Question

[Dương Diệp]

( a+ b+ c)( ab+ bc+ ac) - abc

Answer 1

[Y-S Love SSBĐ]

   ( a + b + c ) ( ab + bc + ac ) - abc

= a²b + abc +a²c + ab² + b²c + abc + abc + bc² + ac² - abc

= 2abc + a²b + a²c + ab² + b²c bc² + ac²

Hk tốt

Answer 2

[temotojirimo]

\(\left(a+b+c\right)\left(ab+bc+ac\right)-abc\)c

\(=a^2b+abc+a^2c+ab^2+b^2c+abc+abc+bc^2+ac^2-abc\).

\(2abc+a^2b+a^2c+ab^2+b^2c+bc^2+ac^2\)

HK tốt