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\(\frac{4}{5}\)+ \(\frac{1}{5}\): \(\frac{-2}{15}\)= \(\frac{4}{5}\)+ \(\frac{1}{5}\)* \(\frac{-15}{2}\)=\(\frac{4}{5}\) + \(\frac{-3}{2}\)= \(\frac{-7}{10}\)
b = \(\frac{-7}{12}\). (\(\frac{3}{11}\)+ \(\frac{-14}{11}\)) + \(\frac{5}{6}\)= \(\frac{-7}{12}\). (-1) + \(\frac{5}{6}\)= \(\frac{7}{12}\)+ \(\frac{10}{12}\)= \(\frac{17}{12}\)
cái chữ này cj nhìn khó hiểu quá nên em thông cảm nếu muốn bt đáp án thì viết rõ ra đc chứ^^
a.
\(\frac{5}{24}+x=\frac{7}{12}\)
\(x=\frac{7}{12}-\frac{5}{24}\)
\(x=\frac{3}{8}\)
b.
\(x-\frac{3}{4}=\frac{1}{2}\)
\(x=\frac{1}{2}+\frac{3}{4}\)
\(x=\frac{5}{4}\)
Trả lời:
a, \(\frac{5}{24}+x=\frac{7}{12}\)
\(\Rightarrow x=\frac{7}{12}-\frac{5}{24}\)
\(\Rightarrow x=\frac{3}{8}\)
b, \(x-\frac{3}{4}=\frac{1}{2}\)
\(\Rightarrow x=\frac{1}{2}+\frac{3}{4}\)
\(\Rightarrow x=\frac{5}{4}\)
c, \(\left(\frac{2}{7}x+\frac{3}{7}\right)\div2\frac{1}{5}-\frac{3}{7}=1\)
\(\Rightarrow\left(\frac{2}{7}x+\frac{3}{7}\right)\div\frac{11}{5}-\frac{3}{7}=1\)
\(\Rightarrow\left(\frac{2}{7}x+\frac{3}{7}\right)\div\frac{11}{5}=1+\frac{3}{7}\)
\(\Rightarrow\left(\frac{2}{7}x+\frac{3}{7}\right).\frac{5}{11}=\frac{10}{7}\)
\(\Rightarrow\frac{2}{7}x+\frac{3}{7}=\frac{10}{7}\div\frac{5}{11}\)
\(\Rightarrow\frac{2}{7}x+\frac{3}{7}=\frac{22}{7}\)
\(\Rightarrow\frac{2}{7}x=\frac{22}{7}-\frac{3}{7}\)
\(\Rightarrow\frac{2}{7}x=\frac{19}{7}\)
\(\Rightarrow x=\frac{19}{7}\div\frac{2}{7}\)
\(\Rightarrow x=\frac{19}{2}\)
a) x/3 - 1/4 = - 5/6
x/3 = -5/6 + 1/4
x/3 = -7/12
x = -7/12 :3
x = -7/36
a: \(\dfrac{x}{3}-\dfrac{1}{12}=\dfrac{1}{5}\)
=>\(\dfrac{x}{3}=\dfrac{1}{12}+\dfrac{1}{5}=\dfrac{17}{60}\)
=>\(x=\dfrac{17}{60}\cdot3=\dfrac{17}{20}\)
b: \(\dfrac{x}{15}=\dfrac{3}{5}+\dfrac{-2}{3}\)
=>\(\dfrac{x}{15}=\dfrac{9}{15}-\dfrac{10}{15}=\dfrac{-1}{15}\)
=>x=-1