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a) \(\left(2x-1\right)^2-25=0\)
\(\left(2x-1\right)^2=0+25=25\)
\(\left(2x-1\right)^2=5^2=\left(-5\right)^2\)
\(\Rightarrow\left[\begin{array}{nghiempt}2x-1=5\\2x-1=-5\end{array}\right.\Rightarrow\left[\begin{array}{nghiempt}2x=6\\2x=-4\end{array}\right.\Rightarrow\left[\begin{array}{nghiempt}x=3\\x=-2\end{array}\right.\)
b) \(8x^3-50x=0\)
\(2x\left(4x^2-25\right)=0\)
\(\Rightarrow\left[\begin{array}{nghiempt}2x=0\\4x^2-25=0\end{array}\right.\Rightarrow\left[\begin{array}{nghiempt}x=0\\4x^2=25\Rightarrow x^2=\frac{25}{4}\Rightarrow\left[\begin{array}{nghiempt}x=\frac{5}{2}\\x=-\frac{5}{2}\end{array}\right.\end{array}\right.\)

\(x+1=7^{542}.7^{543}\)
\(x+1=7^{1085}\)
\(x=7^{1085}-1\)

a) Thiếu đề nhé
b) \(\left|x\right|-5=3\Leftrightarrow\left|x\right|=8\Leftrightarrow x=+_-8\)
c) \(\left|x-3\right|=7-\left(-2\right)\Leftrightarrow\left|x-3\right|=9\Leftrightarrow\orbr{\begin{cases}x-3=9\\x-3=-9\end{cases}\Leftrightarrow\orbr{\begin{cases}x=12\\x=-6\end{cases}}}\)
b)|x|-5=3
|x|=3+5
|x|=8
suy ra x=8 hoặc x=-8
c) |x-3|=7-(-2)
|x-3|=9
suy ra x-3=9 hoặc x-3=-9
x=9+3 x=-9+3
x=12 x=-6
vậy x=12 hoặc x=-6
ý a thiếu đầu bài nha

a ) 5x=2y
b) 7x = 3y
c ) 3+x /7+y= 3/7
=> (3+x).7= (7+y).3
21 + 7x = 21 + 3y
=> 7x = 3y
=> x/y = 3/7 => x= 20:(7+3).3=6
=> y = 20 - 6 = 14
Vậy (x;y) thuộc {(6;14)}

a) => 4/3x = 7/9 - 4/9 = 1/3
=> x = 1/3 : 4/3 = 1/4
b) => 5/2 - x = 9/14 : (-4/7) = -9/8
=> x = 5/2 - (-9/8) = 5/2 + 9/8 = 29/8
c) => 3x = 2 và 2/3 - 3/4 = 8/3 - 3/4 = 23/12
=> x = 23/12 : 3 = 23/36
D) => -5/6 - x = 1/4
=> x = -5/6 - 1/4 = -13/12
a) \(\dfrac{4}{9}+\dfrac{4}{3}x=\dfrac{7}{9}\)
\(\dfrac{4}{3}x=\dfrac{7}{9}-\dfrac{4}{9}=\dfrac{1}{3}\)
\(x=\dfrac{1}{3}:\dfrac{4}{3}\)
\(x=\dfrac{1}{4}\)
b) \(\left(\dfrac{5}{2}-x\right)\left(-\dfrac{4}{7}\right)=\dfrac{9}{14}\)
\(\dfrac{5}{2}-x=\dfrac{9}{14}:\left(-\dfrac{4}{7}\right)=-\dfrac{9}{8}\)
\(x=\dfrac{5}{2}-\left(-\dfrac{9}{8}\right)\)
\(x=\dfrac{29}{8}\)
c) \(3x+\dfrac{3}{4}=2\dfrac{2}{3}\)
\(3x+\dfrac{3}{4}=\dfrac{8}{3}\)
\(3x=\dfrac{8}{3}-\dfrac{3}{4}=\dfrac{23}{12}\)
\(x=\dfrac{23}{12}:3\)
\(x=\dfrac{23}{36}\)
d) \(-\dfrac{5}{6}-x=\dfrac{7}{12}+\dfrac{-1}{3}\)
\(-\dfrac{5}{6}-x=\dfrac{1}{4}\)
\(x=-\dfrac{5}{6}-\dfrac{1}{4}\)
\(x=-\dfrac{13}{12}\)

3(x + 1) + 2(x + 5) = 7
3x + 3 + 2x + 10 = 7
3x + 2x + 3 + 10 = 7
3x + 2x + 13 = 7
x(3 + 2) + 13 = 7
5x + 13 = 7
5x = 7 - 13
5x = -6
x = -6 : 5
x = -1,2
3(x + 1) + 2(x + 5) = 7
3x + 3 + 2x + 10 = 7
3x + 2x + 3 + 10 = 7
3x + 2x + 13 = 7
x(3 + 2) + 13 = 7
5x + 13 = 7
5x = 7 - 13
5x = -6
x = -6 : 5
x = -1,2

a) 4x - 15 = -75 -x
4x+x = -75 + 15
5x = 60
x= 60: 5
=> x= 12
b) 3| x-7| = 21
|x-7|= 21:3
|x-7|=7
=> x-7 =7 hoặc x-7=-7
+) x-7=7
x=7+7=14
+) x-7=-7
x= -7+7=0
=> x=14 hoặc x=0
c) Áp dụng t/c phân số bằng nhau
=> x= \(\frac{-3.\left(-2\right)}{6}\)=\(\frac{6}{6}\)=1
Thay x=1 => y= \(\frac{\left(-2\right).\left(-18\right)}{1}\)=\(\frac{36}{1}\)=36
Thay y =36 => z=\(\frac{\left(-18\right).24}{36}\)=\(\frac{-432}{36}\)=-12
vậy (x,y,z)= (1;36;-12)
(câu d dài quá vs lại cx dễ nên bn tự lm nha mk chỉ giúp đến đây thôi)
a, \(\left|x-5\right|=\left|-7\right|\)
\(\left|x-5\right|=7\)
\(\Rightarrow x-5=7\) hoặc \(x-5=-7\)
\(x=7+5\) hoặc \(x=-7+5\)
\(x=12\) hoặc \(x=-2\)
b, \(\left|x-3\right|=7-\left(-2\right)\)
\(\left|x-3\right|=7+2\)
\(\left|x-3\right|=9\)
\(\Rightarrow x-3=9\) hoặc \(x-3=-9\)
\(x=9+3\) hoặc \(x=-9+3\)
\(x=12\) hoặc \(x=-6\)