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Ta có: \(B=\frac{101+102+103}{102+103+104}=\frac{101}{102+103+104}+\frac{102}{102+103+104}+\frac{103}{102+103+104}\)
Ta thấy: \(\frac{101}{102}>\frac{101}{102+103+104}\)
\(\frac{102}{103}>\frac{102}{102+103+104}\)
\(\frac{103}{104}>\frac{103}{102+103+104}\)
\(\Rightarrow A=\frac{101}{102}+\frac{102}{103}+\frac{103}{104}>\frac{101}{102+103+104}+\frac{102}{102+103+104}+\frac{103}{102+103+104}=\frac{101+102+103}{102+103+104}=B\)
Vậy....
\(B=\frac{101+102+103}{102+103+104}=\frac{101}{102+103+104}+\frac{102}{102+103+104}+\frac{103}{102+103+104}\)
Ta có: \(\frac{101}{102}>\frac{101}{102+103+104}\)
\(\frac{102}{103}>\frac{102}{102+103+104}\)
\(\frac{103}{104}>\frac{103}{102+103+104}\)
\(\Rightarrow A=\frac{101}{102}+\frac{102}{103}+\frac{103}{104}>\frac{101}{102+103+104}+\frac{102}{102+103+104}+\frac{103}{102+103+104}=\frac{101+102+103}{102+103+104}=B\)Vậy....
Ta có :\(\frac{101}{102}>\frac{101}{102+103+104}\)
\(\frac{102}{103}>\frac{102}{102+103+104}\)
\(\frac{103}{104}>\frac{103}{102+103+104}\)
Do đó:\(\frac{101}{102}+\frac{102}{103}+\frac{103}{104}>\frac{101+102+103}{102+103+104}\)
Vậy A>B
a) 27 × 10 = 270; 72 × 100 = 7200; 14 × 1000 = 14000
86 × 10 = 860; 103 × 10 = 10300; 452 × 1000 = 452000
358 × 10 = 3580; 1977 × 100 = 197700; 300 × 1000 = 300000
b) 80 :10 = 8; 400 : 100 = 4 ;6000 : 1000 = 6
300 : 10 = 30; 4000 : 100 = 40 ; 60000 : 1000 = 60
2000 :10 = 200; 40000 :100 = 400 ;600000 : 1000 = 600
c) 64 × 10 = 640; 32 × 100 = 3200; 95 × 1000 = 95000
640 : 10 = 64; 3200 : 100 = 32; 95000 : 1000 = 95
b,(5+x)+(7+x)+(9+x)+...+(101+x)+(103+x)=2850
<=>(x+x+x+...+x)+(5+7+...+103)=2850
<=>50*x+2700=2850
<=>50*x=150
<=>x=3
b,(5+x)+(7+x)+(9+x)+...+(101+x)+(103+x)=2850
<=>(x+x+x+...+x)+(5+7+...+103)=2850
<=>50*x+2700=2850
<=>50*x=150
<=>x=3
1. Tính
23 x 46 = 1058
34 x 10 = 340
54 x 46 = 2484
17 x 35 = 595
19 x 30 = 570
2 Tìm X :
a) X : 11 = 35 b) X : 11 = 87 c) X - 425 = 625
X = 35 x 11 X = 87 x 11 X = 625 + 425
X = 385 X = 957 X = 1050
Vậy X = 385 Vậy X = 957 Vậy X = 1050
d) X - 103 = 99 e) X + 527 = 1892 f) X x 5 = 1085
X = 99 + 103 X = 1892 - 527 X = 1085 : 5
X = 202 X = 1365 X = 217
Vậy X = 202 Vậy X = 1365 Vậy X = 217
a; \(\dfrac{1919}{2121}\) = \(\dfrac{1919:101}{2121:101}\) = \(\dfrac{19}{21}\)
b; 17 x 5 - \(\dfrac{17}{120}\) - 103
= 85 - \(\dfrac{17}{120}\) - 103
= \(\dfrac{10200}{120}\) - \(\dfrac{17}{120}\) - \(\dfrac{12360}{120}\)
= \(\dfrac{10183}{120}\) - \(\dfrac{12360}{120}\)
= \(\dfrac{-2177}{120}\)
c; 2929 - \(\dfrac{101}{2\times1919}\) + 404
= 2929 - \(\dfrac{1}{38}\) + 404
= \(\dfrac{111302}{38}\) - \(\dfrac{1}{38}\) + \(\dfrac{15352}{38}\)
= \(\dfrac{111301}{38}\) + \(\dfrac{15352}{38}\)
= \(\dfrac{126653}{38}\)
a+b+c = 10+102+103 = 215
vậy a+b+c = 215
Thay a=10; b102; c=103 ta có :
10+102+103=215
Vậy a+b+c=215