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Ta có:3a=2b,\(\frac{b}{4}=\frac{c}{5}\)
\(\Rightarrow\frac{a}{2}=\frac{b}{3},\frac{b}{4}=\frac{c}{5}\)
\(\Rightarrow\frac{a}{8}=\frac{b}{12},\frac{b}{12}=\frac{c}{15}\)
\(\Rightarrow\frac{a}{8}=\frac{b}{12}=\frac{c}{15}=\frac{a+b+c}{8+12+15}=\frac{70}{35}=2\)(T/C...)
\(\Rightarrow a=16,b=24,c=30\)
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\(a-b=\dfrac{a}{b}=3\left(a+b\right)\\ \Leftrightarrow3a+3b-a+b=0\\ \Leftrightarrow2a+4b=0\\ \Leftrightarrow a+2b=0\Leftrightarrow a=-2b\)
Mà \(a-b=\dfrac{a}{b}\Leftrightarrow-3b=-\dfrac{2b}{b}=-2\Leftrightarrow b=\dfrac{2}{3}\)
\(\Leftrightarrow a=-2\cdot\dfrac{2}{3}=-\dfrac{4}{3}\)
Vậy \(\left(a;b\right)=\left(-\dfrac{4}{3};\dfrac{2}{3}\right)\)
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Theo đề ra, ta có:
\(\frac{a}{b}=\frac{9}{7}\Rightarrow\frac{a}{9}=\frac{b}{7}\)
\(\frac{b}{c}=\frac{7}{3}\Rightarrow\frac{b}{7}=\frac{c}{3}\)
\(\Rightarrow\frac{a}{9}=\frac{b}{7}=\frac{c}{3}\)
Áp dụng tính chất của dãy tỷ số bằng nhau
\(\frac{a}{9}=\frac{b}{7}=\frac{c}{3}=\frac{a-b+c}{9-7+3}=\frac{-15}{5}=-3\)
\(\Rightarrow a=\left(-3\right).9=-27\)
\(\Rightarrow b=\left(-3\right).7=-21\)
\(\Rightarrow c=\left(-3\right).3=-9\)
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a= 10;b=15; c=20
Nếu muốn cách giải thì
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