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1, \(\frac{1}{2}-\left(6\frac{5}{9}+x-\frac{117}{8}\right):\left(12\frac{1}{9}\right)=0\)
\(\left(\frac{6.9+5}{9}+x-\frac{117}{8}\right):\frac{12.9+1}{9}=\frac{1}{2}\)
( . là nhân nha)
\(\left(\frac{59}{9}-\frac{117}{8}+x\right):\frac{109}{9}=\frac{1}{2}\)
\(\frac{59}{9}-\frac{117}{8}+x=\frac{1}{2}\cdot\frac{109}{9}\)
\(\frac{59}{9}-\frac{117}{8}+x=\frac{109}{18}\)
\(x=\frac{109}{18}-\frac{59}{9}+\frac{117}{8}\)
\(x=\frac{113}{8}\)
( \(\left(y+\frac{1}{3}\right)+\left(y+\frac{2}{9}\right)+\left(y+\frac{1}{27}\right)+\left(y+\frac{1}{81}\right)=\frac{56}{81}\)
\(y+\frac{1}{3}+y+\frac{2}{9}+y+\frac{1}{27}+y+\frac{1}{81}=\frac{56}{81}\)
\(4y+\frac{1}{3}+\frac{2}{9}+\frac{1}{27}+\frac{1}{81}=\frac{56}{81}\)
\(4y+\frac{49}{81}=\frac{56}{81}\)
\(4y=\frac{7}{81}\)
y = 7/81:4
y = 7/324
Giúp tôi giải toán - Hỏi đáp, thảo luận về toán học - Học toán với OnlineMath
Ta có:
1+y/9=1+2y/7
=>(1+y).7=(1+2y).9
=>7y+7=18y+9
=>18y-7y=7-9
=>11y=-2=>y=-2/11
Thay y=-2/11 vào
=>x=5
vậy x=5
#)Giải :
\(\left(y+1\right)+\left(y+3\right)+\left(y+5\right)+...+\left(y+49\right)=700\)
\(\left(y+y+y+...+y\right)+\left(1+3+5+...+49\right)=700\)(có 25 số hạng trong các ngoặc)
\(25y+\frac{\left(49+1\right)25}{2}=700\)
\(25y+625=700\)
\(\Rightarrow25y=75\)
\(\Rightarrow y=3\)
(y+1)+(y+3)+(y+5)+...+(y+49)=700
=>(y+y+y+...+y)+(1+3+5+...+49)=700
-> y=(49-1):2+1=25 số hạng
=>25y+[(49+1)×25÷2]=700
=>25y+625=700
=>25y=75
=>y=3
4 x y + (1/3 + 1/9 + 1/27 + 1/81) = 56/81
4 x y + (27/81 + 9/81 + 3/81 + 1/81) = 56/81
4 x y + 40/81 = 56/81
4 x y = 56/81 - 40/81 = 16/81
y = 4/81
\(\left(y+\frac{1}{3}\right) +\left(y+\frac{1}{9}\right)+ \left(y+\frac{1}{27}\right)+\left(y+\frac{1}{81}\right)=\frac{56}{81}\)
\(y\cdot4+\left(\frac{1}{3}+\frac{1}{9}+\frac{1}{27}+\frac{1}{81}\right)=\frac{56}{81}\)
\(y\cdot4+\frac{40}{81}=\frac{56}{81}\)
\(y\cdot4=\frac{56}{81}-\frac{40}{81}\)
\(y\cdot4=\frac{16}{81}\)
\(y=\frac{16}{81}:4\)
\(y=\frac{4}{81}\)
a) (x+1)/3 + (x+1)/9 + (x+1)/27 + (x+1)/81 = 56/81
<=> (27x+27)/81 + (9x+9)/81 + (3x+3)/81 + (x+1)/81 = 56/81 (quy đồng)
<=> 27x + 9x + 3x + x + 27 + 9 + 3 + 1 = 56 (khử mẫu)
<=> 40x = 56- 40 = 16
<=> x = 16/40 = 2/5
~ hok tốt ~
y + 1/3 + y+ 1/9 +y +1/27 + y+ 1/81 =56/81
4y +(1/3 +1/9+1/27+1/81) = 56/81
4y +(27 +9+3+1/81)=56/81
4y +40/81=56/81
4y =56/81 -40/81
4y=16/81
y=16/81 .1/4
y=4/81
Tìm y :
( y + 1/3 ) + ( y + 1/9 ) + ( y + 1/27 ) + ( y + 1/81 ) = 56/81
y + 1/3 + y + 1/9 + y + 1/27 + y + 1/81 = 56/81
y x 4 + ( 1/3 + 1/9 + 1/27 +1/81 ) = 56/81
y x 4 + ( 27/81 + 9/81 + 3/81 + 1/81 ) = 56/81
y x 4 + 40/81 = 56/81
y x 4 = 56/81 - 40/81
y x 4 = 16/81
y = 16/81 : 4
y = 4/81
a) 34,8 : y = 7,2 + 2,8
34,8 : y = 10
y = 34,8 : 10
y = 3,48
b) 21,22 + 9,072 + 24,72 : 12 = y : 2
32,352 = y : 2
y = 32,352 x 2
y = 64,704
Tk mk nha!
a) 34,8 : y = 7,2+2,8 b) 21,22 + 9,072 + 24,72 : 12 = y : 2
34,8 : y = 10 30,292 +2,06 = y : 2
y = 34,8 : 10 32,352 = y : 2
Vậy y = 3,48 32,352 x 2 = y
64,704 = y
Vậy y = 64,704