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\(\frac{a}{b}\cdot4+\frac{1}{16}=\frac{17}{6}\)
\(\frac{a}{b}\cdot4=\frac{17}{6}-\frac{1}{16}\)
\(\frac{a}{b}\cdot4=\frac{133}{48}\)
\(\frac{a}{b}=\frac{133}{48}:4\)
\(\frac{a}{b}=\frac{133}{12}\)
Cách giải của mình nhé
\(\frac{a}{b}\times4+\frac{1}{6}=\frac{17}{6}\)
\(\frac{a}{b}\times4=\frac{17}{6}-\frac{1}{6}\)
\(\frac{a}{b}\times4=\frac{16}{6}\)
\(\frac{a}{b}=\frac{16}{6}:4\)
\(\frac{a}{b}=\frac{2}{3}\)
c; 17\(\dfrac{2}{31}\) - (\(\dfrac{15}{17}\) + 6\(\dfrac{2}{31}\))
= 17 + \(\dfrac{2}{31}\) - \(\dfrac{15}{17}\) - 6 - \(\dfrac{2}{31}\)
= (17 - 6) - \(\dfrac{15}{17}\) + (\(\dfrac{2}{31}\) - \(\dfrac{2}{31}\))
= 11 - \(\dfrac{15}{17}\)+ 0
= \(\dfrac{172}{17}\)
b; 130\(\dfrac{25}{28}\) + 120\(\dfrac{17}{35}\)
= 130 + \(\dfrac{25}{28}\) + 120 + \(\dfrac{17}{35}\)
= (130 + 120) + (\(\dfrac{25}{28}\) + \(\dfrac{17}{35}\))
= 250 + (\(\dfrac{125}{140}\) + \(\dfrac{68}{140}\))
= 250 + \(\dfrac{193}{140}\)
= 250\(\dfrac{193}{140}\)
6 2/7 + 7 3/5 + 8 6/9 + 9 1/4 + 2/5 + 5/7 + 1/3 x 3/4 + 1967
= 44/7 + 38/5 + 78/9 + 37/4 + 2/5 + 5/7 + 1/3 + 1967
= ( 44/7 + 5/7 ) + ( 38/5 + 2/5 ) + ( 26/3 + 1/3 ) + ( 37/4 + 3/4 ) +1967
= 7 + 8 + 9 + 10 + 1967
= 15 + 9 + 10 + 1967
= 24 + 10 + 1967
= 34 + 1967
= 2001
a/b*4+1/6=17/6
a/b*4 =17/6-1/6
a/b*4 =16/6
a/b =16/6 : 4
a/b =16/24
a/b =2/3
\(\frac{a}{b}\)x 4 + \(\frac{1}{6}\)= \(\frac{17}{6}\)
\(\frac{a}{b}\)x 4 = \(\frac{17}{6}\)- \(\frac{1}{6}\)= \(\frac{16}{6}\)
\(\frac{a}{b}\)= \(\frac{16}{6}\): 4
\(\frac{a}{b}\)= \(\frac{2}{3}\)