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a/ \(\left|5x+\frac{3}{4}\right|-\frac{5}{4}=2\)
\(\left|5x+\frac{3}{4}\right|=\frac{13}{4}\)
- / \(5x+\frac{3}{4}=\frac{13}{4}\)
\(5x=\frac{5}{2}\)
\(x=\frac{1}{2}\) - / \(5x+\frac{3}{4}=-\frac{13}{4}\)
\(5x=-4\)
\(x=-\frac{4}{5}\)
\(\Rightarrow x=\left\{\frac{1}{2};-\frac{4}{5}\right\}\)
b/\(\frac{3}{2}-\left|\frac{1}{2}x+1\right|=\frac{1}{4}\)
\(\left|\frac{1}{2}x+1\right|=\frac{5}{4}\)
1/\(\frac{1}{2}x+1=\frac{5}{4}\)
\(\frac{1}{2}x=\frac{1}{4}\)
\(x=\frac{1}{2}\)
2/\(\frac{1}{2}x+1=-\frac{5}{4}\)
\(\frac{1}{2}x=-\frac{9}{4}\)
\(x=-\frac{9}{2}\)
\(\Rightarrow x=\left\{\frac{1}{2};-\frac{9}{2}\right\}\)
a) \(x-\frac{4}{5}=\frac{5}{7}\)
\(x=\frac{5}{7}+\frac{4}{5}=\frac{53}{35}\)
b) \(5x=-\frac{1}{5}\)
\(x=-\frac{1}{5}:5=-\frac{1}{25}\)
c) \(\frac{5}{3}-x=7+\frac{4}{5}\)
\(\frac{5}{3}-x=\frac{39}{5}\)
\(x=\frac{5}{3}-\frac{39}{5}=-\frac{92}{15}\)
d) \(-\frac{5}{11}+2x=\frac{7}{22}\)
\(2x=\frac{7}{22}+\frac{5}{11}\)
\(2x=\frac{17}{22}\)
\(x=\frac{17}{22}:2\)
\(x=\frac{17}{44}\)
\(x=-\frac{1}{5}:5\)
NÈ BẠN!!!
a) \(x-\frac{4}{5}=\frac{5}{7}\)
\(x=\frac{5}{7}+\frac{4}{5}=\frac{25}{35}+\frac{28}{35}=\frac{53}{35}\)
b) \(5x=-\frac{1}{5}+\frac{11}{5}\)
\(5x=2\)
\(x=\frac{2}{5}\)
c)\(\frac{5}{3}-x=7\)
\(x=\frac{5}{3}-7=\frac{5}{3}-\frac{21}{3}=-\frac{16}{3}\)
d) \(-\frac{5}{11}+2x=\frac{7}{22}\)
\(2x=\frac{7}{22}-\frac{-5}{11}=\frac{7}{22}-\frac{-10}{22}=\frac{17}{22}\)
\(x=\frac{17}{22}:2=\frac{17}{22}\cdot\frac{1}{2}=\frac{17}{44}\)
K CHO MÌNH NHA!!!
PT <=> \(\frac{4x}{3}=\frac{14x}{3}+5\)
<=> \(\frac{10x}{3}=-5\)
<=> x= \(-5:\frac{10}{3}=-\frac{15}{10}=-\frac{3}{2}\)
vậy x= - 3/2
e,
\(2^x-15=17\\ 2^x=17+15\\ 2^x=32\\ 2^x=2^5\\ x=5\)
Vậy \(x=5\)
d,
\(\left(x-1\right)^5-\left(x-1\right)^2=0\\ \left(x-1\right)^2\cdot\left[\left(x-1\right)^3-1\right]=0\\ \Rightarrow\left[{}\begin{matrix}\left(x-1\right)^2=0\\\left(x-1\right)^3-1=0\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}x-1=0\\\left(x-1\right)^3=1\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}x=1\\\left(x-1\right)^3=1^3\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}x=1\\x-1=1\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}x=1\\x=2\end{matrix}\right.\)
Vậy \(x=1\) hoặc \(x=2\)
mấy câu còn lại coi lại đề
\(\left(6+\left(\frac{1}{2}\right)^3-\left|-\frac{1}{2}\right|\right):\frac{3}{12}\)
\(=\left(6+\frac{1}{8}+\frac{1}{2}\right):\frac{1}{4}\)
=\(\frac{53}{8}:\frac{1}{4}\)
\(=\frac{53}{2}\)
a)30/60,-40/60,45/60,48/60
45/60>30/60>-40/60>-48/60
=3/4>1/2>-2/3>-4/5
Ta có : \(A=4+4^2+4^3+........+4^{2017}\)
\(\Rightarrow4A=4^2+4^3+4^4+......+4^{2018}\)
\(\Rightarrow4A-A=4^{2018}-4\)
\(\Rightarrow3A=4^{2018}-4\)
\(\Rightarrow A=\frac{4^{2018}-4}{3}\)
Ta có:
\(4A=4^2+4^3+....+4^{2018}\)
\(\Rightarrow4A-A=3A=\left(4^2+4^3+...+4^{2018}\right)-\left(4+4^2+...+4^{2017}\right)\)
\(\Rightarrow3A=4^2+4^3+...+4^{2018}-4-4^2-...-4^{2017}\)
\(\Rightarrow3A=4^{2018}-4\)
\(\Rightarrow A=\frac{4^{2018}-4}{3}\)