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a) [(-2,5. 0,38. 0, 4) - ( 0,125. 3,15. (-8)]
=[(-2,5.0,4).0,38] - [(-8.0,125).3,15)]
= [(-1).0,38] - [(-1).3,15]
= -0,38 - (-3,15)
= 2.77
b) [(-20,83) .0,2 + (-9,17).0,2] : [ 2,47.0,5 - (-3,53).0,5]
= [(-20,83 - 9,17).0,2] : [(2,47 + 3,53).0,5]
= (-6) : 3
= -2
a/ \(\left(-2,5.0,38.0,4\right)-\left[0,125.3,15.\left(-8\right)\right]\)
\(=\left(-0,95.0,4\right)-\left[0,39375.\left(-8\right)\right]\)
\(=-0,38-3,15=2,77\)
b/ \(\left[\left(-20,83\right).0,2+\left(-9,17\right).0,2\right]:\left[2,47.0,5-\left(-3,53\right).0,5\right]\)
\(=\left[-4,166+-1,834\right]:\left[1,235--1,765\right]\)
\(=-6:3\)
\(=-2\)
\(\left[\left(-20,83\right).0,2+\left(-9,17\right).0,2\right]:\left[2,47.0,5-\left(-3.53\right).0,5\right]\)
\(=\left\{0,2.\left[\left(-20,83\right)+\left(-9,17\right)\right]\right\}:\left[2,47.0,5+3,53.0,5\right]\)
\(=\left[0,2.\left(-30\right)\right]:\left[0,5.\left(2,47+3,53\right)\right]\)
\(=\left(-6\right):\left(0,5.6\right)\)
\(=\left(-6\right):3\)
\(=\left(-2\right)\)
[ (-20,83) . 0,2 + (-9,17) . 0,2 ] : [ 2,47 . 0,5 - (-3.53) . 0,5 ]
= [\(\frac{-2083}{500}\) + \(\frac{-917}{500}\) ] [ \(\frac{247}{200}-\frac{-353}{200}\) ]
= -6 : 3 = -2
a) (−3,1597)+(−2,39)= -5,5497
b) (−0,793)−(−2,1068)= 1.3138
c) (−0,5).(−3,2)+(−10,1).0,2= -0,42
d) 1,2.(−2,6)+(−1,4):0,7=-5,12
c) \(\frac{0,375-0,3+\frac{3}{11}+\frac{3}{12}}{0,625-0,5+\frac{5}{11}+\frac{5}{12}}=\frac{3\left(0,125-0,1+\frac{1}{11}+\frac{1}{12}\right)}{5\left(0,123-0,1+\frac{1}{11}+\frac{1}{12}\right)}=\frac{3}{5}\)
a) (-2,5. 0,38. 0, 4) - ( 0,125. 3,15. (-8))
=((-2,5.0,4).0,38) - ((-8.0,125).3,15)
= ((-1).0,38) - ((-1).3,15)
= -0,38 - (-3,15)
= 2.77
b) ((-20,83) .0,2 + (-9,17).0,2) : ( 2,47.0,5 - (-3,53).0,5)
= ((-20,83 - 9,17).0,2) : ((2,47 + 3,53).0,5)
= (-6) : 3
= -2
a) (-2,5. 0,38. 0, 4) - ( 0,125. 3,15. (-8))
=((-2,5.0,4).0,38) - ((-8.0,125).3,15)
= ((-1).0,38) - ((-1).3,15)
= -0,38 - (-3,15)
= 2.77
b) ((-20,83) .0,2 + (-9,17).0,2) : ( 2,47.0,5 - (-3,53).0,5)
= ((-20,83 - 9,17).0,2) : ((2,47 + 3,53).0,5)
= (-6) : 3
= -2