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2B = 2^2 +3^2+4^2 + ....+51^2
2B-B= 2^2+3^2+4^2+....+51^2 - 1^2 +2^2 + 3^2 +....+50^2
B= 51^2-1^2
= 50^2
=2500
2C = 3^2+4^2+......+ 51^2
2C-C= 3^2+4^2+....+51^2-2^2+3^2+.....+50^2
C= 51^2-2^2
C= 49^2
2D=2^2+3^2+4^2+......+ 50^2
2D-D= 2^2+3^2+......+50^2-1^2+2^2+....+49^2
D= 50^2- 1^2
D= 49^2
Ta có: \(A=2^0+2+2^2+...+2^{49}+2^{50}\)
\(2A=2+2^2+2^3+...+2^{50}+2^{51}\)
\(2A-A=2^{51}-2^0\)
Hay \(A=2^{51}-1\)
Hok "tuốt" nha^^
a) 21.72 - 11.72+90.72 + 49.125.16
= 21.72 - 11.72 + 90 .72 + 72.125.8.2
= 21.72-11.72+90.72+72.1000.2
=21.72-11.72+90.72+72.2000
= 72.( 21-11 + 90 + 2000)
= 72. 2100
= 49.2100
= 102 900
b) Đặt A = ( 20+21+22+23). 20.21.22.23
A = (20+21+22+23).26
A = 26+27+28+29
=> 2A = 27+28+29+210
2A-A = 210-26
A = 210-26
A = 960
Đặt \(A=1^2+2^2+3^2+...+49^2+50^2\)
\(\Rightarrow A=1.1+2.2+3.3+...+49.49+50.50\)
\(\Rightarrow A=1.\left(2-1\right)+2.\left(3-1\right)+3.\left(4-1\right)+...+49.\left(50-1\right)+50.\left(51-1\right)\)
\(\Rightarrow A=1.2-1+2.3-2+3.4-3+...+49.50-49+50.51-50\)
\(\Rightarrow A=\left(1.2+2.3+3.4+...+49.50+50.51\right)-\left(1+2+3+...+49+50\right)\)
Đặt \(B=1.2+2.3+3.4+...+49.50+50.51\)
\(\Rightarrow3B=1.2.3+2.3.3+3.4.3+...+49.50.3+50.51.3\)
\(\Rightarrow3B=1.2.3+2.3.\left(4-1\right)+3.4.\left(5-2\right)+...+49.50.\left(51-48\right)+50.51.\left(52-49\right)\)
\(\Rightarrow3B=1.2.3+2.3.4-1.2.3+3.4.5-2.3.4+...+49.50.51-48.49.50+50.51.52-49.50.51\)
\(\Rightarrow3B=50.51.52\)
\(\Rightarrow B=50.17.52=44200\)
Đặt \(C=1+2+3+...+50\)
\(\Rightarrow C=\frac{\left(1+50\right).50}{2}=1275\)
Thay B, C vào A
\(\Rightarrow A=44200-1275=42925\)
21.72-72.11+90.72+49.125.16
=72.(49+21).90+125.16
=14.70+90+125.16
=(14+16).90-20+125
=20-20.125+90
=0
b)
(22+21+22+23).20.21.23.22
=(22-22-22).(23-23).(21-21) 20
=0.0.0.0
=0
hok tốt
bạn tuấn tú ơi giải hộ mình đi
B = 1 + 2 + 22 + 23 + ... + 249 + 250
=> 2B = 2 + 22 + 23 + 24 + ... + 250 + 251
=> 2B - B = 251 - 1
Vậy B = 251 - 1