(=x\left(x+3\right)+\left(x+3\right)\)
\(=\left(x+1\right)\left(x+3\right)\)
\(a,=x\left(4x^2-1\right)=x\left(2x-1\right)\left(2x+1\right)\\ b,=2\left(3x-2\right)-x\left(3x-2\right)=\left(2-x\right)\left(3x-2\right)\\ c,=x\left(y-1\right)-\left(y-1\right)=\left(x-1\right)\left(y-1\right)\\ d,=\left(y+2\right)^2-4x^2=\left(y+2-2x\right)\left(y+2+2x\right)\\ e,=x^2-x-2x+2=\left(x-1\right)\left(x-2\right)\)
a) \(4x^3-x^2=x^2\left(4x-1\right)\)
b) \(6x-4+x\left(2-3x\right)=2\left(3x-2\right)-x\left(3x-2\right)=\left(2-x\right)\left(3x-2\right)\)
c) \(xy+1-x-y=\left(xy-x\right)-\left(y-1\right)=x\left(y-1\right)-\left(y-1\right)=\left(x-1\right)\left(y-1\right)\)
d) \(y^2-4x^2+4y+4=\left(y^2+4y+4\right)-4x^2=\left(y+2\right)^2-\left(2x\right)^2=\left(y-2x+2\right)\left(y+2x+2\right)\)
e) \(x^2-3x+2=\left(x^2-x\right)-\left(2x-2\right)=x\left(x-1\right)-2\left(x-1\right)=\left(x-1\right)\left(x-2\right)\)