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e, (-25).(-13).8.(-4).125
= (-25).(-4).8.125.(-13)
= 100.1000.(-13)=-1300000
f, 38.(-43)+43.(-79)-(-43).17
= 38.(-43)+(-43).79-(-43).17
= (-43).(38+79-17)
= (-43).100=-4300
a) ( -7) . 11 + 7 . ( - 89 )
= 7 . (-11) + 7 . (-89)
= 7 . [(-11)+(-89)]
= 7 . (-100)
= -700
\(\frac{1}{2}+\frac{5}{6}+\frac{11}{12}+\frac{19}{20}+...+\frac{89}{90}\)
\(=1-\frac{1}{2}+1-\frac{1}{6}+1-\frac{1}{12}+1-\frac{1}{20}+...+1-\frac{1}{90}\)
\(=9-\left(\frac{1}{2}+\frac{1}{6}+\frac{1}{12}+\frac{1}{20}+...+\frac{1}{90}\right)\)
\(=9-\left(\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+\frac{1}{4.5}+...+\frac{1}{9.10}\right)\)
\(=9-\left(1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+....+\frac{1}{9}-\frac{1}{10}\right)\)
\(=9-\left(1-\frac{1}{10}\right)\)
\(=9-\frac{9}{10}=\frac{81}{10}\)
a: =25x100-150=2500-150=2350
c: \(=520:\left\{515\cdot25\right\}\)
=104/2575
a: =17-43=-26
b: =-34+34+11-11+105=105
c: \(=64+125\cdot100=12564\)
d: \(=60+\left[7^3-343\right]\cdot2017^{2018}=60\)
a) (-12).(7-72)-25.(55-43)
=(-12).(-65)-25.12
=12.(65-25)
=12.40
=480
b) (39-19):(-2)+(34-22).5
=20:(-2)+12.5
=-10+60
^HT^
a) 315 + 2x = x+115
<=> 2x-x = 115-315
<=> x = -200
Vậy x= -200
b) 25-(30-x)=25-(-12+125)
<=> 25-30+x = -88
<=> -5 + x =-88
<=> x = -83
Vậy x=-83
TL:
\(\text{a) (-12).(7-72)-25.(55-43) = (-12).(-65)-25.12 = 12.(65-25) = 12.40 = 480 b) (39-19):(-2)+(34-22).5 = 20:(-2)+12.5 = -10+60 = 50}\)
HT
a, (-4) . 125 . (-25) . (-11) . (-8)
= [(-4) . (-25)] . {[125 . (-8)] . (-11)}
= 100 . 11000 = 1100000
b, (-42) . 25 . (-25) . (-5) . (-4)
= [(-42) . (-5)] . [25 . (-4)] . 25
= 210 . (-100) . 25
= -5025000