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111111=3.7.11.13.37
222222=2.3.7.11.13.37
THẾ ZÔ LM TIẾP
a) \(\frac{1}{n}\) - \(\frac{1}{n+1}\) = \(\frac{n+1}{n\left(n+1\right)}\) - \(\frac{n}{n\left(n+1\right)}\) = \(\frac{1}{n\left(n+1\right)}\) = \(\frac{1}{n}\) . \(\frac{1}{n+1}\) =>đpcm
b) A= \(\frac{1}{2}\) - \(\frac{1}{3}\) + \(\frac{1}{3}\) - \(\frac{1}{4}\)+...+\(\frac{1}{8}\) - \(\frac{1}{9}\) +\(\frac{1}{9}\)
= \(\frac{1}{2}\) + \(\frac{1}{9}\)= \(\frac{11}{18}\)
a)\(\frac{1}{a}-\frac{1}{a+1}=\frac{a+1}{a\left(a+1\right)}-\frac{a}{\left(a+1\right)a}=\frac{a+1-a}{a\left(a+1\right)}=\frac{1}{a\left(a+1\right)}\)
b)\(\frac{1}{a}-\frac{1}{b}=\frac{b}{ab}-\frac{a}{ab}=\frac{b-a}{ab}\)
Thay a,b,c lần lượt vào biểu thức...
Tính được kết quả:
a) A= \(-\frac{7}{10}\)
b) B= \(-\frac{2}{7}\)
c) C= 0
Câu 1 :\(P=\left(1-\frac{1}{2}\right).\left(1-\frac{1}{3}\right).....\left(1-\frac{1}{99}\right)=\frac{1}{2}.\frac{2}{3}.\frac{3}{4}.....\frac{98}{100}=\frac{1}{100}\)
Không chép lại đề nhé
Ta có:
P=\(\frac{50-49}{49}+\frac{50-48}{48}+...+\frac{50-2}{2}+\frac{50-1}{1}\)
P=\(\frac{50}{49}-\frac{49}{49}+\frac{50}{48}-\frac{48}{48}+...+\frac{50}{2}-\frac{2}{2}+\frac{50}{1}-\frac{1}{1}\)
P=\(\left(\frac{50}{49}+\frac{50}{48}+...+\frac{50}{2}\right)+\frac{50}{1}-\left(\frac{49}{49}+\frac{48}{48}+...+\frac{2}{2}+\frac{1}{1}\right)\)
P=\(50\cdot\left(\frac{1}{49}+\frac{1}{48}+...+\frac{1}{2}\right)+50-49\) (chỗ này gộp nha)
P=\(50\cdot\left(\frac{1}{2}+\frac{1}{3}+...+\frac{1}{48}+\frac{1}{49}\right)+1\)
P=\(50\cdot\left(\frac{1}{2}+\frac{1}{3}+...+\frac{1}{49}\right)+\frac{50}{50}\)
P=\(50\cdot\left(\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+...+\frac{1}{49}+\frac{1}{50}\right)\)
=>P=50S
=>\(\frac{S}{P}=\frac{S}{50S}=\frac{1}{50}\)
Vừa nãy mình nói nhầm, Sorry.
a: \(B=\left(-\dfrac{1}{5}-\dfrac{5}{7}+\dfrac{-3}{35}\right)+\left(\dfrac{1}{3}+\dfrac{1}{6}+\dfrac{1}{2}\right)+\dfrac{1}{41}\)
\(=\dfrac{-7-25-3}{35}+\dfrac{3+2+1}{6}+\dfrac{1}{41}=\dfrac{42}{41}-1=\dfrac{1}{41}\)
a) 2\(\frac{x}{7}\) = \(\frac{75}{35}\)
\(\frac{2.7+x}{7}\) = \(\frac{75:5}{35:5}\) = \(\frac{15}{7}\)
=> 2.7+x = 15
14+x = 15
x = 15-14 = 1
Vậy x=1
b)4\(\frac{3}{x}\) = \(\frac{47}{x}\)
\(\frac{4.x+3}{x}\) = \(\frac{47}{x}\)
=> 4.x + 3 = 47
4x= 47-3=44
vậy x= 44:4=11
c)x\(\frac{x}{15}\) = \(\frac{112}{5}\)
x\(\frac{x}{15}\) =\(\frac{112.3}{5.3}\) = \(\frac{336}{15}\)
\(\frac{x.15+x.1}{15}\) = \(\frac{336}{15}\)
=>(15+1) x =336
16x = 336
x = 336 : 16
vậy x = 21
\(A=\frac{111111}{121212}+\frac{111111}{202020}+\frac{111111}{303030}\)
\(A=\frac{11}{12}+\frac{11}{20}+\frac{11}{30}\)
\(A=\frac{55}{60}+\frac{33}{60}+\frac{22}{60}\)
\(A=\frac{110}{60}=\frac{11}{6}\)
bạn ơi rút gọn bằng cách nào vậy từ \(\dfrac{111111}{121212}\)