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a) Ta có : \(\frac{a}{b}+\frac{5}{6}=\frac{7}{8}\)=> \(\frac{a}{b}=\frac{7}{8}-\frac{5}{6}\)
=> \(\frac{a}{b}=\frac{21}{24}-\frac{20}{24}=\frac{1}{24}\)
Vậy \(\frac{a}{b}=\frac{1}{24}\)
b) \(\frac{a}{b}\times\frac{2}{3}=\frac{3}{4}\)
=> \(\frac{a}{b}=\frac{3}{4}:\frac{2}{3}=\frac{3}{4}\times\frac{3}{2}=\frac{9}{8}\)
Vậy \(\frac{a}{b}=\frac{9}{8}\)
c) \(\frac{5}{8}-\frac{a}{b}=\frac{5}{12}\)
=> \(\frac{a}{b}=\frac{5}{8}-\frac{5}{12}=\frac{15}{24}-\frac{10}{24}=\frac{5}{24}\)
Vậy \(\frac{a}{b}=\frac{5}{24}\)
d) \(\frac{5}{8}+\frac{a}{b}=\frac{13}{8}\)
=> \(\frac{a}{b}=\frac{13}{8}-\frac{5}{8}=\frac{8}{8}=1\)
Vậy : ....
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a. 25,97 + 6,54 + 103,46
= 25,97 + (6,54+103,46)
= 25,97+110
= 135,97
b. 50% + 7/12-1/2
= 1/2+7/12-1/2
= (1/2-1/2)+7/12
= 0+7/12
= 7/12
c. 2015.65 + 2015.45 - 2015.10
= 2015. (65+45-10)
= 2015.100
= 201500
2.a.2/3.x+3/4=3
=> 2/3.x=3-3/4
=> 2/3.x=9/4
=> x=9/4:2/3
=> x=9/4.3/2
=> x=27/8
b. 100-7(x-5)=58
=> 7(x-5)=100-58
=> 7(x-5)=42
=> x-5=42:7
=> x-5=6
=> x=6+5
=> x=11
c. x+1/3=7/26 x 13/6
=> x+1/3 = 7/12
=> x=7/12-1/3
=> x=7/12-4/12
=> x=3/12
=> x=1/4
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\(6A\)
Ta có: \(\frac{1}{2};\frac{1}{3};\frac{1}{4}\Leftrightarrow\frac{12}{24};\frac{8}{24};\frac{3}{24}\Rightarrow12>8>3\)
\(7B\)
Ta có: \(\hept{\begin{cases}\frac{7}{4}-\frac{2}{7}+\frac{11}{28}=\frac{17}{28}\\\frac{3}{8}+\frac{5}{8}-\frac{1}{4}=\frac{3}{2}=\frac{42}{28}\end{cases}\Leftrightarrow17< 42}\)
\(8D\)
Ta có: \(\hept{\begin{cases}\frac{2}{3}=\frac{2.4}{3.4}=\frac{8}{12}\\\frac{3}{4}=\frac{3.3}{4.3}=\frac{9}{12}\end{cases}\Leftrightarrow8< 12\Rightarrow\frac{2}{3}< \frac{3}{4}}\)
\(10.\)
Số quả cam: \(24:\frac{2}{3}=36\) (quả)
\(\frac{3}{4}\) số quả cam là: \(36\times\frac{3}{4}=27\) (quả)
\(12D\)
Ta có: \(\frac{1}{8}m^2=0,125m^2=125000mm^2\)
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a, \(1\frac{2}{7}+6\frac{5}{6}=\frac{9}{7}+\frac{41}{6}=\frac{54}{42}+\frac{287}{42}=\frac{341}{42}\)
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a.1/4 +3/8 +5/16=15/16
b, 3/5 - 1/3 -1/6=1/10
c, 4/7 *5/8 *7/12=5/24
d. 25/28 : 15/24 * 6/7=60/49
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1a)\(\frac{5}{3}\)=\(\frac{5x4}{3x4}\)=\(\frac{20}{12}\); \(\frac{1}{4}\)=\(\frac{1x3}{4x3}\)=\(\frac{3}{12}\)
b)\(\frac{3}{8}\)=\(\frac{3x3}{8x3}\)=\(\frac{9}{24}\); \(\frac{7}{24}\)
c)\(\frac{1}{2}\)=\(\frac{1x15}{2x15}\)=\(\frac{15}{30}\); \(\frac{2}{3}\)=\(\frac{2x10}{3x10}\)=\(\frac{20}{30}\); \(\frac{3}{5}\)=\(\frac{3x6}{5x6}\)=\(\frac{18}{30}\)
2a)\(\frac{11}{8}\)>\(\frac{11}{9}\)
b)\(\frac{4}{9}\)<\(\frac{3}{5}\)
c)\(\frac{6}{5}\)>\(\frac{5}{6}\)
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