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a) 2.(-25).(-4).50 = 10000
b) 16.50.(-25).(-250) = 5000000
c)
− 167 . − 83 + 167.17 − 33 = 167.83 + 167.17 − 33 = 167. 83 + 17 − 33 = 167.100 − 33 = 1667
d)
135 − 35 .47 − 53. − 48 − 52 = 100.47 − 53. − 100 = 100.47 + 53.100 = 100. 47 + 53 = 100.100 = 10000
a) 2. − 25 . − 4 .50 = 10000
b) 16.50. − 25 . − 250 = 5000000
c)
− 167 . − 83 + 167.17 − 33 = 167.83 + 167.17 − 33 = 167. 83 + 17 − 33 = 167.100 − 33 = 1667
d)
135 − 35 .47 − 53. − 48 − 52 = 100.47 − 53. − 100 = 100.47 + 53.100 = 100. 47 + 53 = 100.100 = 10000
1. -25.72 + 25.21 - 49.25
= 25.(-72) + 25.21 - 49.25
= 25.(-72 + 21 - 49)
= 25. (-100)
= -2500
2. 35(14 - 23) - 23(14 - 35)
= 35. (-9) - 23. (-9)
= -9(35 - 23)
= -9. 12
= -108
3. 8154 -(674 + 8154) + (-98 + 674)
= 8154 - 674 - 8154 + (-98) + 674
= 8154 - 8154 - 674 + 674 + (-98)
= -98
4. 25.21 + 25.72 + 49.25
= 25(21 + 72 + 49)
= 25. 142
= 3550
5. 27(13 - 16) - 16(13 - 27)
= (27.13 - 27.16) - (16.13 - 16.27)
= 27.13 - 27.16 - 16.13 - 16.27
= 27.13 - 16.13 - 27.16 - 16.27
= 27.13 - 16.13
= 13(27 - 16)
= 13.11
= 143
6. -1911 -(1234 - 1911)
= -1911 - 1234 + 1911
= -1911 + 1911 - 1234
= -1234
Câu 1:
a) Ta có: 2n+1 là số lẻ∀n
⇒\(\left(-1\right)^{2n+1}=-1\)
Ta có: \(\left(-25\right)\cdot21\cdot\left(-2\right)^2\cdot\left(-\left|-3\right|\right)\cdot\left(-1\right)^{2n+1}\)
\(=-25\cdot21\cdot4\cdot\left(-3\right)\cdot\left(-1\right)\)
\(=75\cdot84\cdot\left(-1\right)\)
\(=-6300\)
b) Ta có: \(\left(-5\right)^3\cdot67\cdot\left(-\left|-2^3\right|\right)\cdot\left(-1\right)^{2n}\)
\(=-125\cdot67\cdot\left(-8\right)\)
\(=1000\cdot67=67000\)
c) Ta có: \(35\cdot18-5\cdot7\cdot28\)
\(=35\cdot18-35\cdot28\)
\(=35\cdot\left(18-28\right)=35\cdot\left(-10\right)=-350\)
d) Ta có: \(24\cdot\left(16-5\right)-16\cdot\left(24-5\right)\)
\(=24\cdot16-24\cdot5-24\cdot16+16\cdot5\)
\(=-24\cdot5+16\cdot5\)
\(=5\cdot\left(-24+16\right)=5\cdot\left(-8\right)=-40\)
e) Ta có: \(29\cdot\left(19-13\right)-19\cdot\left(19-13\right)\)
\(=6\cdot\left(29-19\right)=6\cdot10=60\)
g)Sửa đề: \(31\cdot\left(-18\right)+31\cdot\left(-81\right)-31\)
Ta có: \(31\cdot\left(-18\right)+31\cdot\left(-81\right)-31\)
\(=31\cdot\left(-18-81-1\right)\)
\(=31\cdot\left(-100\right)=-3100\)
h) Ta có: \(\left(-12\right)\cdot47+\left(-12\right)\cdot52+\left(-12\right)\)
\(=-12\cdot\left(47+52+1\right)\)
\(=-12\cdot100=-1200\)
k) Ta có: \(13\cdot\left(23+22\right)-3\cdot\left(17+28\right)\)
\(=13\cdot45-3\cdot45\)
\(=45\cdot\left(13-3\right)=45\cdot10=450\)
m) Ta có: \(-48+48\cdot\left(-78\right)+48\cdot\left(-21\right)\)
\(=48\cdot\left(-1-78-21\right)\)
\(=48\cdot\left(-100\right)=-4800\)
n) Ta có: \(135\cdot\left(171-123\right)-171\cdot\left(135-123\right)\)
\(=135\cdot171-135\cdot123-171\cdot135+171\cdot123\)
\(=123\cdot\left(-135+171\right)=123\cdot36=4428\)
Sai thì sửa,chửa thì đẻ
Sửa đề đi, thiếu dấu ko làm đc
a) (42 – 98) – (42 – 12) - 12
=42-98-42+12-12
=(42-42)+(12-12)-98
=0-98
=-98
e) (– 5) . 4 . (– 2) . 3 . (-25)
=[-5.(-2)].(-25.4).3
=10.-100.3
=-1000.3
=-3000