Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
Câu 1 : ( 2+x)2 =49
(2+x)2= 72
2+x = 7
=> x = 7 - 2
=>x=5
câu 2: 10 +2x = 45:43
10+2x = 42
10+2x = 16
2x = 16-10
2x = 6
=>x= 6 :2
=>x =3
câu 3: [ ( 4x +28) . 3+55 ] :5 = 35
(4x +28).3+55 = 35 . 5
(4x +28).3+55 = 175
( 4x+28).3 = 175 - 55
(4x+28).3 = 120
4x+28 = 120 :3
4x+28 = 40
4x = 40 - 28
4x = 12
x = 12:4
x = 3
**** cho mình nha!!!
a,128-39(x+4)
89(x+4)
(x+4)=89
x=89-4
x=85
mik cũng ko chắc nữa
[(4x + 28).3 + 55] : 5 = 35
=> (4x + 28).3 + 55 = 175
=> (4x + 28).3 = 120
=> 4x + 28 = 40
=> 4x = 12
=> x = 3
vậy_
[(4x+28).3+55]:5=35
[(4x+28).3+55]=35.5
[(4x+28).3+55]=175
(4x+28).3=175-55
(4x+28).3=120
4x+28=120:3
4x+28=40
4x=40-28
4x=12
x=12:4
x=3
k cho mik nhoa bn nha!
A = 1/2+5/6+11/12+19/20+29/30+41/42+55/56+71/72+89/90 =
1-1/2+1-1/6+1-1/12+1-1/20+1-1/30+1-1/42+1-1/56+1-1/72+1-1/90 =
9 – (1/2+1/6+1/12+1/20+1/30+1/42+1/56+1/72+1/90) =
9 – [1/(1x2)+1/(2x3)+1/(3x4)+1/(4x5)+1/(5x6)+1/(6x7)+1/(7x8)+1/(8x9)+1/(9x10)] =
9 – ( 1-1/2+1/2-1/3+1/3-1/4+1/4-1/5+1/5-1/6+1/6-1/7+1/7-1/8+1/8-1/9+1/9-1/10) =
9 – (1 – 1/10) = 9 – 9/10 = 81/10
a) \(128-3\left(x+4\right)=23\)
\(\Rightarrow3\left(x+4\right)=128-23\)
\(\Rightarrow3\left(x+4\right)=105\)
\(\Rightarrow x+4=35\)
\(\Rightarrow x=35-4\)
\(\Rightarrow x=31\)
b) \(\left[\left(4x+28\right)\cdot3+55\right]:5=35\)
\(\Rightarrow\left(4x+28\right)\cdot3+55=35\cdot5\)
\(\Rightarrow\left(4x+28\right)\cdot3+55=175\)
\(\Rightarrow\left(4x+28\right)\cdot3=120\)
\(\Rightarrow4x+28=40\)
\(\Rightarrow4x=12\)
\(\Rightarrow x=3\)
a, \(128-3\left(x+4\right)=23\)
\(=>3\left(x+4\right)=128-23\)
\(=>3\left(x+4\right)=105\)
\(=>x+4=105:3\)
\(=>x+4=35\)
\(=>x=35-4\)
\(=>x=31\)
b, \(\left[\left(4x+28\right).3+55\right]:5=35\)
\(=>\left(4x+28\right).3+55=35.5\)
\(=>\left(4x+28\right).3+55=175\)
\(=>\left(4x+28\right).3=175-55\)
\(=>\left(4x+28\right).3=120\)
\(=>4x+28=120:3\)
\(=>4x+28=40\)
\(=>4x=40-28\)
\(=>4x=12\)
\(=>x=12:4\)
\(=>x=3\)
\(#WendyDang\)
`@` `\text {Ans}`
`\downarrow`
`b)`
\([(4x+28).3+55] \div 5=35\)
`=> (4x + 28) * 3 + 55 = 35 * 5`
`=> (4x + 28)*3 + 55 = 175`
`=> (4x + 28)*3 = 175 - 55`
`=> (4x + 28)*3 =120`
`=> 4x + 28 = 120 \div 3`
`=> 4x + 28 = 40`
`=> 4x = 40 - 28`
`=> 4x = 12`
`=> x = 12 \div 4`
`=>x = 3`
Vậy, `x = 3.`
=>[12x+84+55]=175
=>12x=175-84-55=120-84=36
=>x=36/12=3