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Thấy 28%=\(\frac{7}{25}\)33%=\(\frac{33}{100}\)17%=\(\frac{17}{100}\)
Vậy ta có phép tính \(\frac{7}{25}+\frac{11}{50}+\frac{17}{100}+\frac{33}{100}\)
Ta có: \(\left(\frac{7}{25}+\frac{11}{50}\right)+\left(\frac{17}{100}+\frac{33}{100}\right)\)
=\(\frac{6}{25}+\frac{1}{2}\)=\(\frac{37}{50}\)
a) 17 x 25 + 25 x 33 +25 x 50 = 25 x (17 + 33 + 50)
= 25 x 100 = 2500
b) 125 x 15 -25 x 15 = 15 x (125 - 25)
= 15 x 100 = 1500
\(\frac{17}{8}+\frac{28}{15}-\frac{8}{15}=\frac{17}{8}+\frac{4}{3}=\frac{83}{24}=3\frac{11}{24}\)
=> chọn a
\(\frac{31}{53}.\frac{17}{28}+\frac{31}{28}.\frac{11}{53}\)
\(=\frac{31}{53}.\frac{17}{28}+\frac{11}{28}.\frac{31}{53}\)
\(=\frac{31}{53}.\left(\frac{17}{28}+\frac{11}{28}\right)\)
\(=\frac{31}{53}.1\)
\(=\frac{31}{53}\)
\(\frac{31}{53}\times\frac{17}{28}+\frac{31}{28}\times\frac{11}{53}\)
\(=\frac{31}{53}\times\frac{17}{28}+\frac{31}{53}\times\frac{11}{28}\)
\(=\frac{31}{53}\times\left(\frac{17}{28}+\frac{11}{28}\right)\)
\(=\frac{31}{53}\times1\)
\(=\frac{31}{53}\)
bỏ tạm 38/25 ra
=(9/10-11/15) +(13/21-15/28) +(197/4851-199/4950)
=1/6+1/12+1/20+...+1/49*50=2450
=3-2/2x3+4-3/3x4+5-4/4x5+....50-49/49x50
=1/2-1/3+1/3-...-1/50
1/2-1/50=12/25
=38/25+12/25=50/25
=2
1 Tính
7/12 - 2/7 + 1/12= (7/12-1/12)+2/7=6/12+2/7=1/2+2/7=7/14+4/14=11/14
12/17-5/17-4/17= 12-5-4/17=3/17
2a, 7/11+3/4+4/11+1/4= (7/11+4/11)+3/4+1/4=11/11+4/4=1+1=2
b)72/99-28/99-14/99= (72-28-14)/99=30/99=10/33
c)69,78+35,97+30,22= (69,78+30,22)+35,97=100+35,97=135,97
d) 83,45-30,98-42,47=83,45-(30,98+42,47)=83,45-73,45=10